5

Which, if any, of the curves in Figure $6-10$ look(s) like a normal curve? If a curve is not a normal curve, tell why....

Question

Which, if any, of the curves in Figure $6-10$ look(s) like a normal curve? If a curve is not a normal curve, tell why.

Which, if any, of the curves in Figure $6-10$ look(s) like a normal curve? If a curve is not a normal curve, tell why.



Answers


Which, if any, of the curves in Figure $6-10$ look(s) like a normal curve? If a curve is not a normal curve, tell why.

Colin wants us to find where the line that is noble to skirt at 11 intersex the curb at another point. So we want to find that other point. So let's see the differentiation. To take the derivative, we have to X plus two times using the product. Rule X, Steve I D. X plus one times Why? Which is why minus six wine D Y T Thanks Triple zero. We want to bring everything that doesn't have a d u i d X term to their size. They subtract two x will be subject to why and then we have to x He rides the X line six live you are the X equal minus two. Excellent is to lie We're going Factor out this t y de vex divide both sides by what we have here. So we have t Y t X People's two x plus two light over +65 miles to x And all I did was taken her negative that was here and ransom did Almeida. So let's plug in 11 you get for over four Think of this one for the next page. We know that the normal line is going to have a slope of negative one because it's going to be the negative reciprocal of the slope of the tangent line. Negative one. And we're going to find the why are set by using the points one and one, and we put in the new one. We have negative one. Plus the liners have wires. Articles, too. Trust you. No, I wouldn't do that. Would take X and with X equals two minus y and had to plug this back in coastline to clean up. Now something we can notice about this line. There's quiet over here that we can rewrite it as X plus y squared minus four y squared because X plus y squared gives us expert was two ex wife plus y squared. But we have a negative. We have minus three y squared, so we subtract minus four y squared and makes the cleaner. And of course, we don't have to do this. We could just plug it in normally, but I think this makes it a little bit easier to do. So I'm going to peace and other page. You know I'm finished. I'm gonna put it here. Excellence Y squared minus four Y squared equals zero. And so if I take this X equals two months one played in we get to minus y plus y squared minus four y squared equals zero. We get four The Y four minus four y squared equals zero. You get y squared equals one if we move it all the other side. So I'm going to say why equals plus or minus one, depending on when we pick. So I'm gonna try positive one first if we try positive. One off actually became father won because that's the line of Yuri chokes the support, the very chips was too negative. One. If Y is negative one, then exit three. So a 30.3 negative one. If we test it out, it works the normal line and then we plug it in here. It works, too, So this is the point here.

Okay, section 3.7. Looking at problem number 47. They tell us that that line that is normal to the curve X squared plus two x y minus three wives squared at the 30.11 intersects the curve. At what other point? Okay, so other than +11 what other point will this That's normal line intersects the curve. Okay, so defined the normal line. I'm gonna have to know the tension and then figure out the slope from that. Okay, So that means I'm gonna have to different Jake. That's so let's figure out what is the derivative of this with respect to X. So when I do this, I get it. Two x plus. Now I'm going to use the product rule. So two x times D y the ex plus two times why minus six. Why D Y d X is equal to zero. And this original curve Sorry if I go back made a mistake here in this original curve that was equal to zero. So when a different shape is a different to the left hand side difference in the right head side, I do get zero here. So let's gather up the D Y de exes. So it looks like, um, I can factor to out of this entire equation. So let's just go and write this as, um X plus x Do I d. X plus? Why minus three. Why D y d x All of that is equal to zero. This tells me that d y the X is going to be equal to negative of X plus y. So bring all of that over to the right side. Divided by X minus three Wife No so negative of X plus y over X minus three. Why another way of riding this? If you've got too many minus signs, here is I could just write this simply as D Y d X is equal to X. Plus, why divided by instead of X minus three. Why just make that three y minus X? So that's one less minus sign for me to worry about. So what happens? What is D Y. D? X evaluated at the 0.11 So when I do that, this is one plus one over three minus one that it's two over two, which is equal to one. So I know that this that is the slope of the tension from finding the derivative. So therefore, I know that the slope of the normal line so em equal negative one. That's the slope of the normal at the point 11 Okay, so what is the equation of this line? So, point slope, this is why minus one equals negative one X minus one. So that gives me why is equal to negative X plus one plus one. So why is equal to negative X plus two? Okay, so this is the equation of the normal line at the point 11 Now, I'm asked to go back to the original question. Was looking at the original occur that you have. We know that it goes through 11 We have the equation of a normal line that goes through that. What other point does that normal lines intersect this curve. Okay, so our original curve is X squared. Plus two x y minus three y squared equals zero, and I've got a normal line of wives equally negative X plus two. So I need to find out where there will be an intersection point. Okay. So I can rewrite this quilt an expression of X is equal to negative. Why plus two. So to figure out where these things intersect, I'm gonna take this value for X and just substituted into the equation that you see here. So I'm going to get negative. Why? Plus two squared plus two negative Y plus two times why minus three y squared equal zero. So this gives me why Squared minus four. Why plus four. And then I'm going to get minus to Why squared Plus, for why minus three y squared equals zero. So a little bit of a simplification here for y and minus for Why that helps out. How many white squares do I have here? It looks like I've got minus four. Why squared plus four equals zero equivalent expression in here is four times negative y squared plus one equals zero. So this tells me that why is equal to plus or minus one in order to make this a true statement. Now we already know what happens at the 0.11 Okay, so I know I've already established at the 0.11 I know that I crossed that point when y is equal to one. That's the intersection of the Roman line. So the other value that it just found is when y is equal to negative one. So so when? Why equal negative one? What was the equation of our normal line? Normal? I'm was wise, equal to negative X Plus two. We know that Y is equal to negative X plus, too. So substitute that value negative one equal negative X plus, too. And that gives me X is equal to three. So at the 0.31 that is when my normal line will also intersect that curve at an additional point.

