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Draw a FBD of 43 _602...

Question

Draw a FBD of 43 _602

Draw a FBD of 43 _ 602



Answers

Determine the resultant of the three forces of Prob. 2.22.

We want the resultant of these three forces and the resultant is simply just the some of the forces in the X plus the some of the forces. And then why? So that would be your X and Y components of the resultant. So our forces in the X are gonna be 1 20 times the co sign of 70 degrees, because it's 40 plus 30 plus 80 times the coastline of 40 degrees minus 1 50 times the co sign of 35 degrees minus. Because that forces pointing to the left in the X direction. So we get an X component of the resultant of negative 20 0.55 Nunes and then our Why components some of the forces in the why 1 20 times a sign of 70 plus 80 times the sign of 40 plus 1 50 times the sign of 35 and that comes out to be 250 points to two news. So to get the magnitude of that result in, well, that's just the square root of the X components. Where was the lifeboat in squared? So it's the square root of native 20.55 squared plus 250 squared and we get a magnitude of 251.1 Nunes. And now we want the, um the angle. So our result in let's use dream here. We know we have Rx in the negative direction left and are why up? So the result is gonna look something like this. So the magnitude of that result since excuse me, the angle of that salt resultant all called Alfa and the tangent about was equal to the opposite side with you, Jason, which will be our why over our X, and that's going to give us an angle of 85.3 degrees.

A table, and on top of the table is an apple. Now the forces would be, gravity is pulling the apple downward, but a normal force is being exerted by the table onto the apple, and it is equal and opposite to the gravitational force um there by the net force.

In this problem. We have a chair, friend. Okay. On that there was employed force. Push it forward. This is, if applied the reason there. Gravitational force down board and reads a normal force applied from floor to the chair at is footwork. We want to draw the free body diagram off this object. So first of all, you should draw that X and y axes. Fenton, just draw them. F g is done. Board. That is 155 near turn F and is off barred. And as it is expected, it is 155 years old upward on that Lloyd Force is in at the direction off XX is positive. XX is that is 185 Newt. So he's forces as it is. Ah, obvious here in the Y direction. You don't have any net force On the net. Force along xxx F net along X axis. It is 180 five

Using vector addition for K Expose K. Why we have negative one Cover five plus seven comic three, which gives us six comma eight and then we have 10. So this means that we now have our signal force in our magnitude.


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