5

(0.Spts)Neatly show your work for the ratio of components and calculation of the percentage of product_Maximum size for new files 20.OOMBMaximum attachmentsDrag and...

Question

(0.Spts)Neatly show your work for the ratio of components and calculation of the percentage of product_Maximum size for new files 20.OOMBMaximum attachmentsDrag and drop a file or folder here or click(0.5pts) Is the reaciton complete?Choose.(0.Spts)D: If the reaction was not complete; how could the experiment be modified? How could the chemist have realized the reaction was not complete before working up the reaction?SavedNormalB | II 4 Ili 8 XE| IliXz | XI _E1=1=fx| 0/012T(0.Spts) E The chemist

(0.Spts) Neatly show your work for the ratio of components and calculation of the percentage of product_ Maximum size for new files 20.OOMB Maximum attachments Drag and drop a file or folder here or click (0.5pts) Is the reaciton complete? Choose. (0.Spts) D: If the reaction was not complete; how could the experiment be modified? How could the chemist have realized the reaction was not complete before working up the reaction? Saved Normal B | II 4 Ili 8 XE| Ili Xz | XI _ E1=1= fx| 0/012 T (0.Spts) E The chemist is now planning to oxidize



Answers

A chemical reaction in which reactants A and B form the product C is studied in the laboratory. The researcher carries out the reaction with differing relative amounts of reactants and measures the amount of product produced. Examine the given tabulated data from the experiment and answer the questions.
a. For which experiments is A the limiting reactant?
b. For which experiments is B the limiting reactant?
c. The molar mass of A is 50.0 g>mol, and the molar mass of B is 75.0 g>mol. What are the coefficients of A and B in the balanced chemical equation?
d. For each of the experiments in which A is the limiting reactant, calculate the mass of B remaining after the reaction has gone to completion. Use the molar masses and coefficients from part c.
e. The molar mass of C is 88.0 g>mol. What is the coefficient of
C in the balanced chemical equation?
f. Calculate an average percent yield for the reaction.

In problem toe. Explain how to create a maximum amount off product in a chemical reaction. So this question is taken from the topic mole ratio. So get the maximum amount off product. Maximum amount off products from a reaction reacted. Must be must be mixed in the correct proportions. A reactant must be mixed in a correct proportion. So basically toe get the maximum amount off product from our reaction they attend. Must be mixed in the correct proportion. So, for example, if we consider a reaction for example, if we consider a reaction in which copper sulfate at course, copper sulfate reacts with the echoes sodium hydroxide and it will produce. And it will produce copper hydroxide. Solid copper hydroxide along with sodium sell food that was Atco sodium sulfate. So in this reaction, uh, we see that these are the coefficient, so coefficient of copper sulfate is one and sodium hydroxide is two and the copper hydroxide it. This one and sodium sulfite it is, too, So the coefficient in the chemical equation indicates the proportions. The coefficients in a chemical equation, you know, chemical equation indicates the proportion in which are reluctance indicates the proportions in which substances reacts in which the substances reacts so in moles in terms, off mall or other counting unit in terms off small. So the coefficient in this particular equation indicate for everyone more law for copper sulfate. Two more of sodium hydroxide is required, so one mole off supercell food reacts with the two mole off. Reacts with the to maul off sodium hydroxide toe make maximum amount off products. Maximum amount off products product. So in short, we can say that the ratio is often referenced. The mole ratio that is the so using the ratio given by the balanced chemical equation produces the maximum Althoff product. So we can say that using the ratio given by the ratio given by the so using the ratio given by the look even by the balanced chemical equation produces balanced chemical equation produces produces the maximum amount off product produces the maximum amount off product. Maximum amount off products. Okay, I okay,

In problem toe How to create a maximum amount of products in a reaction. So to get the maximum amount off product maximum among off product from the reaction, the reactant must be mixed. The area tents must be mixed in the correct proportions in the correct proportions. So basically these documentary coefficient play important, very important role for for this case, for example, Cooper sell food when a react reacts with the any which so it will form copper hydroxide. And and then it was off for so in this case, So on balancing we get to an image, and now this is the balance equation. So basically, the coefficient in a chemical reaction indicate in the indicate that the proportion in which these substances react in a mold, enamels or other counting units. The confession in this particular equation indicate 30 for everyone mold for every one mole for every one mole off copper sulfate. Two more off any wage are required. Two more off any Ohh are required Adequate toe make maximum amount off product, so make maximum amount off product amount off product. So that means the test tube containing the most important, most important off solid correspond to this one ratio to off the reactant, so this ratio is often known as smaller ratio. So that means this copper sulfate and an image ratio in the form off one ratio to so This is also known as Moeller ratio. So using the racial given by the ballistic Asian so we can see that using the ratio given by the balanced chemical equation Balanced Chemical equation produces the maximum amount off product produces the maximum amount off product.

