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OB. Ho:HD * 0 (where HD = Ht H2)2)Data TableJ to twoExpert CC_ S.E_ EG B.I. CM_ C.N. GN_ RM Pv:Brand Brand B 26 : 1 27 26 22 28) two deconcludebout the3 distribulid...

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OB. Ho:HD * 0 (where HD = Ht H2)2)Data TableJ to twoExpert CC_ S.E_ EG B.I. CM_ C.N. GN_ RM Pv:Brand Brand B 26 : 1 27 26 22 28) two deconcludebout the3 distribulidistributPrintDone0 distribull

OB. Ho:HD * 0 (where HD = Ht H2) 2) Data Table J to two Expert CC_ S.E_ EG B.I. CM_ C.N. GN_ RM Pv: Brand Brand B 26 : 1 27 26 22 28 ) two de conclude bout the 3 distribuli distribut Print Done 0 distribull



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Calculate $E^{\circ}$ for the following cells: (a) $\mathrm{Pb}\left|\mathrm{PbSO}_{4} \| \mathrm{Pb}^{2+}\right| \mathrm{Pb}$ (b) $\mathrm{Pt}\left|\mathrm{Cl}_{2}\right| \mathrm{ClO}_{3}^{-} \| \mathrm{O}_{2}\left|\mathrm{H}_{2} \mathrm{O}\right| \mathrm{Pt}$ (c) $\mathrm{Pt}\left|\mathrm{OH}^{-}\right| \mathrm{O}_{2} \| \mathrm{ClO}_{3}^{-}, \mathrm{Cl}^{-} \mid \mathrm{Pt} \quad$ (basic medium)

Dark Hussein is white phosphorus and reaction with see A. We're told to ems we have wide fast for us. Yes. Yeah. Which will too So this upon reaction will give This will give p three less. Yeah, that's too you're too All too. So this is the product of this reaction. So let us set the options so we see option B and option here, correct and speaking rate of sin the and option the uh that answer.

So we were taking a look at a reaction. So we have al I in the acquis phase as an electron. So we're reducing a material here because we're adding an electron generates ally solid changing Gibbs Energy off next up to nine. 3.3. Killer jewels. Well, this is equal to negative and a just negative one. Mall 458 multiplied by the eternal value where we're solving for, you know, which is negative. 3.40 volts. So this value is the same as the one that is in all table that is provided to us. So these values are in good agreement with one another.

We have function. F r equals negative two R squared plus one. Let's use it to find some different F of our values with different inputs as seen here in the table. So we'll start with negative 1.7, giving us negative two times negative 1.7 squared plus one. Now, if you simplify this a little bit, I highly recommend a calculator for these multiplication. Then you'll end up with negative 5.78 plus one or negative 4.78 and that goes in the table. Next up is 0.9. So we'll have negative two times 0.9 squared and plus one. And when you multiply all of this out, you're going to end up with negative 1.62 plus one or negative 0.62 So that goes in the table negative 0.62 and our final number is 5.4. So we've got negative two times 5.4 squared plus one. All right, that's not so bad. Once again, use a calculator to multiply out the first term, and you will end up with negative 58.32 plus one And, of course, you just have to add in this one to get negative 57.3 to which goes in the table. So now we've figured out all of these values that go in the table, that is, we have multiplied them all out using the different values of our. So we're done with this problem?

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.


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