5

CalculationsWrite balanced hypothetical net-ionic chemical equation (even there Is no apparent reaction) for each of the eight systems in table similar t0 the one b...

Question

CalculationsWrite balanced hypothetical net-ionic chemical equation (even there Is no apparent reaction) for each of the eight systems in table similar t0 the one below. Be sure that these equations are written correctlylReactionBalanced Hypothetical Net-Ionic Equation8-9Calculate AG? for each of the above reactions using the data given in Table on page Arrange your results in table similar to the one below:AG' = AH' TAS?ReactionAH? (kJlmole)Aso (kJlmole K)AG? (kJlmole 8-9"Note: K

Calculations Write balanced hypothetical net-ionic chemical equation (even there Is no apparent reaction) for each of the eight systems in table similar t0 the one below. Be sure that these equations are written correctlyl Reaction Balanced Hypothetical Net-Ionic Equation 8-9 Calculate AG? for each of the above reactions using the data given in Table on page Arrange your results in table similar to the one below: AG' = AH' TAS? Reaction AH? (kJlmole) Aso (kJlmole K) AG? (kJlmole 8-9 "Note: K; Ni(NHbJa? (aq) 2.0 108 at 25*C_ Calculate AG? for reaction using 4G' = -RT In Kwhere R = 8.31 Jlmole K and T = 298 K



Answers

Balance each of the equations below, and indicate the type of reaction for each equation.
a. $\mathrm{Cl}_{2}(g)+\mathrm{NaBr}(a q) \rightarrow \mathrm{NaCl}(a q)+\mathrm{Br}_{2}(l)$
b. $\mathrm{CaO}(s)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{Ca}(\mathrm{OH})_{2}(a q)$
c. $\mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2}(s) \rightarrow \mathrm{CaCl}_{2}(s)+\mathrm{O}_{2}(g)$
d. $\begin{array}{rl}{\operatorname{AgNO}_{3}(a q)+\mathrm{K}_{2}} & {\mathrm{SO}_{4}(a q)} \\ {} & {\mathrm{Ag}_{2} \mathrm{SO}_{4}(s)+\mathrm{KNO}_{3}(a q)}\end{array}$
e. $\mathrm{Zn}(s)+\mathrm{CuBr}_{2}(a q) \rightarrow \operatorname{ZnBr}_{2}(a q)+\mathrm{Cu}(s)$
f. $\mathrm{C}_{8} \mathrm{H}_{18}(l)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)$

