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Treatment of propionaldehyde with dil. $\mathrm{NaOH}$ solution gives (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCH}_{2} \mathrm{CH}_{2} \mathrm{CHO}$ (b) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHOHCH}_{2} \mathrm{CH}_{2} \mathrm{CHO}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHOHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CHO}$ (d) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}$

Hello and welcome to this video solution of enumerate. So it is given that is sulfur reacts with concentrated H. & 0. 3 nitric acid that gives you compound P. And again it's reacts with in a marriage caustic soda that gives you Q. Red. So let me write down the reaction of his sulfur With considering nitric acid. Right? So here consecration it's six H. n. 0. 3 that will give you H. two, s. 0. four plus to H. Two plus We have got six and or two right now. If you check the options, you see that the compound be right. The speed is nothing but aged and so forth. Right? And you can actually directly check in option A. For that. I hope this is clear to you and have a very good rest of the day. Thank you.

Question number 150 is an E d t a tie trey shin question or a complex ion formation. Question. Where e. D t. A. Is the ligand. The reaction that we're considering is Cobalt reacting with E d. T. A. Producing the complex ion of cobalt with e d. T. A. It has a K F value that will be equal to 10 to its PKF value of 16.31 And it'll it's ratio will simply be the product concentration over the two reactant concentrations. This will become important in a couple of calculations in this problem. For part, A wants us to determine the concentrations of copper two plus and E. D. T. A. After 25 mil. Leaders have been added because the volumes are essentially the same and the concentrations are pretty close to the same than we could assume that the equivalents point volume is going to be about 50 mL. Well, essentially because the concentrations air about the same, the volume should be about the same. So if we've only added, 25 mL were only halfway there, which means we haven't added enough e d t a. To consume all of the cobalt, so the cobalt concentration is going to be equal to the moles of cobalt. We start with its volume times. It's molar ity minus the moles of e. D. T. A. Added, because it's a one toe one reaction 25 mL at 250.5. Moeller This numerator is now the most of cobalt that's left over and will divide by the new total volume 50 mL plus 25 mL 4.75 mL. Now the concentration of the complex ion that is formed is simply going to be equal to the moles of E d. T. A. That we added 25 mil leaders at 250.5 Moeller divided by the new volume. Assuming this reaction goes to completion, it's got a large equilibrium constant. So it should. So every Molavi DT A, we added, should make a mole of product. That's the assumption that we are going off of when we calculate the molar ity of the product. Then the concentration of e. D. T. A. Could be calculated at equilibrium, using this expression here and the two concentrations that we just determined and we get 5.32 times 10 to the negative seven for the last one. It's very similar. We're just going to now calculate the concentration of the data that's formed, which is going to come from all of the cobalt we started with because we are post equivalents. So the moles of cobalt we start with is now the moles of product formed, and we divide by the new volume 50 million liters plus 75 mL. The amount of E. D. T. A. That's left in solution is going to be the amount that we add, minus the amount that reacted. This is what we added. 75 mL of five, Mueller and UM, 50 mL at 500.48 Moeller of Cobalt was present, and because it's the one toe one reaction that is the moles of E. D. T. A. That reacted. So this is now the most of e. D. T. A. Left over. In the new volume. This would then be it's molar ity. Now to get the cobalt concentration will go back to the KF expression plug in these two concentrations and the K F value that was given to us and we'll get a cobalt concentration of 8.71 times 10 to the negative 17

First off all we need to calculate the initial concentration off magnesium too positive on B trio 10 iron in mixed solution. So calculating the concentration we have MG to positive initial concentration equals Siegel. Multiple night one divided by 1000 milligrams. One one divided by 24 point 305 The initial concentration for magnesium don't know to be 2.1. Multiply 10 days to one negative. Three more were leader or 2.1 10 days to prenegative. Three more lar. The 2nd 1 is B three or then negative for you. One divided by 3 67 point 862 multiplied with one divided by one more into one divided by one leader and a tree Petri or 10 on. For this one. We have beat we or then negative five. Substituting in the world news we have 0.11 moral leader, or 0.11 moon are at next. The reaction after mixing after mixing the substances are MG to positive plus P three or 10 negative five mg B three or 10 based upon the negative. So we have before reaction and after reaction, so before reaction, it will be 2.1 mighty Pretend there's two point negative three on DDE 0.11 00 on for beat three or 10 it will be can just one negative three. It gives us approximate value of 0.11 More large on the product side will be 2.1. Multiply 10 days to open negative three, assuming the reaction is going to completion. In reality, the concentration off magnesium to positive is not equal to zero, so the equilibrium expression will be MG to positive plus P three or 10 negative five needs to mg B three or 10 negative three where the value of K will be will do 4.0 multiplied with then 10 days to power it now. Further, we have value off. A constant is it will do concentration off product in this case MG B three or dead three. Negative, divided by the concentration off reacting magnesium to pour the tip on Petri Orton Negative five. Substituting the values into the equation. We have 4.0 multiply 10 days to power. Eight equals 2.1 10 days to put negative three mg do bore the do on 0.11 The concentration off magnesium topo the Divine turns out to be 4.8. Multiply 10 days to one negative 11 Moreland.

Okay?


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