Problem. party. Yeah, concentration of a note has been huh? Four times times after four half lives. That is concentration of mm at the time. T calls to one x 2 to the power poured in order. That is equals to one x 16 mm. So. Mhm. We can see when it reaches one by 16. The initial concentration treason. The reaction had proceeded four of life. This answer for party. No. In part B. We need to draw a graph. Okay sure. So this is a graph. Okay. For a reaction. This slope The graph of concentration of a versus time is a very slow. You clearly see if the reaction takes six days to complete pour half lives. The half life is 1.5 days or 18 hours. Okay, Data taken from a period two hours or 0.008 days cover a very small portion of Curd and appeared linear. So this is a final answer. And this is a graph.

Going on with our kids and our kinds. What we have here is terminal al kind that can react where the strong base and it removes our proton, followed by an S and two reaction with missile bromide. So that looks as follows. Re agents are research on a in H two missile Pro Mai's to our product. Next we have one large catalyst that is selective so we can take pent to I then last catalyst on Now it's selective towards making the Six Al Keen next year I have the following starting material Adrover from the screen quickly. So here what we're taking as our re agents is lithium aluminum hydride called conditions. What we see is our chemical transformation from a key tone to an alcohol group next week. And take this material that was our alcohol group with conch H two s, 04 on heat. We have an elimination reaction where we form an hour keen. Next, we're taking a look at alcohol. Hey, lights that are able to undergo d hydrogenation in the presence off strong basis so we can have our starting material presence off E T bow and a e T o h, What we form is the following. We have an elimination reaction. Where have a base command? What? Take a proton collapse. Electoral entities, Former double bond, bro Means are leaving group. We form a double bond, which is one missile cyclo hex one in. Lastly, we have the material that we just used. Now what we're doing is reacting that with deuterium, which is an isotope off hydrogen d two, what we now has is exaggerated compound as our final material.


