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For norma population with mean equal to 77 and standard deviation equal to 19 determine the probability of observing sample mean of 84 or less from sample of size 1...

Question

For norma population with mean equal to 77 and standard deviation equal to 19 determine the probability of observing sample mean of 84 or less from sample of size 12Click here to viewpage of the cumulative standardized normal table Cllckhere Jo_ ylelpaqe Quhe cumulatie stanchrdlzed normalabm)P (xs84) (Round to four decimal places as needed:)

For norma population with mean equal to 77 and standard deviation equal to 19 determine the probability of observing sample mean of 84 or less from sample of size 12 Click here to viewpage of the cumulative standardized normal table Cllckhere Jo_ ylelpaqe Quhe cumulatie stanchrdlzed normalabm) P (xs84) (Round to four decimal places as needed:)



Answers

Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. $n=84, p=0.65$

And this question, we're told that a population has mean of 72 and a standard deviation of six. And for us to find the mean and standard deviation of this sample means. So the mean of sample means is 72. The standard deviation is six over squared of 45, which is .8944. Have our answer to part a Part B. We're asked to find the probability that the mean of a sample of size 45 will differ from the population mean 72 by at least two units. So we're basically asked for the probability that The mean is less than 17, Or that the mean is more than 74. So We're basically going to find the probability that Z is less than -2.24, And Z is more than 2.24. So actually, because this is the standard normal distribution, these areas are the same. So this is basically two times, Probably easy, less than -2.24, Which is two times 0.0125, which is 0.025.

So in this question, we're told that a population has a mean of 48.4 and a standard deviation of 6.3. And first we're asked to find the mean and standard deviation of the sample mean. So that's the the mean is just the population mean, which is 48.4. And the standard deviation of the sample mean is san traditional population divided by square root and which is basically six point 3/8 And that is .7875. Now, we're asked to find the probability that the mean of a sample of size 64 will be less than 46.7. So we have probability standard normal random variable is 46.7 minus 48.4 over .7875. So that's probability is the less than -2.16, Which is 0.0154.

Here we have to find mean That is expert and standard deviation that is Sigma for the given set of values. So this to all the unknowns here. So let us find first mean like let us first find the meat so mean expert will be closed toe. So this is given a summation off the given set of values. They would bite portal number of values. So on substituting the values he ever get the summation off the given set of values will be caused to one yet 10 dared by the total set, the total number of values in the given cities seven year have seven set of values. So on dividing 1810 by seven will get answered us to 58 0.57 so we can round this off too. So we'll get the mean values to 59. So this is the mean man, you that is expert. So this is the answer. The first part of the answer now coming to second part of the answer that is where to find the standard deviation you. So standard deviation is given by formula that is quite right. Off summation off X minus expert, The old square divided by the number of times that is in so on, substituting the values here we'll get the standard deviation as it caused too. So this will be construed to 28 point 34 So we can around this value too. So we'll get the signal value, which will be the standard divisional because to 28. So this this is the answer for the given question that is that mean is 2 59 and the standard deviation is tough to 28.

So in this question, we are told that a population has mean 128 and standard deviation 22. And first we're asked to find the mean and standard deviation of the sample mean X, so the mean Of the sample mean, it's just the mean of the population, that's 1:28. And the standard deviation is basically the population standard deviation divided by the square root of 36, so that's approximately 3.67. Now, we are asked to find the probability that the mean of a sample of size 36, so we have our Mean and standard deviation of the sample, the rest from the probability that it will be within 10 units of the population means that is between 1 18 and 1 38. So we convert that to our standard normal random variable, so we get Between -2.72 And 2.72. And that basically gives us .9967 -1033, And the probability is .9934.


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