This question was shown to potential Louis diagrams for the sulfate ion and this particular question were asked which of the following statements regarding Structure B is true? Is it a. The double bonds must be located opposite it each other due to additional electron propulsion be it is more polar. It is a more polar molecule than the molecule represented by structure a. See, the bonds of the molecule are weaker than those in structure A where d oh bonds in the molecule are identical to each other. So any time you see a molecule drawn in a way in which um residence exists, then this is just one of several different structures. So, for example, if I were to draw this where these electrons kicked down and these electrons kick out and now the double bond is here rather than hear, the molecule has not changed. There's still two double bonds to single bonds, and this structure that is given to us originally and the one I've just edited are identical to one another. All residents directors are identical, and you could move these electrons around several times, but the same about here. And though I'm here and so on. So all the resin structures air equivalent to one another. Therefore, uh, this molecule doesn't have polarity. If all of the structures are, um, are equivalent one another, there's no one direction which the the Di Poole is directed, uh, the they don't have to be on opposite sized or another. You can draw this residence structures in any particular way, and yet you control them any particular way. Are the bonds weaker than in structure? A. No, There's some double bond character. Each of these bonds will be slightly stronger, and so the only correct answer is D that all the bon in the molecule are identical because they're all resident structures of one another.