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Empirical Forms ionic formula of ionic compound? compoundelement #1element #2name of ionic compoundbariumiodineyesiodinecesiumyescesiumcalciumyesbariumoxygenyes 0 n...

Question

Empirical Forms ionic formula of ionic compound? compoundelement #1element #2name of ionic compoundbariumiodineyesiodinecesiumyescesiumcalciumyesbariumoxygenyes 0 no

empirical Forms ionic formula of ionic compound? compound element #1 element #2 name of ionic compound barium iodine yes iodine cesium yes cesium calcium yes barium oxygen yes 0 no



Answers

When barium metal is heated in chlorine gas, a binary compound forms that consists of 65.95$\%$ Ba and 34.05$\%$ Cl by mass. Calculate the empirical formula of the compound.

When talking about whether compound is Ionic. So looking at beryllium all right, as an example, if we were to put this compound into water, it should disassociate. In other words, it should become beryllium two plus ions and fluoride minus ions, which would be a Chris ions. However, in this case, the compound does not do this, which would indicate, but it is not.

So the way that we would determine if B e. C l two or um brilliant chloride would form an Ionic compound is we would heat it up to its melting point so that it can be in its molten state, its molten state. We would see if the compound conducts electricity, and we would do this by setting up a circuit. And since ionic compounds usually conduct electricity in the molten state, if the B E seal to conducts electricity, it is Ionic, and if not, it is Kobe lit.

This question is asking, What is the formula for a new I on a compound containing burying bromide Eso, the barium ion has a charge of plus two, whereas the brew mean ion has a charge of negative one. So that means that the there are two roaming ions required to balance the charge of a single barium ion. Um so the compound for from the ions of these two elements is called barium bromide. It'll have the Formula B A B R two.

To determine the formula for the Ionic compound formed between these pair of elements, we need to know the charge that each element typically takes on when it forms an ionic compound. Typically, aluminum is three plus, and oxygen is two minus. Therefore, we need to aluminum's to give us a total of six plus and three oxygen's to give us a total of six minus. So we have a neutral compound. Beryllium is typically two plus. Iodine is one minus, so we need to. Iodide is for everyone. Beryllium calcium is two plus sulphur is two minus, so we need one of each of them CS and calcium is to typically two plus iodine one minus. So we need to iodine per calcium. See eye to


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