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Question 5 (1 point) A student obtains an unknown indicator which is colourless in neutral water: When placed in a 0.1 M solution of HCI or NHACl, the indicator rem...

Question

Question 5 (1 point) A student obtains an unknown indicator which is colourless in neutral water: When placed in a 0.1 M solution of HCI or NHACl, the indicator remains colourless: When placed in 0.1 M solution of NaNOz, the indicator turns blue: What is the approximate pKa of the indicator?13.0 - 14.05.0 - 6.08.0 - 9.02.0-4.0

Question 5 (1 point) A student obtains an unknown indicator which is colourless in neutral water: When placed in a 0.1 M solution of HCI or NHACl, the indicator remains colourless: When placed in 0.1 M solution of NaNOz, the indicator turns blue: What is the approximate pKa of the indicator? 13.0 - 14.0 5.0 - 6.0 8.0 - 9.0 2.0-4.0



Answers

Methyl red has a pKa of 5.0 and is red in its acid form and yellow
in its basic form. If several drops of this indicator are placed in a
25.0-mL sample of 0.100 M HCl, what color does the solution
appear? If 0.100 M NaOH is slowly added to the HCl sample, in
what pH range will the indicator change color?

Hi. Today I'll be walking you through problem three. So the information that you are given is that you start off with 20 milliliters of the week based methanol me which you then tie trade with one Moeller strong acid hcl. You are also told that the weak base can only accept one proton. Your objective is to find a more clarity of the week base. So given this information, you know that the equation that you can use is m one V one is equal to end to be to or similarity times. The volume of the acid is equal to the polarity times the volume of the base. Essentially, what you're doing is you're setting the moles of the acid equal to the moles of the base. And this comes from the equation for Mullah charity. Over here, if you multiply the volume over the other side, you can see that moles is equal to the polarity Times leaders, which is how we get this equation over here. So you can start by plugging what the problem already tells you. You know that the polarity of the acid is one Moeller, so you can plug that in right here. You're also given the volume of the base and so back in the input right here. However, we still have two variables and so you can look at the graph that is provided that I conveniently drew for you and see that the volume of a CEO added Athey. Equivalence point is approximately 15 millimeters and that can be input right there. The reason you use thumb volume at the equivalence of point is because at the equivalence point, the moans of the acid is equal to the most of the base, which is what validates this equation. And so now that you have only one variable left, which is the polarity of the week base, you can divide 20 millimeters over, and you will find that once you saw you're left with a malaria T equal to 0.75 Moore's per meter making answer be true. Thank you for watching, and I hope this out

In order to determine wth e concentration. The easiest way to do this is to look at the equivalence point, right? So we know that at the equivalence point, the moles of acid equal the moles of base. Right now for this particular reaction, it is a 1 to 1 ratio of acid to base, so we won't have to worry about any mole ratio. Specifically, we can just do a 1 to 1 calculation right now. We know on the HCL side, when we look at that hydrochloric acid that the polarity is one Moeller and that it's 15 millilitres, so you can keep that as 15 middle letters if you want to, or you can change it to leaders. Doesn't matter as long as you're consistent in the problem. All right. We're trying to determine the polarity of our base Guys, I'm just gonna put the polarity of the base there. And what we can see from the graph is that at the Colin's point, it takes 20 milliliters of base to reach that equivalence point. Right? So we're getting that 20 milliliters from the graph because that's where the graphics most upright, that's the equivalence point, right? So when we do the math here, right, Um, one times 15 divided by the 20 milliliters. Gives us a molar ity of 200.75 Moeller. Um, C h three N h two.

Okay, So the question is asking for the p k B of methadone army, and what you want to use is this zone right here, because you know that this is the buffer. Because the fluctuation in the pH is so small and this value is approximately, I would say 10.5. So we use his buffer region, right? And this formula associated with the buffer region to solve for the peak eight a. The acid, he can't ask it of metal. I mean, and what will fit we'll find out, is by plugging in all the numbers 10.5 from the graph and 10 from the X axis right here, we can figure out that the peak A of metal Amin is around 10.5. This means that if you and P k must p k b or the the ph of the asset versus the ph of the base, you'll have to get 14. And if you do, ah, little subtraction. Here you'll get 3.5, which is exactly the answer you want


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