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Wtc Aoums On obdicc Campenrd Rurctitn Jaalyl e Wuckk #n fuzaeirp douiltd 8on) "Xo otkule Pa] Gnl Puubablyy Compminu Ppente atlta Qod hsuns withacy tail ue Rah...

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Wtc Aoums On obdicc Campenrd Rurctitn Jaalyl e Wuckk #n fuzaeirp douiltd 8on) "Xo otkule Pa] Gnl Puubablyy Compminu Ppente atlta Qod hsuns withacy tail ue Rah Conta ` TUu Compmutb AQ equlpmendt Tail alau dealo ~oeli] eplpred i, temfrercu Fnd Anebabluy J mid DuuiUl Rvab 900 hau) ilhcudt 'taie

Wtc Aoums On obdicc Campenrd Rurctitn Jaalyl e Wuckk #n fuzaeirp douiltd 8on) "Xo otkule Pa] Gnl Puubablyy Compminu Ppente atlta Qod hsuns withacy tail ue Rah Conta ` TUu Compmutb AQ equlpmendt Tail alau dealo ~oeli] eplpred i, temfrercu Fnd Anebabluy J mid DuuiUl Rvab 900 hau) ilhcudt 'taie



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$\mathrm{FcCl}_{\text {j }}$ solurion addcd ro $\mathrm{K}_{i}\left[\mathrm{Fc}(\mathrm{CN})_{6}\right]$ givcs (a) while with KSCN gives (b). (a) and (b) respecrively arc (a) $\mathrm{Fe}_{1}\left[\mathrm{Fe}(\mathrm{CN})_{\mathrm{G}}\right]_{3}, \mathrm{~K}_{3}\left[\mathrm{Fe}(\mathrm{SCN})_{6}\right]$ (b) $\mathrm{\Gammae}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}, \mathrm{~K}_{3}\left[\mathrm{Fe}(\mathrm{CNS})_{6}\right]$ (c) $\mathrm{Fc}_{3}\left[\mathrm{Fc}(\mathrm{CN})_{i}\right]_{2}, \mathrm{Fc}(\mathrm{CNS})_{3}$ (d) $\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}, \mathrm{KFe}(\mathrm{CNS})_{3}$

Okay, so let's first calculate a director a director be okay? We just thought the corresponding coefficient or the corresponding component and add them together. Okay, So this equals 4 -15 21 which you cause minus 32. Okay, so the magnitude factor echoes. Okay, the square root of this expression which is Scores of 74 and further magnitude of vector B. This is square root tough, one squared plus five squared plus three square and take the square root which is around Squirrels of 35. Okay, so we know according to the definition, we know consistency to, he calls better a little better be over the magnitude of vector eight times the magnitude of vector B, which he calls minus 32. Over square root of 74 times Square 35. Okay. We know that the gazeta equals universe. Cause I of listen this value. Uh huh. And again, the result is around One during the 28.9°. Okay.

We're looking at a population of stray cats about three quarters of them have a stumpy tail, one brought up as a long tail. So if we cross the, simply tell cats to each other, we get some, something tells some long tails. If we cross long tell cats we only get long tells. What does he say about the genus type belong towels cats are they all uh multi little T. Both capital T. Little T. And A. T. T. See Capital city and capital C. Capital city or all hetero signups. Okay, so the important thing to do first is to see that long tell cats crossed with long tail cats gives long tailed kittens. Whereas if you stumpy tails cats you get some a beat. And this is this makes you think that the stumpy tail of freight maybe dominant? Because if we look at that, if we have t T. As being a hetero zygotes? If stumpy tails is the dominant traits, these would both be stumpy tailed parents. But we would get some some details and some long tails. If we were to cross too long tail cats where we can't have the capital T. Because it's dominant? Famous like that. And then all of the offspring was also been tell us. So that's how we can tell which arbitrates is dominant because there is room for them to be carriers of the long tailed spritz without expressing it as a friend inside. So what do we know about the long tailed cats while they have to resuscitate rate. So they must be a Hamas august recess it

So we're given that we have the angle between two forces, single. Between the two forces is um 37 degrees. The one force is 1700 newtons and then the other forces 2500 Nunes. So the X. Direction or the X component is going to be 1700. Um Since we know the two forces um the actual direction of the force does not matter. Instead we're more focused on it is just the fact that this is 1700 and this is 2500. So keep in mind that in this case the direction of it um is only going to matter in the sense that will have 1700 co sign 37. This will be 2500 sign 37 and it's a big plus 2500 post sign 37. This will be plus 2500 9, 37. And we do that, we end up getting 40 I have 100 newtons approximately. Um So depending on how around, we would say that the resultant magnitude is this is going to be 1700 so we end up getting 4200, or depending on how you round about 4000 newtons for magnitude.

Okay so for bacteria and vector B let's find the magnitude of vector A. Vector B. So I just need two times the corresponding coefficient together and add them up. Okay So I got -18 -15 plus two. Which recalls -31. Okay and now let's find the magnitude of vector A. So I need a vector equals minus three square plus five square plus two square. And take the square root. Yeah. Which he calls. Yeah Its growth. 38. Okay. Mhm. And now let's find the magnitude of vector B. Which is called which is square world six square plus minus three square plus one. Which equals 4 46. Okay now let's let's assume the angle between vector A. And vector P. A. C. To so called Cfcda. It goes A. That be over in 98 times the magnitude F. B. Which he calls. It'll be is -31 Over the squirrel. 38 times this quota. 46 which is okay. You can factor out too. Okay Times two out of 19 times squared of 23. So let's find the value. Please check around 3.74 one. Okay so the angle theta we can use the universe coastline function to find out. So universe coastline of minus They were .7 uh 741. Okay. Which is around 138 degree. Okay


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