Move curve is normal to a surface at sea at a point of intersection. If the courage velocity vector is a non zero scaler multiple of Grady a meth. At that point, someone on a show this curb our is normal to that given service when t is equal to one. So it says that this is normal when the curse lost. The vector is a scaler multiple of grading of us. So our goal here is to find a grating a ends our velocity vector and show that their school scaler multiples of each other. I'm gonna start with finding my velocity. Specter No, no, I'm giving my position once. I know that this one is just going to be the derivative of our. So when I take the driven of this, I get 1/2 seeds. The negative 1/2 I It's 1/2 teats. The negative 1/2 J minus 14 Okay, so I know that's easy, Goto one. So therefore, looking at this position vector my employees and tickles one. That means my X is equal to one my wise eagle one and plugging in one in for tea here my Z is going to equal to 1/4 time's for witches. Negative one, several minus a point. It's been able to 11 negative one. And so now, also plugging in one for my baby equation. I get 1/2 I plus 1/2 J minus 1/4. Okay, so I have my velocity equation here. I know my initial points and I confined my Grady in of effort that point. So first, just finally grading it above I'm taking the derivative partial derivative with respect to each variable here. So first I know that the X y z it's just gonna equal to subtracting three over X squared plus y squared minus Z minus three. Siegel zero So taken. Ingredient of effort. This taking the partial derivatives back to X. I get to X. Hi, taking inspector. Why I get to why j taking it with respect to Z, I just get a negative one. So I just have a negative k here and now when I plug in my initial 0.11 minus one, I get Thio plus two J minus k. It's so now I want to compare this to my velocity vector. So I see I have the coefficients to two minus one. Here have 1/2. 1/2 negative. 1/4. So I see if I were to divide migrating and by four I'll get exactly my velocity. So V is equal to 1/4 the great and the best. And we were told in this problem that a smooth curve is normal. To surface is the courage we lost. The vectors is not escape non zero scaler. Multiple agreeing that. But the point. So since this is a scaler of each other, the curb is normal to the surface.

So the question here is to answer why we think the average in marginal cost curs have the same shape. Well, the marginal cost curve. It's going to look huge shape because when you start production, you're going to have increasing returns to production. But at some point diminishing marginal productivity's gonna kick him and give you this kind of increase in marginal cost curve. The average total costs, however, has going to start decreasing. And that's going to be due to, uh, the average marginal, uh, rule. Okay, so as long as the average variable cost, it's above your marginal cost curve, you're going to have that the average is going to decrease. So a song that's this blue Linus apothecary line. The blue line should be decreasing. However, the moment the green line rises up off the blue line, it's going to make the blue line go up. So by this law, right, because marginal cost is going to increase at some point in average parable costs, it's gonna keep decreasing until it meets the marginal Coster. You necessarily get that. They're both going to have to be. You curse right? So that's the recent away. The market across curve and the average bear will cost curve half several similar