Problem Number eight from Chapter eight off chemistry. Here we have to balance the chemical equation. The Cuban in question is chlorine is treated with sodium bromide. You rise to sodium chloride on Dromi here. When we are balancing, the chemical equation will be writing the reactive side atoms of reactive side as well as at himself. Our blood outside on the right hand side, off the product side, that is, product side. Chlorine is only one on, whereas chlorine. On the reaction side, it is, too. So we have to pass the chlorine atom, so we have to multiply it by two toe, make the chlorine atoms to and then So when he'll be writing like this, we have to balance the chemical equation. We had to write to any seal on the product side once again. When you will be balancing this on the left hand side off, the question now so remains to, so we have to balance it. Multiply it by sodium. Also by two. Andi Brahman is already too, so it is part implied by one. So when will be balancing the question? On the reactant side, it iss c l two plus two nbr give rise to to any C l plus B R two. Now, though completely balanced equation is formed on this equation is single displacement reaction. I'm coming to the second equation that ISS calcium oxide when it is treated with the hydrogen oxygen, that is water will be getting calcium hydroxide here, everywhere. On the reaction side, on the product side, everything is same. Catch him on the reaction side, it is one as well as on. The products are also it is one on oxygen is to on products it also it is to on hydrogen is toe oxygen is also you. So it is completely balanced equation because of that Oh, it is as usual, That is cash. Um, oxide is treated with, uh, water Doris toe calcium hydroxide. I'm coming to third equation that is calcium chlorate on the second equation, that is decomposition competition reaction as well as a true thermic reaction. It's also called a synthetic reaction Coming to third equation that is calcium chloride read give rise to calcium chloride on oxygen Once again. Here on the reacting side, calcium is one on the product. Several cities. One chlorine is two times on. There Also, it is on the product side. It is. Perhaps I'd also it is to on coming toe oxygen that is on the react. Inside it is 3266 atoms off oxygen. So it is on the right hand side. Off the product side, it is only two atoms off. Chlorine is oxygen is there, so we have to make it six. So we have toe multiplied by three to get six. So once again, our question is, we'll be having three, three times or two three times a photo on the product side. Now the chemical equation is completely balanced on Dhere. Calcium chlorate give rise to calcium chloride on oxygen. On this kind of reaction will become it as the competition reaction coming toe fourty question. The given equation is silver nitrate when it frustrated with potash himself. Eight give rise to silver self weight on potassium nitrate. Once again, it is will be taking, and No three as a whole molecule will be completely balancing it. On. Silver is one atom off silver on day one atom off nitrogen night raid on one at one molecule of self eight on board to act himself, potassium in No. Three is also a molecule. One molecular off my trade. One molecule off. Self aid. On. On the product side, we'll be having silver two atoms off silver on one ad evolve nitrate onda self. It is also one atom on potash amis, also one. So we have to balance the potassium first. On the reactant side, we will be having to act himself potassium, so we have to multiply on the right hand side of the product side, potassium is multiplied by two. Potassium is multiplied by two to balance the potassium on. Then we'll be having because of that. On the product side, you'll be having two times care No. Three. So once again, when it becomes to dance can or three on the product side, we have to build apply nitrogen nitrogen, that is a night raid. We have to multiply it by two to balance the chemical equation, because off that once again, on the reactant side, we have to multiply our silver also by to toe make it balance in the formula in the chemical equation two times a day and no three plus gateways afford the rise to 82 s a four plus two K and No. Three on this reaction is deeper displacement reaction. This reaction is called us double displacement reaction coming to fifth equation 50. Chemical equation *** is treated with carpet bromide and you runs toe jink, bromide and copper. Everything is balanced on the reactive side. Jink is one atom. On the parks are all status one copper, result of one on copper that products around. So it is one on grooming themselves to on on. The products are also right hand side. It is, too. That means the whole equation is completely balanced. On this reaction, we will be calling it as a single displacement reaction on Dhere. Jink as the *** is very react thio metal with displaces copper very easily to get jink bromide in the product side coming to six. The equation. Sixth given equation here Al cane, that is the formula C and H two n plus two. Here it is. Eight Atoms of carbon is there. So it is octane. When octane is treated with oxygen, give rise to carbon dioxide on water on once again coming to react Inside carbon is eight. Acting's off carbon 18 and tips off hydrogen and oxygen is only two. And on the other side, that is product side. Carbon is only one atom of carbon. Is that toe balance it be how to multiply it by eight. Carbon is multiplied by eight on the product side on once again On the right hand side it is hydrogen is two atoms of hydrogen is their toe. Make it 18 because on the reacting side, 18 atoms of hydrogen is there. So we have to multiplied by nine toe. Make it balance. So it is. Hydrogen is multiplied by two into nine. That's equal to 18. I'm coming to oxygen. We'll be having in carpet a except two at himself. Oxygen is there on the water molecule within. The water molecule will be having one oxygen atom. Because of that, two plus one is three at himself. Oxygen, oxygen Is that on? Once again? Here will be having eight atoms saw eight molecules off carbon dioxide eat molecules off carbon the oxide on DSO it is And here nine molecules off water, nine molecules off water. Now the at himself oxygen is 82 other that is 16 8 to the 16 at himself. Oxygen 16 atoms off oxygen plus nine at himself. Oxygen in water molecule, 16 plus dying that is together. It is 25. Because of that, we have toe. We'll be having 25 25 molecules off oxygen that ISS once again. Oh, to make it whole number, this is 25 by 2. 25 divided by two. So to make the whole number, we have to multiply whole equation Whole chemical equation by two. So at that time will be happy. Two items to molecules off obtained. Two molecules off obtained on 20 if I buy two that prince two into two. That is 25 by two into 222 Gets canceled on 25 molecules off oxygen. Give rise to eight. Politics off carbon dioxide on nine molecules off water on This is the chemical reaction is, uh, compassion reaction

