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Mnined the Mtrzge numher o ytan brirrmn acridents for drivers In ! bre nis rities. Follwinz an tht Isus @nr JI citics east of the Mississippi rier und AissEsippi ri...

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Mnined the Mtrzge numher o ytan brirrmn acridents for drivers In ! bre nis rities. Follwinz an tht Isus @nr JI citics east of the Mississippi rier und AissEsippi riverHonmuDaw uluc cata85 Min;OII o[ =confuene i[c Construct J %2.98 creet Ler M enalt [email protected] ^44 enSterie 4rical Kinie T0 uuc [altdiflcotlce Lrrw etu accldenrs m eJts belu teut Acridents #tSTetn cirics. Lse ncha & Min Me-AnceAnletemeeipabHeaedenaMennnal conidence

mnined the Mtrzge numher o ytan brirrmn acridents for drivers In ! bre nis rities. Follwinz an tht Isus @nr JI citics east of the Mississippi rier und AissEsippi river Honmu Daw uluc cata 85 Min; OII o[ = confuene i[c Construct J %2.98 creet Ler M enalt [email protected] ^44 enSterie 4rical Kinie T0 uuc [alt diflcotlce Lrrw etu accldenrs m eJts belu teut Acridents #tSTetn cirics. Lse ncha & Min Me-Ance Anletemee ipab Heaedena Mennnal conidence



Answers

Data from state driver's manual The state driver's manual lists the reaction distances, braking distances, and total stopping distances for automobiles traveling at different initial speeds (Table 2.11 ). Use the data to determine the driver's reaction time interval and the acceleration of the automobile while braking. The numbers assume dry surfaces for passenger vehicles. $$ \begin{aligned} &\text { TABLE 2.11 Data from driver's manual }\\ &\begin{array}{cccc} \hline \begin{array}{c} \text { Speed } \\ \text { (mi/h) } \end{array} & \begin{array}{c} \text { Reaction } \\ \text { distance (m) } \end{array} & \begin{array}{c} \text { Braking } \\ \text { distance (m) } \end{array} & \begin{array}{c} \text { Total stopping } \\ \text { distance (m) } \end{array} \\ \hline 20 & 7 & 7 & 14 \\ 40 & 13 & 32 & 45 \\ 60 & 20 & 91 & 111 \\ \hline \end{array} \end{aligned} $$

Everyone is. What we have are different reaction times for people who are normal and another one who's people who are drunk. We know that people who are normal can react that 0.75 seconds and those who are drunk take three seconds to react. What we have is a vehicle moving a 44 ft per second and can decelerate at a rate of 2 ft per second. Squared, we were asked us all for is the stopping distance. So so what we can do first is software, the stopping distance from for normal driver. So what we can do first is solve for the car that all for the distance that the car moves while the drivers reacting and call this deep prime and say that this is equal to our times t so moving at a rate of 44 ft per second and a reaction time 440.5 point 75 seconds means at the car moves 33 ft. Next, we can use our Kinnah Matic equations to solve for the total stopping distance. After the driver reacts and applies the brakes so we can do is we can say that B squared is equal to V zero squared plus two times acceleration times Delta, ask So what is going to say? That's s minus zero and we can say that s is going to be our final stopping distance. And s zero will be the distance that the car moves while the drivers reacting. So we can say that this is zero squared is equal 2 44 squared plus two times negative too d minus 33. And solving this expression for D gives us that D is equal to 517 ft. Next we do it for the drunk driver and doing the same thing. We can see that Deep prime, which is the distance the driver travels while reacting, is equal to again be times T and plugging in for 44 times three seconds gives us that driving distance equal to 132 ft. Next by using our kingdom attic equations and saying that V zero squared. This word is equal to V zero squared plus two times acceleration times, Delta s. And by using the same argument that the initial distances 132 ft, you can say that zero squared equals 44 squared, plus two times negative, too D minus 1 32. Solving this ex equation equation for D gives us a stopping distance of 616 ft, which is 99 more feet than the normal driver.

