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Swen.atm, B is 0.0 atm, and € is 0.0 atm: The equilibrium Parta BrtiadedAaar essures of A is 0.5answer....

Question

Swen.atm, B is 0.0 atm, and € is 0.0 atm: The equilibrium Parta BrtiadedAaar essures of A is 0.5answer.

Swen. atm, B is 0.0 atm, and € is 0.0 atm: The equilibrium Parta BrtiadedAaar essures of A is 0.5 answer.



Answers

For the equilibrium
$$\mathrm{A}(g)+2 \mathrm{B}(g) \rightleftharpoons \mathrm{C}(g)$$
the initial concentrations are $P_{A}=P_{B}=P_{C}=0.100 \mathrm{atm}$ . Once equilibrium has been established, it is found that $P_{\mathrm{C}}=0.040 \mathrm{atm} .$ What is $\Delta G^{\circ}$ for this reaction at $25^{\circ} \mathrm{C} ?$

In order to determine Delta Jeannot for the given reaction, we first need to determine the equilibrium constant, so we'll start with the equilibrium and set up a nice table. Initially, we're told that we have 0.1 atmosphere at each A B and C in that at equilibrium. The pressure pressure pressure of C is 0.0 for zero atmospheres, so this is minus 0.60 plus 0.0 60 and plus 0.1 to 0. This would give me 0.160 and 0.2 to 0. For equilibrium, Constant is equal to the partial pressure of C, divided by the partial pressure of a comes the pressure pressure B squared plug in our values here 0.40 0.160 and 0.2 to 0 squared. Let's solve for R equilibrium constant here. When we get an equilibrium constant, it's equal to 5.17 No Delta Jeannot. Secret of negative R T lawn. Ah, very glittering. Constant secret to negative. 8.314 Jules per mole Calvin Temperature 25 degrees Celsius, which is 298. Calvin and the lawn of 5.17 Calculating adult Jeannot. Here we get negative. 4000 and 70.3, Jules per mole or negative 4.7 que o jewels promote.

It's our reaction is Kind of a fictitious one. Write a. Goes to to be and they're both gases. We'll set up an ice box to keep track of what's happening. The initial change in equilibrium, We're starting with 75 and zero And we know that a. Is going to be 36 at equilibrium. So this must have been -39. So this must be plus two times .39. So that gives us .78 and then we want the total pressure. So we're just going to take this pressure plus this pressure. And that will give us a total pressure of 1.14 ATM. So that's your total pressure. And then we'll go ahead and find K. P. That's just going to be the partial pressure of B squared over the partial pressure of A. So that's going to be .78 squared Over .36. So we'll get our K. Is 1.7.

So continuing on with thermodynamics, we will fastly look at the equilibrium pressure for C So see equilibrium pressure people to not point not 60 Then we can calculate the equilibrium pressures of A and B. So we have a equilibrium. Pressure is equal to 9.160 atmosphere. Then we have be equilibrium pressure that is equal to not 0.20 atmosphere. So we substitute thes equilibrium pressure constants into our equation. Here, that is K is equal to see over a b squared. So what we get is not point not for zero divided by 9.160 multiplied by not 0.2 to 0 that is squared because Austria geometric coefficients so K is equal to 5.17 So we substitute in our bodies of all T and K into our equation. For Delta G is equal to negative rt Ln k to solve a delta. Do not so delta Jeannot, is it too negative? 8.314 Jules, Pamela for Calvin, I worked my in the units just to save space multiplied by 298 Calvin multiplied by l n 5.17 So we find that Delta Gino is equal to negative 4.1 killer jewels, part mole

In this problem. We've been asked if two different cases of the same system aren't equilibrium or not. And if they aren't in equilibrium, then in one direction the reaction would proceed a move so very quickly. Here, let me just, um, give you the basics. So this is our reaction. And from that I have written out the KP formula, which is a partial pressure of nitrogen oxygen divided by square, the partial pressure off Kendall because it doesn't to hear in the balanced equation. So you raise it to and it is given that the KP is 24 hungry. Now we've been given three different cases. In the first case, we've been given the partial pressures off three main participating factors of products and the reactions. So we plug those in and we get the value 15 27 178 as the KP Not since the actual equilibrium KP value is greater than the ballot that we've just translated. It means that the reaction has to increase the amount of its products and to do that, it has to shift towards the right, which is in the direction of the products. In the second case, Once you plug the values in, we get 39 64.5, which is greater than the value that has been predicted that a delivery. So this means that we need more reactions to to, um ah, lower that the, um, equilibrium potion that we're dealing with, Which means that the reaction has to move left, which is in the direction of the reactions in the took kiss. We have these values of you plug in and we get 23 ah, 180.4 being, which is against, like being smaller than 2400. So we need a little more off the products, which means that the reaction testable slightly to the right, which is in the direction off the projects.


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