So let's think of a simple reaction where we have some reactant are gonna be broken down into two products. Product one and product too. Now, what we know about this reaction is it has a positive and full P value. Delta H is positive. This positive entropy value tells us that this reaction is endo thermic and we know that it's Endo thermic. In order for this reaction to occur, he must be absorbed. It must be introduced to the system in order for this to occur. So if we have a positive Delta H and we know it is Endo thermic, we know this reaction absorbs heat. So say we have the reverse reaction. We have the same two products being combined together to form the original reactant. Now, if we think about it, the reverse reaction is gonna have the opposite sign and magnitude of the previous simple P. So this Delta H here is going to be negative, right? Because we know going this way, he must be absorbed, but going the opposite way. We know that it's going to give off heat, and if it's giving off, he it's exile. Thermic and its ample p will be negative. Now the value will also be the opposite. No, I'm sorry. The sign will be the opposite, but the value will be the same. For example, if you have the Delta h of one problem say is 100 killer jewels and then you dio the reverse reaction. The Delta H will be negative. 100 killer jewels. You see, we keep the same value. It's the same amount of heat given or absorb. What changes is the sign. And this is true if you start with a reaction that gives off, he has a negative entropy. If you do the birth, it's going to absorb heat this time. So we know when we reverse reaction. Were always flipping the sign. So let's consider the temple p when we have 5.35 moles of CO two reacting with magnesium oxide. So in this case, we're doing the reverse reaction that we see up here because we're combining the two products here to get the original reactive. So we know that we have to change the sign of the M pulpy. And if we think about it, the info p here, which would be negative 117 0.3 Killah jewels is written for one wall. And if we want to multiply by the 5.35 Moles of CO two that we have because we know that since everything's bounced, if we have 5.35 moles of CO two will have the same number of moles of the magnesium oxide and as well as the magnesium carbonate. Here we dio a simple multiplication to cancel moles and we get negative 627 0.56 killing jewels. And so this is the end puppy of the reverse reaction when we are given a set number of moles. Now, if we're given some mass value instead, we have to do the exact same thing. We have to dio one quick conversion first because we have the reaction right now and that's given for one mole. But here were given a mass value. So we did have to convert this massive co 22 moles. And we know that all we have to do is divide by the molar mass. So we have 44.1 grams per mole of co two. This is grams that cancels and we're left with 0.807 moles of C 02 And now we're gonna do the same thing as we did before. We have our temple p of the reverse reaction, which is equal to 117.3. And this is killer jewels, Permal. And then we have a Moeller value to cancel out with. So we have to point e 07 moles. These cancel out and our final entropy is negative. 94.62 killing jewels.