Here. We have several chemical reactions. A little balance and identify. The 1st 1 is ammonia reacting with hydrochloric acid or HCL producing ammonium chloride. It's already balanced. They have combined. So this is a combination reaction. But then have a hydrocarbon reacted with oxygen producing carbon dioxide and water. So this is a combustion reaction. This takes a little bit more to balance back up just a little bit. We'll see that we have four carbons, so we're gonna need to put a four right here. Now, um, we have eight hydrogen, so we need to get where you need to put a four right there to get eight hydrogen. Now, we have generated 12 oxygen, so we need to put a six right here to get our 12 oxygen's for the next reaction. We just have antimony combining with chlorine. So this is a combination reaction. We have, um, six. Well, right now Or we could make the chlorine is equal. So we have three chlorine and two chlorine, so I need to put it to right here to get six chorines, and then we need to put three right there to get six chlorine that introduced to antimony. So we need to put it to right there for antimony. And this is a combination reaction. The next one. We have nitrogen tri iodide falling apart into nitrogen. And I we have two nitrogen, one nitrogen. So we need to put a two right there. That then gives us six. I dines, so we need to put a three right here to get six ia dines. For this is the decomposition reaction. Give er reacts with C l to producing K, C, l and B R. In order to balance it, we have to see l. So we need to put a to in front of the K C L. We have to be ours. So we need to put a to in front of the KBR. This would then be a single replacement reaction as chlorine replaces roaming. We have iron combining with sulfuric acid, nobody's iron, three sulfate and hydrogen gas. This is a single replacement reaction where the iron replaces hydrogen. To balance this, we have three sulfates, so we need to put a three right here. We have two irons, so we need to put a two right there and then we have six hydrogen, so we need to put a three right there, and we have aluminum sulfate reacting with sodium hydroxide, producing sodium sulfate and aluminum hydroxide. This will be a double replacement reaction in order to balance it if we have to. So Diem's here would have to put it to here. But then, that's not gonna balance our hydroxide. We have three hydroxide, so the two of the three gives us six. So now we've got six sodium hydroxide, which will require a three to get our six so Diem's and then to hear, to get our six hydroxide and then that will give us the two aluminum's, which we have over here with our three sulfates, which we already have right here.

For the first chemical reaction. We have, uh, try silicone. Uh, Tetra and I tried falling apart into silicone and nitrogen gas, so this would be decomposition reaction. In order to have a balanced, we need to have three silicones and four nitrogen is we need to put a three and the two on the products that we have magnesium reacting with nitrogen producing magnesium. And I tried. We have three. Magnesium is on the right hand side, so we need three. Magnesium is on the left hand side by adding a three on the magnesium. This, of course, is a combination reaction as the magnesium combines with the nitrogen. Then we have aluminum solid reacting with phosphoric acid, producing aluminum, phosphate and hydrogen gas. The aluminum replaces the hydrogen. So this is a single replacement reaction. And in order to get this one balanced, we back up. We have one aluminum and one aluminum. So those air balanced. But we're gonna recognize that in order to have the hydrogen is balanced, we're gonna need to put a to here and a three. Here. We put two here. We're gonna need to phosphates, so we have to False states. We're gonna need to Aluminum's. And then once we have the two phosphates to to aluminum's, the on both sides, then we will see that we have six hydrogen, so we need a three right there to have six hydrogen. Then we have a hydrocarbon reacting with oxygen producing current outside of water. This is a combustion reaction. To balance this, we have four hydrogen ins, so we need to put a two right there for four. Hydrogen have three carbons, so with three right there and then that generated eight oxygen's on the right hand side. So we need the four on the oxygen on the 02 to get eight oxygen's and we have CR 203 reacting with hydrogen, producing just chromium and water. So the hydrogen is replacing the chromium. So this is a single replacement reaction. We have two chromium, so we need to put two on the chromium right there. We then have a total of three oxygen's, so we need three Oxygen's here, so I need to put a three here on the waters. We have three oxygen's that then created six hydrogen swinging, but a three right here for six hydrogen. But only when I'm solid reacts with chlorine gas to produce aluminum chloride. They just combined together. So this is a combination reaction. We have three chlorine, and we have to glory means. So the common denominator is gonna be six. So we need to put a two right here to get six chlorine zone A three right here to get six chlorine, but we put it to right there. We're gonna need to put it to right there for the two aluminum's and magnesium chloride reacts with silver nitrate producing magnesium nitrate and chloride. This solid right here is what we call a precipitates. We might call this a precipitation reaction, which is an example of a double double replacement reaction. And we had to glory ins here. So we need to put a two right there to get to chlorine that introduced two silvers 22 right there to get two silvers that then introduces to nitrates. But we have to nitrate, So now it's balanced

