8 90.0 %C? tire 3.89 3.23atm ZI2am has Question 42 We atm a pressure of 2.34 atm 30.01 will be the pressure if the temperature increasad...

The pressure in an automobile tire is 1.88 atm at 25.0°C. What will be the pressure if the temperature increases to 37.0°C?

Okay, so this comes Your problem is dealing with gases and, more specifically, the relationship between temperature and pressure. So the problem states that we have a car tire, where in its initial condition, the temperature, the initial temperature is 25 degrees Celsius and the initial pressure is 1.88 atmospheres. Then in the final condition, the same tire. The temperature is 37 degrees Celsius, and we're trying to determine what the final pressure is as a result, So first up we can do to solve this is if we don't remember exactly what equation to do. A good fallback for me is to use the ideal gas law equation that's PV equals NRT very useful equation to memorize and we can consider. And this describes the relationship between the variables PD pressure, the volume and the number of moles of the gas are, which is a constant to describe it, the value to changes based on what units were using, and then t the temperature of the gas. And so this would this equation can describe what the gases like in the initial state, and then we can also use the equation again to represent what it looks like in the final state. This will be final status for the initial state. So what we can do is in order to simplify this more broad equation, to describe the gas into something that directly applies to our problem, where we're only dealing with temperature and pressure, we can determine that the number of moles, the constant and the volume are the same in the tire in under its initial condition, where the temperatures going 25 degrees Celsius and the final condition of the tempers 37 degrees Celsius. Because we based on the work problem that were given, there's no indication that the tire is punctured. So it's gaining or losing most of gas and no indication that it's changing ball. You getting bigger, smaller and then so knowing that thes units I circled in red are equal to each other, we can rearrange the equation into something that looks like this where we have Tom pressure. Initial over temperature initial is equal to the pressure finals over temperature final. So now what we can do is just plug and chug all of our, um, information we have from the problem into this equation. to solve for the final pressure. So we're plugging, trying. It'll look like 1.88 atmospheres over the initial temperature. 25 0 degree Celsius is equal to the final pressures on no so market with a big red X, um, over the temperature final of 37 degrees. That's Celsius. Just all these kinds of problems. I cross multiply. So we get. So then it rearranges the equation to look like this. Where that Psaltis zero and then using some outdoor on a calculator, we see that X rich again is equal to the final pressure is going to be two point 78 atmospheres, and that is our final answer.

Guys don't fight AIDS. The pressure in an auto movie tire. It's one front. It's well, I want it ate at most fair as 25 degree sensors 56 years. Well, I want to confront my temperature. So caving, because the way we're using gas law it, then creature as Toby is friends. You tell me. So you know what to sounded. Three compacted toe caving and 34 to 98. Okay, so I called his phone T One of the court is one people. What pressure? If the temperature in crystal lattice l now want a fine pressure. According to Peter, if the temperature is increased of practice, um, deep recesses that is so close to Santa. Three down B three underdone thing caving. So we see pressure and temperature. This is again to use. Begin the sack law because it's to relate to you for the pressure on temperature off the gas When volume on number molar Vika Constant. I have constant. So the formula is bur off our team while it caused Pete too tea too. I don't want to find Pete too. If I take this tea to buy with about 82 it's just I'm afraid it's one by Tipton I It's one. My teacher. So is that so Then how we are my feet too? Maybe even while Thio plans to to find houses P want knees 1.881 spare by T 1 to 98. And to do these three things different, different, safe. And the answer is Want point 9557 What must be done? I'm fine. Six out front spear.

From the given question. Initial pressure even is 3.74 atmosphere goes At initial treasure. Tyvon initial temperature t even is given as a 15°C 15°C convert into Calvin 15 plays 2 73 equals two 2 88 Calvin. We have to calculate the final pressure P two And the final temperature Tito is given as 35°C, 35 degrees Celsius convert into kelvin 35 plus 2 73 equals +23 noted Calvin as the volume remains constant. The relation between the temperature and pressure is according to the tax law, According to tax law. Even bite even is equal to P- two by T. two. Mhm. Stop shooting the values even is 3.74, divide by Tiffany's to 88. Kelvin is equal to P two by T. two is 3 noted Calvin. From this we can calculate the P two, P two is equal to 3.74 at most meals into three note 8 Kelvin divine by 288 Calvin kelvin kelvin canceled with each other 3.74 into three, not eight by 2 88 equals two, 3.99, which is close to four at hospitals. P two is equal to four. Atmos feels At 35°C, sir, the pressure. In the time it will be four atmosphere goes.

So we're going to use gave us tax law P one over T. One is equal to P. Two over T. To pressure and temperature are directly proportional. We're solving for the second pressure. So multiply both sides by T. Two and we'll get that. The second pressure P two is equal to P one times T two divided by T. One. Where the temperatures are in Calvin. So our initial pressure is 3.74 atmospheres. And then the second temperature is 35 C. We add to 73 and we get 308 Calvin. And then the first temperature is um 15°C or 288 can add to 73. And then we'll get our pressure. Yeah So 3.74 times 308 Divided by 2 88. Yet 3.999. Let's round to 4.00. So we can use three significant figures. That was fierce.