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(rspoben Chapter 2 1 1 1 (znabenneuajc00 Homework 1 Next Protlem chapler loum Wdx Set: 1 01 Problem 26 SyldyF(z,u) = KemetAaneaed exc Cnte U Hl 1 5 Ino Ft MlndetQu ...

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(rspoben Chapter 2 1 1 1 (znabenneuajc00 Homework 1 Next Protlem chapler loum Wdx Set: 1 01 Problem 26 SyldyF(z,u) = KemetAaneaed exc Cnte U Hl 1 5 Ino Ft MlndetQu jrL13 3

(rspoben Chapter 2 1 1 1 (znabenneuajc00 Homework 1 Next Protlem chapler loum Wdx Set: 1 01 Problem 26 Syldy F(z,u) = KemetAaneaed exc Cnte U Hl 1 5 Ino Ft MlndetQu jrL 1 3 3



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Exercises $1-12$ are review exercises. To solve these problems, you will need to utilize the formulas listed at the beginning of this section. Find the distance between the points $(-5,-6)$ and $(3,-1)$

Mhm. Okay. So to solve this problem, we're going to have to use the law of co signs. So over here I have my baseball diamond and I'm going to go ahead and label what I do know in this picture. So I know that each of the square or each of the sides of the square, 90 ft. Go ahead and mark those can grew in. And then I also know the distance from home plate to the pitcher's mound is 60. Wait five ft. Now, what I'm looking for is the distance from the pitcher's mound to first base. Now, because this is a square, we know each of the angles is 90 degrees. So if I'm cutting that 90.5, I know that the single down here is 45 degrees. So I now have enough information to go ahead and solve for this side. I'm going to go ahead and call this side A. Using this formula because that's the side I'm trying to find and I have angle A. Already which is 45. So I'm gonna go ahead and plug these two numbers in for B and C. So I have a squared which I don't know equals B squared 90 squared plus C squared 60.5 squared minus two times 90. I'm 60.5 co sign of A. Which is 45. Now in your calculator you need to make sure that you are in degree mode. But you can go ahead and type this whole side in and if you type that in you should get a squared equals 4000 and 59.86 Um But remember the is still squared here. So to get A you have to take the square root of both sides which will leave you with 63.72 ft. Yeah.

Okay, so for this problem, we're going to have to use the law of co signs, which I have written this formula over here. And I have also drawn the diagram, so we know that each of the feet are sorry, each of the sides of the square or the diamond are 60 ft. These are all congruent and the distance from home plate to the pitcher's mound is 46 ft because it's a square. We also know that all of the angles are right angles, which means if I cut this in half, this is going to be 45 degrees. So that should give me enough information to find this side right here, which is the distance from the pitcher's mound to first base. My call outside A. Because I have angle A. Which is 45 and 60 ft, I'm gonna go ahead and label with B and 46 ft at sea. So I have a squared, which I don't know equals B squared, 60 squared A. C squared 46 squared minus two times 60 times 46 co sign of A. Which is 45. Now, you need to make sure that you are in degree mode for this problem and your calculator and not radiant mode or else your answer will come out incorrect and I had 60 squared it was 46 squared minus two times 60 times 46 co sign of 45 in my calculator. And that gives me for a squared 1812. Wait 77 I can and I'm gonna go ahead and take the square root of both sides to get A. And that gives me 42 0.588

In this problem for being asked to determine if 16 is a solution to the given equation. Now, remember, it will be a solution to the equation if we substitute 16 in place of X, and it then creates a true statement. So we're going to start by substituting 16 in place of X. So we're gonna have a negative one. How is equal to 1/6? Minus two thirds now. The left hand side is all set because it's just a number. We have to simplify the right hand side. Well, looks like we're subtracting two fractions, which means we need a common denominator, which in this case is six. So we need to multiply the numerator and denominator by two. So this will leave us with 1/6 minus 4/6. Well, 16 minus 46 is negative 36 And if we produce negative 3/6, that's going to give us negative one half. So as you could see, it created the true statement. So because this is true, that means 16 is the solution to this equation. So it is a solution

Um, so we want to be using this table part A What? Values of axes. Why equal one? Um, that would be X equals negative one and X equals four. Then we have, ah y equals three. That there is no value in the table such that y equals three. Um For what value of why is X equal to three? That would be negative one for what value of X is why less than or equal to zero. That would be, um, zero, three and five. And then, lastly, the minimum and maximum values, um of why would be nine would be the maximum and the minimum would be negative, too. And that occurs at X equal six and AKI X equals zero, respectively.


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