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QUESTION 13Copy of For the Decay 121 Sn 121 Sn+ Y 121Sn" (I" = 9 2121 Sn (I" = 5 2The possible values of (/ ) for the gamma photon are:OA 3, 5 and 7 ...

Question

QUESTION 13Copy of For the Decay 121 Sn 121 Sn+ Y 121Sn" (I" = 9 2121 Sn (I" = 5 2The possible values of (/ ) for the gamma photon are:OA 3, 5 and 7 B.2, 4 and 6C.2 only 0.2,3,4,5,6 and 7

QUESTION 13 Copy of For the Decay 121 Sn 121 Sn+ Y 121Sn" (I" = 9 2 121 Sn (I" = 5 2 The possible values of (/ ) for the gamma photon are: OA 3, 5 and 7 B.2, 4 and 6 C.2 only 0.2,3,4,5,6 and 7



Answers

Questions 1–3 (A) Alpha decay (B) Beta decay (C) Gamma ray (D) Fission (E) Fusion Select the term from above that identifies the nuclear reactions described in questions 1 to 3. $_{92}^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow_{38}^{90} \mathrm{Sr}$ $+\frac{143}{54} \mathrm{Xe}+3 \mathrm{n}+$ Energy

So in this problem, the atomic number that is also the number off protons increases from 83 to 84 now. For this to happen, a neutron must eject a big a particle that is an electron and become a proton. So if the system nugent, it must eject a beta particle, which is an electron in order to become drop down. Now the overall mass off the atom remains virtually unchanged because the months off the ejected electron is very small. So for this reason since this is nearly equal to zero, the mass of the electron is negligible, therefore ah, and the massive neutral is nearly gold to the massive proton. Therefore, the overall months off the atom women's virtually unchanged before and after the reaction on hence of the atomic mass remains so unchanged on duh. So the light answers Oh, are the right reaction Corresponding to this problem is B because we're getting a beat. A ticket in this problem. Thank you

So the answer to this problem is going to be option A. That is an Alfa decayed on. I'm going to explain. Why is that so? Basically an alpha particle Is the nucleus off a Sheila Martin? That is, Did not it as this. Now, when two protons and two nutrients are released from Tori um 27. So from this two protons until Nugent's are released on dhe, we get a resulting isotope off J D a 2 23 No. Okay, let me just lighted the correct way to 23 on This is I told you to 21 Mar adding together the atomic numbers off helium on DDE ready and 2 23 as well as adding together the atomic masses. The drivel fought in 2 27 So if you add the atomic masses and a comic numbers off Celia Andre, don't radio. Then you'll be able to get the atomic number and atomic masses off Valium. Therefore, we can say that the whole process is on Alfa Dick. It because that is a decayed off on as a particle mentor, IAM goes to stadia

The given question is from the topic nuclear fission fusion in this question is asked that which of the following is giving you alpha beta decay positron emission organization. So it's all this question must have a fundamental idea about what these particles are. So as we known, alpha particle are nothing but helium 24 beta particles are nothing. Bert Beta 0 -1 and positron decay is nothing but zero plus one and gamma decay is nothing but gamma 00 So if you know these particles solving questions would be easy. So solving question would be there is if you're aware of these questions, these concepts of alpha particles were of articles, government positron. So now now as we know the particles let us start solving the questions. So first question says and question one, the question says, Caroni um is an element which is 90 and 94 2 40 undergoes an emission to form uranium 92 2 36 to give us something which is helium 24 So this grey looks like alpha particles. Therefore this question, what is released? How far particularly pleased because alpha particle has mass number two and number two in mass number four question be says Irene 53 1 31 decomposes to give us Irene 53 1 31. And along with that we get a goddamn particle, This is God particle. Therefore it gives you a gamma DK C option, says sodium 11 22 undergoes decomposition to become sick, neon L 10 22. Along with that we get E zero plus one. Therefore, it clearly is an indication of post Ron DK taking place. Therefore, the answer, the following questions are alfa decay, gamma decay and positive on decade depending on uh what kind of particle was ejected. So, these are the answers to this question. These are the answers to this question. So basically the concept here is uh, what alphabetical means, what beta particle means and what God particle means. So depending on their configuration, like helium is to for him to forest alpha, zero man is going to be done. Zero plus one is positron and 00 is comma. So this is how we can solve this question.

Problem two in this problem a nuclear The extent is given here one uranium nucleus is when attacked by a neutron that is moving a neutron. So nuclear uh this nucleus of uranium breaks into two smaller nuclei of Mhm Stransky, um and zen in and apart from these two daughter nuclear, three Neutrons, an enormous amount of energy is also released. So this is called parent nuclear and these two are called daughter nuclear. As we can observe here that The daughter nuclear has atomic masses 90 and 143, which is less than the atomic mass of parent nuclear. So it means that one heavier nuclear is broken, one heavier nuclear is broken into to lighter nuclear. And this process is known as fizzing process. While when two lighter nuclear is combined to form a heavier nuclei, that process is called fusion process, refusing reaction. And this is freezing process. Mhm. So here, since one heavy nuclear is converted into two lighter nuclear. So answer for this problem will be freezing process. So this is our answer for problem number two.


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