Similar Solved Questions

4 answers
Q11. The ligure below shows block sliding up ramp with friction. Rank Ihe quantity of work done by Ihe friction force Wi gravity Wg' and the normal force WN on the block as the block slides distance dup the ramp; Assumc 0-45" and Uk and remember that negative numbers are smaller than positive numbersdSelecl one- Wf <WN < Wg Ww < Wf < Wg Wf < Wg < Wv Wg < Wf < WN Wg < Wv <Wf *cross ouicross ouicross ouIcross outCross QuiThe correcl answer is:Wg < Wf <
Q11. The ligure below shows block sliding up ramp with friction. Rank Ihe quantity of work done by Ihe friction force Wi gravity Wg' and the normal force WN on the block as the block slides distance dup the ramp; Assumc 0-45" and Uk and remember that negative numbers are smaller than posit...
5 answers
0eTratJidu 44nd4H0 !AUdintyeelht diruldAnennhKnatttnut 72374uh rinduilntpuitolf4a Cunuazot; % ua7cka Jcton Ila 7,12 nuamitno Inn &tmneuetntnmnttT Lmli{lmnt 0ttoj8anetetJor Chcoin F" e"esl 47anet [etneJdon B teLuun1Enatnnlnt,Fkrin *u1n408,70 nhnlocetnd 0l RuKeattie nttHtGutt0 @lFebntit4mal hralu4/Itn IaoTannatD Watut47e dt @emnt n re qulaeOna [34 olororultnbnmfm _tDttUduto
0eTrat Jidu 44nd4H0 !AU dintyeelht diruld Anennh Knattt nut 72374 uh rinduilnt puitolf4a Cunuazot; % ua7cka Jcton Ila 7,12 nuamitno Inn &tmneuetntn mnttT Lmli {lmnt 0ttoj8 anetet Jor Chcoin F" e"esl 47anet [etne Jdon B te Luun1E natnnlnt, Fkrin *u 1n408,70 nhnlo cetnd 0l Ru Keattie ntt...
5 answers
For queations (6) (14) refer to tbe graph bclow 'and e choose the btst ansntr in thc matching columa on the right hand side of the page Note: matching answers can be used Oer once; mote than not at alLThe graph oi g(r)Fill-in both and B our #muTODantcboarc (AB}Jim_g(r) =9(I) -lim_ 9(r) =lirg 9(1) =10. i 9(r) =(ABJJin 9(2) =(AD}12. ligg(s) =(AE) Doc No: Extlim 9(2) =(BC) Not ezough infonnationlim 9(=) =(AC)
For queations (6) (14) refer to tbe graph bclow 'and e choose the btst ansntr in thc matching columa on the right hand side of the page Note: matching answers can be used Oer once; mote than not at alL The graph oi g(r) Fill-in both and B our #muTOD ant cboarc (AB} Jim_g(r) = 9(I) - lim_ 9(r...
5 answers
1 EzAx 1 Ju = (0, 5'
1 EzAx 1 Ju = (0, 5'...
5 answers
Find the directional derivative of the function f (2.%)at P(0.1) in the direction of v(3.
Find the directional derivative of the function f (2.%) at P(0.1) in the direction of v(3....
5 answers
N Initolpopulcon120 fish introduceo the Iake atter Yearsconuladon Oroi5Candiako228 fish InLet ( be = tme (In years} slnce the Initial population introd Juced, and let ! be tne number Wrke Tormula relating U3a Exact @xpressions tne Missing parts of the formula Do not Use approrimahionsdlng#0(b} Hom many Inroduced thare Yejry aitcr the initial popurationDo nat round any Intcrmcdlate computations, and round Inswnr the ncarest whole number:Dush
n Initolpopulcon 120 fish introduceo the Iake atter Years conuladon Oroi5 Candiako 228 fish In Let ( be = tme (In years} slnce the Initial population introd Juced, and let ! be tne number Wrke Tormula relating U3a Exact @xpressions tne Missing parts of the formula Do not Use approrimahions dlng #0 (...
5 answers
What volume of 40.0% NaNO solution contains 0.15 mole of NaNO3? Density 132 gmL_
What volume of 40.0% NaNO solution contains 0.15 mole of NaNO3? Density 132 gmL_...
5 answers
Kp is Nz(g) For the Su9000 0 M 01 the provthe reaction?
Kp is Nz(g) For the Su9000 0 M 01 the prov the reaction?...
5 answers
For the total revenue function $R(x, y)$ of Exercise 31, compute $R(100,60)$ and $R(60,100)$. Interpret your results.
For the total revenue function $R(x, y)$ of Exercise 31, compute $R(100,60)$ and $R(60,100)$. Interpret your results....
5 answers
An art dealer sells on average 2. paintings priced over S5,000 per day: On any given day; what is the probability that thc dealer sells more than paintings priced over S5,0007Round your answers t0 thrce decimal places.
