## Question

###### Show that $$\frac{d}{d x}\left(\cosh ^{-1} x\right)=\frac{1}{\sqrt{x^{2}-1}} \cdot \quad x>1$$

Show that $$\frac{d}{d x}\left(\cosh ^{-1} x\right)=\frac{1}{\sqrt{x^{2}-1}} \cdot \quad x>1$$

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