Okay, so for number 63 or 2.63 you have us Interstate 64 are trying to find the me number of miles in each state along that. So we've got 16 plus 1 32 plus 1 24 plus 1 91 plus 1 83 plus 2 99. And you're dividing by the six states. So when you add that up, you get 9. 45 over six is gonna equal Ah, 157.5 miles. That's for part a. Then for part, B, um, find the mean distance between interchanges with the other interstate highways along I 64. So you've got a total of 945 miles. And so there's the one interchange, plus the 10 9. So that's 10 interchanges. So you're just trying to figure out the average mileage per interchange, and that's gonna be 94.5 Niles. All right,

Thanks. And this question were given a speedometer reading over one minute interval Every 10 seconds. We are having a specific velocity and we want to figure out how far this car has traveled within the first minute. So how do we do this? We can find out that the we're going to be using the beginning endpoints to estimate the distance. First. That is at 0 10 2030 40 and 50 seconds will be estimating our philosophy, will be using those velocities as our sample points. And then we're going to add them together. So why don't we figure out first what are change of time is changing between units? So we have delta T. Were given our time interval in seconds. We know that it's going to be of course 10 seconds. But that's also equivalent to saying that that is just 1/3 60 hours. And that's actually the very important part because now we can just multiply the 1 60. We can multiply this one over 360 by each of these. five points. Six point sorry. So we can calculate the distance traveled which I'm going to label his ex is equal to one over 360 times The value at 10 Plus the value at 20 Plus the value at 30 Plus the value at 40 Plus the value at 50. And don't forget the value of zero. Yeah. So you should only consider the values from 0 to 50. And when you evaluate this on your calculator you'll get that. This is going to be approximately 2.383 mi. This is if we consider at the beginning endpoints Yeah let's consider the let's consider the ending end points of the time interval. Of course are a delta T. Is the same from above. And of course we're going to have our distance as being 1/3 60 Being multiplied by all of these things. But we're going to only consider the values from 10 To 60, ignoring zero. So we have 162.9 plus one of 6.6 Plus 99.8 plus 1 24.5 plus 1 76.1 Yeah. Plus 1 75.6. And when we evaluate this we're going to get approximately 2.363 mi. No. And for the last part, we want to determine if we're using upper and lower estimates. Well, if we notice notice that over the velocity time from zero from the 1st 30 seconds it's going to be decreasing. But after that it's going to be increasing. So can we really say? We can divide us up into two cases on the cases where we are dividing. Where were decreasing. We can say that the the overestimate is gonna be a whatever is overestimating is going to be the upper end point and whatever is lower is going to be decreasing. The same applies vice versa. That's basically how you do this question.

To make this from a little bit easier. First time I set it up in standard form without evaluating what D is. So we're gonna have 0.31 X square minus 0.291 x and then plus 7.1 minus D. By doing it this way, I can see them on a value for every case here for both our A and B, my body is gonna be 0.0 r 0031 My B values gonna be negative. 0.291 in my see value will just be 7.1 minus t set apart A I give us that d eyes equal to one, which means my see value would just be 7.1 minus one, which is 6.1 seven employees into the quadratic formula, which is minus B plus plus and minus the square root of B squared minus four a c over two times a. And so let's play in these value. So a 0.31 is negative. 0.29 line my C baby 6.1. Yes, for the positive answer we haven't X equal to 62. Approximately 62. Let's call it 62.3. And from when I change it to be a negative square root, it's gonna be a 31.6. Okay, So the two ages were driving Is the fatalities of one in 1000 are for age 62.3 and 31.6. Okay, for the age where it would be triple. That means D is equal to three. That means my cva is the only thing we need to change our sea by is gonna become 4.1. Okay, so going back and just changing my see about you, you can see it only shows up one time in the quadratic formula, we continue to see to be 4.1. They said it's gonna be three times aside for people who are 76.6 years of age or 17.3 years of age. Okay, There you have it. Thank you very much.


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