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The value of R is 1.8The value of Vz is 4.1The value ofis 2.2Find the value of v4 to three significant figuresAnswer:...

Question

The value of R is 1.8The value of Vz is 4.1The value ofis 2.2Find the value of v4 to three significant figuresAnswer:

The value of R is 1.8 The value of Vz is 4.1 The value of is 2.2 Find the value of v4 to three significant figures Answer:



Answers

If ${ }^{18} C_{r}={ }^{18} C_{r+2}$, then find the value of $r$.

Okay, Does if three artists equal to eighteen, what is the value of six R plus three? Well, here's three are is eighteen, so they multiply. Both sides of this equation by two will get six r is you go to thirty six, then we have the six are component. So then we can plug this thirty six right into this equation and say, thirty six plus three. And that's thirty nine to the value of six R plus three is thirty nine.

Okay, so we went to simplified the following expression here. So it's plug in our our value. So it's three times are, which is 17 27 all over 11. So it's three times 17 minus 11. That's equal to a 40. So we got 40 over 11 so we can't simplified us any further. So does here is our solution.

Hi in the given problem, there are three resistors and all of the three resistors are in a series combination along with a battery which is providing an E. N. F. Of 70.0 volt. The current passing through this city's combination is I is equal to 4.85 and Pierre the first resistor having a resistance Arvin which is missing. We have to find it. The second one is having a value are two is equal to 8.25 home the third one artery again missing here. The potential drop, the voltage drop across the first one. We won is given to be 13 point fine fold that across the second one means we do that is missing and a gross artery. This is a game given to us which is having a value 33 is equal to 16 5 volt. Now we have to find the unknown values here. And the concept used here will be the current remains the same in series and using arms law for this value of our Van Darwin will be given by we won by I for even this is 13.5 bold. The current. Well the same across all these 34.85 ampere. So finally this Arvin comes out to be two point 78 oh. Now for this way to again using the same Homes law. We too will be given by I into our two again having the same current through 84.85 NPR multiplied by art which is having a value of 8.25 oh. So here this we too comes out to be 40 world 40.0 volt. And at last this artery using same home slope will be given by we three divided by same current. I. So here it will be 16.5 divided by 4.85 16.5 World divided by 4.85 ampere. So again, this artery will have a value of three point for Seattle. Oh, so all these three here are the answers for the same given problem. Thank you.

All right in this problem, we're being asked to evaluate the given expression when ours too. So let's start by simplifying our expression. We'll remember negative are to the third Power needs to multiply negative are by itself three times. So we're gonna have nine times negative, two times negative are times negative are times negative are. So let's figure out the sign of our expression or of a simplified answer while 1234 terms are negative, which means the result will be positive. Now we just have to multiply nine times to which is 18. And then we have our times are times are, which is our to the third. Now that we've simplified, we simply need to substitute to in place of our. So when we do this, we're gonna have 18 times two to the third power will remember to to the third power means two times two times two, which is equal to eight in 18 times eight is just 144. So the answer to this pot problem is positive. 144


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