An art dealer sells on average 2. paintings priced over S5,000 per day: On any given day; what is the probability that thc dealer sells more than paintings priced over S5,0007 Round your answers t0 thrce decimal places....
1 answers
A simple pendulum of length $l$ is suspended from collar $C$ that is forced to move horizontally according to the relation $x_{C}=\delta_{m} \sin \omega_{f} t .$ Determine the range of values of $\omega_{f}$ for which the amplitude of the motion of the bob is less than $\delta_{m}$ (Assume that $\delta_{m}$ is small compared with the length $l$ of the pendulum.)
A simple pendulum of length $l$ is suspended from collar $C$ that is forced to move horizontally according to the relation $x_{C}=\delta_{m} \sin \omega_{f} t .$ Determine the range of values of $\omega_{f}$ for which the amplitude of the motion of the bob is less than $\delta_{m}$ (Assume that $\de...
5 answers
Question 12 Not yet ansucnidWhat is the value of the force (N) roquired t0 balance the syster in the figure? M=17 kg and makes an angle (0 370)( below horizontal. Consider 10 rs?Marked oul 0f 2.00 Flag question850B. NoneC.425D. I700E. 1275Next pngePrevious page
Question 12 Not yet ansucnid What is the value of the force (N) roquired t0 balance the syster in the figure? M=17 kg and makes an angle (0 370)( below horizontal. Consider 10 rs? Marked oul 0f 2.00 Flag question 850 B. None C.425 D. I700 E. 1275 Next pnge Previous page...
5 answers
340 YC UeoraculFred u JIltnolo 0 J0_0-abvLZB tV=Da chrtWhalesIrllal tokal mochanlcal enaray 0 the projectila (Give Vcir Jn~tnee Aenicart Iauros |Taponau Oiltetntolcuftelimnsroro than [0i Douba choctcalculatonsuppodeproletulotr *vellig %0,7 IVaal Mariruin Iaabl u $Hom Hisilt naik hae OcenWls unetu ultnmul"clu Muedlnd Up/rudteseneenmctnirigHceen
340 YC Ueoracul Fred u JIltnolo 0 J0_0-abv LZB tV= Da chrt Whales Irllal tokal mochanlcal enaray 0 the projectila (Give Vcir Jn ~tnee Aenicart Iauros | Taponau Oiltetntol cuftelimns roro than [0i Douba choct calculatons uppode proletulo tr *vellig %0,7 IVaal Mariruin Iaabl u $ Hom Hisilt naik hae Oc...
5 answers
Calculate the pH of 0.700 M solution of H2A (Ka1 = 2.40 x 10^-5and Ka2 = 4.70 x 10^-8) Hint: Use an assumption, and check it!
Calculate the pH of 0.700 M solution of H2A (Ka1 = 2.40 x 10^-5 and Ka2 = 4.70 x 10^-8) Hint: Use an assumption, and check it!...
5 answers
Find the domain of Y = x3 _ 8(-8,All Reals except 3none ofthese
Find the domain of Y = x3 _ 8 (-8, All Reals except 3 none ofthese...
5 answers
Which of the following is incorrect?a. If a codon lacks a precisely matching tRNA, it can be read bya similar tRNA if either the second or third position of the codonwobblesb. Ribosomes are made up of protein and RNAc. Stop codons are recognized by release factors, which areproteinsd. Isoaccepting tRNAs are different tRNAs that bind the sameamino acids
Which of the following is incorrect? a. If a codon lacks a precisely matching tRNA, it can be read by a similar tRNA if either the second or third position of the codon wobbles b. Ribosomes are made up of protein and RNA c. Stop codons are recognized by release factors, which are proteins d. Isoacce...
5 answers
B. Here are three possible approaches to proving that AABC is isosceles. Which of these will give a valid proof and what criterion for congruent triangles would be used in each situation? Let X be the point of side AC so that BX LAC and construct segment BX. Let M be the midpoint of side AC and construct segment BM. Let D be the point of side AC so that the segment BD bisects LB and construct segment BD.
b. Here are three possible approaches to proving that AABC is isosceles. Which of these will give a valid proof and what criterion for congruent triangles would be used in each situation? Let X be the point of side AC so that BX LAC and construct segment BX. Let M be the midpoint of side AC and cons...

-- 0.021910--