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A sample of 1.25g of liquid benzene, C6H6, is burned in an adiabatic bomb calorimeter in the presence of oxygen gas_ The temperature before ignition was 21.314 degr...

Question

A sample of 1.25g of liquid benzene, C6H6, is burned in an adiabatic bomb calorimeter in the presence of oxygen gas_ The temperature before ignition was 21.314 degrees C and the temperature after the combustion was 26.519 degrees €_ The heat capacity of the entire calorimeter is 10,000 J/K: CsHs (V) 15 O2 (g) ~ > 12 COz (g) 6 HzO () Calculate the following and SHOW YOUR WORK ArxnU, A.H (enthalpy of combustion) at 298K A;He for CsHs given: A; He for COz (g)- -393.51kl/mol, A;H? forHzO (IJ is

A sample of 1.25g of liquid benzene, C6H6, is burned in an adiabatic bomb calorimeter in the presence of oxygen gas_ The temperature before ignition was 21.314 degrees C and the temperature after the combustion was 26.519 degrees €_ The heat capacity of the entire calorimeter is 10,000 J/K: CsHs (V) 15 O2 (g) ~ > 12 COz (g) 6 HzO () Calculate the following and SHOW YOUR WORK ArxnU, A.H (enthalpy of combustion) at 298K A;He for CsHs given: A; He for COz (g)- -393.51kl/mol, A;H? forHzO (IJ is-285.83 kJ/mol



Answers

One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was $20.826^{\circ} \mathrm{C}$ and the temperature after the combustion was $25.000^{\circ} \mathrm{C}$. This was an adiabatic calorimeter. The heat capacity of the bomb, the water around it, and the contents of the bomb before the combustion was $10000 \mathrm{JK}^{-1}$. Calculate $\Delta_{\mathrm{f}} H^{\circ}$ for $\mathrm{C}_{6} \mathrm{H}_{6}(\mathrm{l})$ at $298.15 \mathrm{K}$ from these data. Assume that the water produced in the combustion is in the liquid state and the carbon dioxide produced in the combustion is in the gas state.

Thermodynamics is the study of the relationship between heat work, temperature and energy. So here we're looking to calculate Q. for the burning of one mole of Benzene. So we know the specific heat capacity of the color perimeter. We know the change in temperature. That's 37.18. Subtract 25 degrees C. So Q. The caliber emitter, which is equal to see, multiplied by delta T. This is equal to positive one for 6 .769 units of killer jewels. So therefore, If we have 3.15g of C6 H6, which is Benzene, this is equivalent to 146.769 kg joules of heat energy. And so the energy change for the reaction is equal in magnitude, but it is opposite in science the heat capacity produced from the warming of the solution and the calorie meter. So therefore we have the following expression of negative one for 6.769 kg jewels, Divided by 3.51 g. Multiplied by 78.11 g into the valley. We get out of here negative three .27 times 10 to the three killer jewels Permal of C6 H six

So let's start by changing our grams of benzene to malls. So one mall is 78.12 g. That gives us .0449 moles are changing temperature is always final minus initial 37.18 -25 Gives us 12.18°C. R. C. Of our calorie emitter Is 12.05 killer jewels for degrees Celsius. So our Q. Is negative. See cal times delta T. -12.05 killed jules per degree Celsius times 12.18°C. So that gives us negative one 47 killer jewels for that many moles. So that gives us our delta H. Is negative 32 69 killer jewels per mole. But we want to know how many killer jewels will get if we use 1.25 moles. So that's gonna be negative for 0.9 Times 10 to the third killer jewels.

In the case of a bomb calorie emitter, we have a constant volume system. So with a constant volume system, the internal energy which normally equals q minus p delta v. Since the change in volume is equivalent to zero, the change in internal energy of the system, it's just the heat transfer of the heat transfer of the system. So in this case we have our system mainly as 1.048g of a certain compound With a molar mass of 78 g promote. And we find that once we put this system into a bomb calorie meter, which has a massive H 20 of 945 g. And we know the heat capacity of H 20 Is 4.184 jewels program degrees Celsius. We find that the temperature change in the surroundings, which is the water and the calorie meter itself in this case Is equivalent to 32.69 to -23.64. And we find that the temperature changes 9.05, 2 degrees Celsius. Okay, so we also know that the calorie meter constant is 891 tools per degree Celsius. When we're doing the heating combustion process, we have to heat both the water and the accelerometer. So they are both technically at the same temperature. So we can find that the heat transferred is equivalent to The mass of H 20. The capacity of water times the change in temperature plus the calorie meter constant times the change in temperature of the surroundings. So this is for the surroundings by substituting our values in. Okay, and converting to kill jewels as a more convenient unit. In this case, We can find that the change in the heat of the surroundings is 43 .9 Killer Jewels and converting this to into the system, which is one of the system is negative heat transferred of the surroundings. This is equivalent to negative 43.9 killer jewels. So this is for Benzene. So in this case we can write this as since it's for a constant volume system, it's the change in internal energy. So this occurs for 1.048g of our substance so we can delight this out And we find that this is approximately negative 41.9 killer jewels. Program and now we can convert this into killing joules per mole. And for one mole of us, uh certain One more certain reaction occurring, we have 78gg of our substance to negative 41.9 times 78 is equivalent to negative 3268 killer jewels promote. So here and I forgot to write out the combustion reaction. So we're combusting benzene. So this involves auction so we need to balance our reaction accordingly. So since we find the coefficient of auctions out here, we have to double the concentration of all our components, an auction is in excess here, so we really don't have to consider it in terms of our bomb calorie meter system, This becomes 12 co two plus six H 20. And we can find that the told the number of auction atoms is 24-plus 6, which is 30. So this is plus 15 auction atoms. And let me rewrite that. So this becomes plus 15 oxygen yields 12. c. or six h 12 groups. And this is the chemical reaction for what is occurring within the bomb columns. And that's it.

Okay for this question, daughter e equals to minus on sea daughter tea. So in this question, army will strew zero point to fire 1514 grams C postal 5.86 on Dr T is 33.33 minus 24 pointed to fire themselves this degree we have easily calculated out E on DDE. The most off by Fino equals to, um, divided by the molar mass. And so the daughter ye reaction equal strode out on e miners minus the total more off the reactor and equals two minus 6.3 times 10 to the power off three killjoys hormone.


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