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Interpret the p-value_The p-value (Round to three decimal places a5 needed )...

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Interpret the p-value_The p-value (Round to three decimal places a5 needed )

Interpret the p-value_ The p-value (Round to three decimal places a5 needed )



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Pertain to P-values for a one-mean t-test. For each exercise, do the following tasks. a. Use Table IV in Appendix A to estimate the P-value. b. Based on your estimate in part (a), state at which significance levels the null hypothesis can be rejected, at which significance levels it cannot be rejected, and at which significance levels it is not possible to decide. Left-tailed test, $n=10,$ and $t=-3.381$

Now. This time my zip statistic is minus 1.55 minus 1.55 This is my Zed statistic, my Z statistic and my Alfa level A 0.5 My Alfa is 0.5 So now what I want to do is I want to find the p value for my set statistic and I use a P value calculated for that. This is a one tailed test. Since this is left tail and I get my P value of 0.606 my P value is 0.606 And since my P values greater than my Alfa, I failed to reject minor hypothesis. I fail to reject my it's not This would be my answer.

We're going to be a left hailed hypothesis test for population meaning you With sample size and equals 30 and output a T statistic -1.572. Given this information as input, We want to answer the following two questions first. We want to use a tea table to find the p value associated with this test statistic T. Using a tea table. We see that the T interval for the greer freedom and minus one equals 29. Is that negative? 1.699 is less than T. Is less negative 1.311 From the tea table. This map directly onto a P value of .05 is less than P is less than .1 for a one tailed test. Next we want to answer what significance levels we can and can't reject the null hypothesis. Asian art. Remember that we can reject H not whenever people listening to alpha. So from RP interval we have that we can reject whenever alpha is greater than equal 2.1. And we failed to reject when alpha is less than .05 In between .05.1, we can't be sure whether or not we reject the failed to reject the tea table does not provide as precise measurement as we would be able to answer that question with.

Okay, We have sampled E and simple are the sample size for eight ISS and off a peacoats here to 50 x off e iss 15 and symbols myself are because to 75 x o. R is 25 so we can calculate p e prying which iss XP go burke and be when he was 15/2. 50 and we have barrel point. There are six. So q e prime iss there a point, not knife or, um P r prime isjust x are over and are which is 25 over to 75 and we have there a point. Narrow what on their online at once. All right. Eso the cute of our prime. Is there a point? Well, I Darryl my Okay, um, let's calculate the pool the proportion which is pp prime PP prime mystical two x off e plus X off our over an a plus and are and we have there a point there. 076 and Q p prime is just one Linus PP prime. When we have there a 0.9 to 4 here. Okay, so let's calculate that that star. So that star is equal. Teoh p e prime Linus, he our prime over square root wolf pp prime times, Q p prime times one over and a plus one over and are. And we have the number to be negative 1.333 Um, our hypothesis is she a smaller than p r. So it is equivalent to say P e minus p are smaller than narrow. All right, so we're going to calculate the people you people who is a probability such that a random vera bows that which is following standard normal distribution on a narrow one. Um, this random, durable ISS smaller than our test statistic, Which is that star, um, here. Why it is smother than because in our hypothesis, it it is stating that we want to know, like the hypothesis is p e smaller than p R, which is B minus. The difference is smarter than there are so here were used smaller than all right, um and this probability is equal to probability off that smaller than negative 1.333 This is just our Is that our Sorry that star and ah, still, that here is just a random bearable Can't the probability iss their own point there are lie to So this number is our p value for those hypothesis

Now, this is question number nine from the textbook. Over here. We have a diagram. Okay, We have a t I displayed on the left hand side, and we're going to use this display to answer all the questions we have to make. Remember that we are using the 0.5 significance level. Now. What is going to be Arnell? An alternative hypothesis. We are using the data to test the claim that they form a population having a mean less than 4.0 MVPs. Mean is less than four point zero MVPs M. B. P s. This is what we're testing. So this becomes our alternative hypothesis, right? So what is going to be our null hypothesis? Arnel hypothesis ends up becoming mu greater than equal to 4.0 MVPs, 4.0 MVPs. Okay, what is Artie statistic from the diagram, we can see that Artie statistic is minus zero point minus 0.366 And what is the P value? The P value that is given to us in the diagram is 0.3579 0.3579 Okay. What was the significance level? What was Alfa, it was 0.5 Okay, this was our Alfa for analysis. Okay, So using this Alfa, we see that our P value is much greater than Alfa. So we fail to reject our null hypothesis. This is our null hypothesis. So we fail to reject it, right? So we say that we fail to reject Anil hypothesis and that there is not sufficient evidence to support the claim that the Sprint Airport data speeds are from a population having a mean less than four MBPs. Right? So we failed to reject h not we fail to reject h not and again in words. We will say that there is not sufficient evidence to support the claim that the Sprint Airport data speeds are from population having a mean less than 4.0 MVPs and these would be my answers.


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