So this problem asks us to calculate Elegy of Reaction and K Q for two different reactions. So we'LL start with Letter A, which is chromium to plus Aquarius and chromium two o seven to minus Aquarius, forming chromium three plus Aquarius. And so if we split this up into half reactions, we have chromium to plus Aquarius forming chromium three plus plus C minus. That's our oxidation, which has the potential of zero point for two vaults. And then our reduction reaction is CR two o seven, two minus plus fourteen h plus plus sixty minus forms to chromium three plus plus seven h two o and the reduction potential Here is one point three three votes, and so therefore, East Cell. We just add those together and we get one point seven five volts. Now we can calculate our delta G of reaction pretty straightforward. Leesh just negative and F e cel, which is negative. Six electrons times Faraday's constant nine six four eight five times Our east cell, which gives us negative. One zero one three zero nine three jewels. Permal. So now I go to a new page to find the but archaic equation is e to the negative Delta Jeannot reaction over Artie, which is equal to e to the one or one three zero nine three, divided by eight point three one four times two ninety eight. And that gives us a K e q of three point eight three times ten to the one seventy seven so massively large number that I actually needed to get a new calcula calculator to get it to go that high. Now for a letter B, we have chromium three plus plus chromium solid, forming chromium to plus a Prius. And so now we take our chromium salad, which is our oxidation, and give the oxidation potential for that zero point nine one volts and then our chromium three plus two chromium to plus reduction, which gives us an E reduction of negative zero point for two vaults. So we add these together to get our East cell, which will be zero point for nine volts way that we have that we confined our delta G of reaction which will be negative and f e cell so negative to In this case, we have two electrons nine six for eight, five times zero point four nine, which gives us negative nine four five five, five point three Jules per mall as our Delta ji of reaction. And then we find our cake the same way we did in the previous example. So now we have nine four five five, five point three, divided by eight point three one four times two ninety eight. And that gives us a K e q of three point seven, six times ten to the sixteenth. And so those are our apologies, a reaction and cake for the two scenarios given in the problem.


