5

5 e*(2-e)& A3-292 e+3D) 291-2...

Question

5 e*(2-e)& A3-292 e+3D) 291-2

5 e*(2-e)& A3-2 92 e+3 D) 2 91-2



Answers

$$ \frac{1}{9^{-5 / 2}} $$

Want to find where these two lines intersect and we have three X. Looking -2. Why let's get that raised minus two. Y. Is equal to five. And we have five X plus two. Y. Is equal to three. Now we could grab them and find where they intersect but oh my goodness! Look adding them as a linear combination is going to be great because these wise will drop out. So three X plus five X. Is eight X. Please drop out. 85 plus three is eight. Holy moly divide by eight. We get access one. How convenient. And now let's plug it back into it. Doesn't matter which equation. Let's plug it back into this first one. So we get three minus two. Y. Is equal to five. So negative two. Y. is equal to and subtracting three from both sides, likely end up getting to so why is equal to negative one? So our point of intersection should be the 10.0.1 negative one. And let's just double check If I plug one back in here and negative one in there. I get three minus negative two and yep that's five. So that works. I plug one in here, I'll get five and then plug negative one in there. I'm gonna get plus negative two and that equals three. So this checks in both equations

The neighbors. This nature convertible metrics says. If the determinant A you go to zero and eight and 19 vertical first, let's take the determinant of this matrix convertible. So if you do reduction to find determining into matrix, you could see that it's not increase zero. That implies a irritable now to find actual interested in a We used the algorithm where you have this set appear. He had the nature to a It's separated. You have identity matrix. So if identity major for two by two now, let's just produce decide Instead, identity matrix in this side here will turn into a dangerous you do reduction. You get 41 when the road is always during going before my flight Before then you scale the first row to get 11 of the 41 before No, you can divide the second room by veritable force multiplied. I wrote to you even wrote here time for 31. When you do that, you get 111 when I'm here. It was before and now we can cancel this issue here by north applying. I wrote to you by minus one before and then adding to brew one. Now we have to decide identity matrix and decide becomes in verses matrix here

Okay, so I want to replace tea with three. So when I replaced TV three, I'm gonna write three in parentheses and then still raise that three to the fourth power. Now, according to the order of operations, I'm gonna first evaluate parentheses. But technically, I just have a three inside the parentheses. So I'm done. Then my expert and someone do three to the fourth power first. So I'm just gonna write that and expanded form. This is just three times itself another three times, for a total of four times. When I evaluate what's inside of the parentheses, three times three is nine times, three times three is another nine. So this will end up being 81 the parentheses, and then six times 81 is 486 as my final answer.

So if the fraction two nights and we want to turn it into a percent the way you go from a fraction to a percent is you do numerator divided by denominator times 100. So we're going to do two divided by nine gonna have to add a decimal point and a zero. So what we're gonna do is we're just going to keep the adding zeros and bringing them down until we end up with no remainder. Now, what we can notice is, no matter what we dio, we are always gonna end up with the remainder of two s. Oh, this is going to be a decimal that's repeating. It continues on so we can go ahead and stop right here the way we multiply by 100. Technically, as we move our decimal 1000.2 places to the right. So that way we can see that two nights is equal to 22 and too tense percent


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