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Shown the graph of force function (in newtons) that increases its maximum value and then remains constant Hor much work W done by the force in moving an object . di...

Question

Shown the graph of force function (in newtons) that increases its maximum value and then remains constant Hor much work W done by the force in moving an object . distance of 32 m?F(N)x(m)

Shown the graph of force function (in newtons) that increases its maximum value and then remains constant Hor much work W done by the force in moving an object . distance of 32 m? F(N) x(m)



Answers

Shown is the graph of a force function (in newtons) that increases to its maximum value and then remains constant. How much work is done by the force in moving an object a distance of 8 m?

If we want to find how much work is being done here, the first thing we would need to do is just integrate our force function from A to B so normally would have, like mass times acceleration. But in this case, since they just give us the force diagram already, or the force the graph of the forest function, we can just go ahead and integrate this directly. So what this is really saying is, Well, what is all of this area right here? And you might notice that we have a trapezoid here, and so this is going to be the area of base one plus base, too, over two times our height. So base one is going to be from here to here. So that's the base one. And that's just eight minus zero. So it looks like it's eight. Base two is going to be from here to here, which goes from 84 So that's just for and then our height is just going to be from the first base to the second base, which goes from 0 to 30. So H is 30. So we just come over here and plug all those in now, it would be eight plus 4/2 times 30. Uh, So that would be 12/2, which is six. And then six times 30 is 180. Add the units for work. Since we have everything in terms of kilograms and meters. Yeah, so then this here should be in jewels. So this is how much work would be done.

If we want to find how much work is being done here, the first thing we would need to do is just integrate our force function from A to B so normally would have, like mass times acceleration. But in this case, since they just give us the force diagram already, or the force the graph of the forest function, we can just go ahead and integrate this directly. So what this is really saying is, Well, what is all of this area right here? And you might notice that we have a trapezoid here, and so this is going to be the area of base one plus base, too, over two times our height. So base one is going to be from here to here. So that's the base one. And that's just eight minus zero. So it looks like it's eight. Base two is going to be from here to here, which goes from 84 So that's just for and then our height is just going to be from the first base to the second base, which goes from 0 to 30. So H is 30. So we just come over here and plug all those in now, it would be eight plus 4/2 times 30. Uh, So that would be 12/2, which is six. And then six times 30 is 180. Add the units for work. Since we have everything in terms of kilograms and meters. Yeah, so then this here should be in jewels. So this is how much work would be done.

In this example, we have a figure of a force and distance graph where a particle starts at zero meters and travels to eight meters were assigned to find the work done from 0 to 8 meters, and work is going to equal to the area under the curve or, in other words, the integral of this graph. So simply we can take the area that this particle has traveled and add that to shapes together so we can find the first area that triangle and second the area of the rectangle. So, first we will find the area of the triangle which is 1/2 base times the height 1/2 4 meters times the force of 30 Newtons. And we will add this to the area of the rectangle which is base times, height or four times 30 which equals 180. And the unit is Jules

If we want to find how much work is being done here, the first thing we would need to do is just integrate our force function from A to B so normally would have, like mass times acceleration. But in this case, since they just give us the force diagram already, or the force the graph of the forest function, we can just go ahead and integrate this directly. So what this is really saying is, Well, what is all of this area right here? And you might notice that we have a trapezoid here, and so this is going to be the area of base one plus base, too, over two times our height. So base one is going to be from here to here. So that's the base one. And that's just eight minus zero. So it looks like it's eight. Base two is going to be from here to here, which goes from 84 So that's just for and then our height is just going to be from the first base to the second base, which goes from 0 to 30. So H is 30. So we just come over here and plug all those in now, it would be eight plus 4/2 times 30. Uh, So that would be 12/2, which is six. And then six times 30 is 180. Add the units for work. Since we have everything in terms of kilograms and meters. Yeah, so then this here should be in jewels. So this is how much work would be done.


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