Similar Solved Questions

5 answers
3 fgr - 1 11 B 1 U U 1 1 1 1 1 1 1 1 ol # 1 8 ; 3L+ 9 3 1 L 171
3 fgr - 1 1 1 B 1 U U 1 1 1 1 1 1 1 1 ol # 1 8 ; 3 L + 9 3 1 L 1 7 1...
4 answers
Solid #mmeniut chromate slowly adled 175 mL ofu 0,0558 initiate prce!pitationrcqulIC4 [0 IuA
Solid #mmeniut chromate slowly adled 175 mL ofu 0,0558 initiate prce!pitation rcqulIC4 [0 IuA...
5 answers
Homework: HW 2.6 Part 1 Applications of Derivatives Score: 0 of 5 of 10 (10 complete}Instructor-created question The height (feet) of aunched the alr = seconds alter It is launched given Dy:f() = 1612 + 311t+19,Aftor how many seconds Ihe bal (alling 140 Ieei per socond?S8C4necossary (ound two decimal placos .thero Mare than one corract answer; suparate them widh commas
Homework: HW 2.6 Part 1 Applications of Derivatives Score: 0 of 5 of 10 (10 complete} Instructor-created question The height (feet) of aunched the alr = seconds alter It is launched given Dy: f() = 1612 + 311t+19, Aftor how many seconds Ihe bal (alling 140 Ieei per socond? S8C4 necossary (ound two d...
5 answers
Score: 0 ol 1 pl Maasuus 7.2.41 housu at B, survayor Eslance each house atAlo Ilie wake = ofl the the distance hom four be 40" . and tien are the housos? To find which 6 lound l0 How far apart the angle ACe Md 60 (eet tonprctlvely housc, 40 (oel =60 nE7yfeet apart mcded ) The houses are nomesi hundredh (Round to IheJont
Score: 0 ol 1 pl Maasuus 7.2.41 housu at B, survayor Eslance each house atAlo Ilie wake = ofl the the distance hom four be 40" . and tien are the housos? To find which 6 lound l0 How far apart the angle ACe Md 60 (eet tonprctlvely housc, 40 (oel = 60 n E7y feet apart mcded ) The houses are no...
5 answers
Pati4<tdonde E(t) estii en voltios Eucuentre carga en coulombxs Kespuestu;condensador en tiemposgundos. Tome 9(0)
pati 4<t donde E(t) estii en voltios Eucuentre carga en coulombxs Kespuestu; condensador en tiempo sgundos. Tome 9(0)...
5 answers
10. particle moves in straight line and has acceleration given by alt) = 10sin t + 3cost. Its initial position s(0) 0, and :(27) =12 Find tbe position function s(t) of the particle:
10. particle moves in straight line and has acceleration given by alt) = 10sin t + 3cost. Its initial position s(0) 0, and :(27) =12 Find tbe position function s(t) of the particle:...
5 answers
4363839Moving to another question will save this response.Question 21The hybridization concept is for ionic bonding covalent bonding none oi theseMoving to another question will save this response
436 38 39 Moving to another question will save this response. Question 21 The hybridization concept is for ionic bonding covalent bonding none oi these Moving to another question will save this response...
5 answers
The V Jnok Botve AX=B # A 1 X= 075ard 8 = 5
The V Jnok Botve AX=B # A 1 X= 075 ard 8 = 5...
5 answers
When a 25.4 grams sample of aluminum (CAI 0.900 J/gOc) is heated to 93.3 degrees Celsius and placed in a coffee cup calorimeter that contains 63.5 grams of water (CH2O = 4.184 JgOc) at 20.0OC, what will the final temperature of the system be when thermal equilibrium is attained? (SHOW WORK and DO NOT WRITE UNITS IN YOUR ANSWER)
When a 25.4 grams sample of aluminum (CAI 0.900 J/gOc) is heated to 93.3 degrees Celsius and placed in a coffee cup calorimeter that contains 63.5 grams of water (CH2O = 4.184 JgOc) at 20.0OC, what will the final temperature of the system be when thermal equilibrium is attained? (SHOW WORK and DO N...
4 answers
Section 6.3 Step Function: Problem 16 Previous Problem Problem List Next Problempcint) Conipute the inverse Laplace transfomm O1Fls)j()(Notation: #tife u(t-C) {Or Ine Heaviside step function u.(t) with stcp &: /
Section 6.3 Step Function: Problem 16 Previous Problem Problem List Next Problem pcint) Conipute the inverse Laplace transfomm O1 Fls) j() (Notation: #tife u(t-C) {Or Ine Heaviside step function u.(t) with stcp &: /...
4 answers
PART IV: COMMUNICATION 7. m) When finding the cross product of tWO non-zero vectors how do we find the direction of crOSS product vector! Assume the vectors are not collinearb) Does the order in which the cross product is performed affect the result? Explain
PART IV: COMMUNICATION 7. m) When finding the cross product of tWO non-zero vectors how do we find the direction of crOSS product vector! Assume the vectors are not collinear b) Does the order in which the cross product is performed affect the result? Explain...
5 answers
You are conducting test ofhomogeneity for the claim that two different populations have the same proportions of the following two characteristicsHere is the sample data Population |Population CategoryThe expected observations for this table would Population |Population CategoryWhat is the chi-square test-statistic for this data?Report all answers accurate t0 three decimal places
You are conducting test ofhomogeneity for the claim that two different populations have the same proportions of the following two characteristicsHere is the sample data Population |Population Category The expected observations for this table would Population |Population Category What is the chi-squa...
5 answers
1) hypothesize why potassium channels have evolved to betetrameric? 2) explain why the amino acids that "carry" the positivegating charges in the potassium channel voltage sensors arearginines and not lysines?3) explain how potassium channels can be thought of asenzymes. Your explanation should apply principles of enzymecatalysis to the structure and function of the potassium channelpore domain.
1) hypothesize why potassium channels have evolved to be tetrameric? 2) explain why the amino acids that "carry" the positive gating charges in the potassium channel voltage sensors are arginines and not lysines? 3) explain how potassium channels can be thought of as enzymes. Your explana...
5 answers
Questicn 205 ptsSolve the following by Cramer'$ Rule:31 - 6y = -5 I + %y = 63,3 (3,2) (6,@) Cramer' $ Rule fails to solve this system
Questicn 20 5 pts Solve the following by Cramer'$ Rule: 31 - 6y = -5 I + %y = 6 3,3 (3,2) (6,@) Cramer' $ Rule fails to solve this system...
5 answers
Find the arc length of the curve below by integrating with respect to y: x=Sy 5; for 2sys4An integral that gives the arc length is(Type exact answers )The arc: length is (Type an exact answer:)
Find the arc length of the curve below by integrating with respect to y: x=Sy 5; for 2sys4 An integral that gives the arc length is (Type exact answers ) The arc: length is (Type an exact answer:)...

-- 0.021919--