Similar Solved Questions

5 answers
The (m) and specific LV heat the N given difference 8 3 1 Calculate this in Jkgl el
The (m) and specific LV heat the N given difference 8 3 1 Calculate this in Jkgl el...
5 answers
Intro InstructionsNote:In the texc all questions Use 62.5 poundsrft? as the force perivolume density of Water; In metric; we would need Newronsimeter?_ The mass density per volume of water is1000 Ikgm? convert this Into; force densicy peri volume; we multiply by gravicy approximately 9.8 mys? Tne resulting quantity is the force density per volume in metric:` 9800 Nm3
Intro Instructions Note:In the texc all questions Use 62.5 poundsrft? as the force perivolume density of Water; In metric; we would need Newronsimeter?_ The mass density per volume of water is1000 Ikgm? convert this Into; force densicy peri volume; we multiply by gravicy approximately 9.8 mys? Tne r...
5 answers
KCI 2 Oz ALOj MgSO-, BaOz
KCI 2 Oz ALOj MgSO-, BaOz...
5 answers
Reacton lor it rto b Rate HN V2[01 ie pamal ordor wth raspeciIhaparal ordeteroegland ato d OnX}XTha olders cannolGtinednouchamical naction1;1
reacton lor it rto b Rate HN V2[01 ie pamal ordor wth raspeci Ihaparal ordet eroegl and ato d On X} X Tha olders cannol Gtinednou chamical naction 1;1...
5 answers
(d) Water of density 998 kg m' is moving with speed of 6 mls through pipe With cross_ sectional area of 0_ m?. The pipe gradually drops 15 m as fts cross-sectional area increases to 0.2 mWhat is the speed of the water at 15 m below the initial position?marks]4(d) (W) Answer:(ii) If the pressure at the initial upper level is 1Sx10-Pa; what is the pressure at 15 m below the initial position? [3 marks]4(d) (ii) Answer:
(d) Water of density 998 kg m' is moving with speed of 6 mls through pipe With cross_ sectional area of 0_ m?. The pipe gradually drops 15 m as fts cross-sectional area increases to 0.2 m What is the speed of the water at 15 m below the initial position? marks] 4(d) (W) Answer: (ii) If the pres...
5 answers
3(Opt) . Find an example of a function f o R that is continuous only at I = 3.Bonus (Spt) . Consider function f : R= R Using Def: 5.2.1and Thm 5.2.2 to prove that f is continuous if and only if for every open set U € R the preimage f-'(U) is open:
3(Opt) . Find an example of a function f o R that is continuous only at I = 3. Bonus (Spt) . Consider function f : R= R Using Def: 5.2.1and Thm 5.2.2 to prove that f is continuous if and only if for every open set U € R the preimage f-'(U) is open:...
5 answers
(30 Points): Solve ONE the following problems:Use the method of Variation of Parameters to find the gener solution of the following differential equationsFind the general solution of the non-homogenous differential equation given by y"+9y = Csc(3x)Find the general solution of the non-homogenous differential equation given by y"_4y=xe
(30 Points): Solve ONE the following problems: Use the method of Variation of Parameters to find the gener solution of the following differential equations Find the general solution of the non-homogenous differential equation given by y"+9y = Csc(3x) Find the general solution of the non-homogen...
5 answers
2. Calculate the radius of an aluminum wire in meters. It is 20.00 feet long and has resistance of 3(a) 1.2103 x 10 ' meters above(6) 1.4649 x 10 * meters(c) 2.1924x 10 4 melersnone of
2. Calculate the radius of an aluminum wire in meters. It is 20.00 feet long and has resistance of 3 (a) 1.2103 x 10 ' meters above (6) 1.4649 x 10 * meters (c) 2.1924x 10 4 melers none of...
5 answers
Electrons can move to higher energy levels when they (absorb/emit) energy.
Electrons can move to higher energy levels when they (absorb/emit) energy....
5 answers
(3 marks) Evaluatetan(z) In(cos(x))dz
(3 marks) Evaluate tan(z) In(cos(x))dz...
1 answers
Find the exact values of the sine, cosine, and tangent of the angle. $$\frac{11 \pi}{12}=\frac{3 \pi}{4}+\frac{\pi}{6}$$
Find the exact values of the sine, cosine, and tangent of the angle. $$\frac{11 \pi}{12}=\frac{3 \pi}{4}+\frac{\pi}{6}$$...
5 answers
A power shovel does work raising dirt to a height of 10m. If the power used is 1,000W, determine how much earth (in kilograms) can rise in half an hour.
A power shovel does work raising dirt to a height of 10m. If the power used is 1,000W, determine how much earth (in kilograms) can rise in half an hour....
4 answers
Question 21 ptsLet f(r) = 7-3 Which one of the following is the Taylor series for the function f?e 8 7n Un=0T n=1 enltnZn-0(7x)n=0
Question 2 1 pts Let f(r) = 7-3 Which one of the following is the Taylor series for the function f? e 8 7n Un=0 T n=1 enl tn Zn-0 (7x) n=0...
4 answers
1. A buffer solution is 0.437 Min HF and 0.363 Min KF. IfKa for HF is 7.2×10-4,what is the pH of this buffer solution?2. A buffer solution is 0.356 Min H2S and 0.327 M in NaHS. If Ka1 forH2S is 1.0x10^-7, what is the pH of this buffer solution?pH = _______3. A buffer solution is 0.317 Min NaHSO3 and 0.272 M in Na2SO3. IfKa for HSO3- is 6.4x10^-8, what is the pH of this buffersolution?pH = _______
1. A buffer solution is 0.437 M in HF and 0.363 M in KF. If Ka for HF is 7.2×10-4, what is the pH of this buffer solution? 2. A buffer solution is 0.356 M in H2S and 0.327 M in NaHS. If Ka1 for H2S is 1.0x10^-7, what is the pH of this buffer solution? pH = _______ 3. A buffer solution is 0.317 M...

-- 0.069471--