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7. Calculate the ionic strength for a solution made by mixing 100 mL of 0.4M HCIO4 with 150 mL of O.1M Cu(CI04)2? (2 Points)0.27Other0.340.260.280.320.33...

Question

7. Calculate the ionic strength for a solution made by mixing 100 mL of 0.4M HCIO4 with 150 mL of O.1M Cu(CI04)2? (2 Points)0.27Other0.340.260.280.320.33

7. Calculate the ionic strength for a solution made by mixing 100 mL of 0.4M HCIO4 with 150 mL of O.1M Cu(CI04)2? (2 Points) 0.27 Other 0.34 0.26 0.28 0.32 0.33



Answers

Shown here are two aqueous solutions containing various ions. The volume of each solution is 600 mL. (a) Write a net ionic equation for the reaction after the solutions are mixed. (b) Calculate the mass of the precipitates formed and the concentrations of the ions in the mixed solution. Treat each sphere as 0.0500 mol.

In this problem. Our goal is to convert these concentrations into units. Similarity. Um, and the way we do this is we want to change milligrams per leader into molds for leader. So the way we do this is first by multiplying factor to convert milligrams two grams and then by multiplying by the atomic mass of calcium, which is 40 0.1 grams per bowl. And this will give us for units. Cancel. We will get moles over leaders, and that is what we worked in that cube says 3.54 times, 10 to the negative, fourth more in calcium two plus. And this is also to 0.35 for Millet Moeller in calcium two plus. Next we have 32.8 milligrams of potassium in 100 milliliters. And again we want to convert two moles over leaders. So first we can convert our middle leaders, two leaders and then milligrams two grands, and then we can multiply by the molar mass of potassium again. And that is 39 0.1 grabs. And this will give us 8439 claims 10 to the negative third. Well, we're in potassium, which is equal to 8.39 No more fantastic. Lastly, we are looking at a solution with 225 micrograms of zinc ion her Millie. So first we can cover our mill leaders, two leaders and then our micrograms. Two grams microgram is one millionth of a gram and then by multiplying by Moller mess again. And this gives us a concentration of we pulled it for four times 10 the negative third bowler zinc islands, and that is equal to 3.4 for no more sink.

For part A. When these three Ionic solutions air mixed, we have sodium sulfates and as a chloride, too. And berry, um, sign aids. Um, which solutions will be precipitated out. So we will produce BSO four on zinc sign, eat and, uh, to in a c l A quiz. So, uh, that is balanced. Our precipitates would be B A s 04 and Zet n c n two for part B were asked, What is the morality of each iron assuming complete precipitation. So, assuming complete precipitation, we're going Thio have the total volume is 250 mill leaders from all three solutions N a two s 04 would associate to an A plus and s 04 to minus and we're told that similarity is 0.1 Moeller so sodium what you would point to Mueller and s 4.1 Mueller, we have 100 mL of the two s, l four. Um, we have zed n c l two todo zinc two plus to see off minus. And this is three Mohler's 0.3 Moeller and six Smolar and this is 50 mL and we also have B A, C N to be a two plus two CN minus. Went to Moller 3.2 Moeller four Moeller And this is also at 100 mL. So from here, we can solve for the morality of the S 04 to minus way that we have 0.1 Moeller and it will be 100 0 millimeters it per 250 mL. And this would be equal to 2.0 400 Moeller. The Moliere ity of the variants you plus will be 200 Moeller 100 mL, 2 50 mL Of the total volume of this or cow took 500.800 Mueller so okay, 0.400 Moeller be a two plus will react with 0.0 for points. Sorry, this should be 0.400 Moeller 400 Moeller s four to minus, um so there will be no s 04 to minus left in the resulting solution morality of be a two plus in the resulting solution is going to be put 0400 Moeller left over in excess. Let's look at the morality of the zinc two plus, which will be equal 2.300 Moeller, 50 mL, 2 50 mL Yes to this workout 0.600 Mueller and the polarity of a C minus is equal to 400 Mueller on 100 mL over 250 mL. This is equal 2.16 year old Mueller. So, UH, 0.600 Moeller Zed and two plus or react with points 0.1 to 0 Moeller CN minus So zinc two plus, um so So there will be no zinc two plus in the resulting solution, the morality of the sea ed minus in the resulting solution would be equal to point 16 by this 0.1 to 0 to be with the 0.400 Mueller and the morality of the In a plus, things does not precipitate. So this will be a 0.200 Mueller times 100 0 mL over the 2 50.0 mL. This is going to be equal to 0.800 Moeller and the polarity of the C L minus is equal to point. It's six Moeller 50 mL over the final government to 50 mL. This will be equal to uh huh 0.1 to 0 Moeller. So in summary here, the malaria t of the zinc two plus in the resulting solution of zero the morality of the barium two plus in the resulting solution is 20.400 Moeller the morality of the n A plus and the resulting solution is 0.800 Mueller the mill arat e of the S 04 to minus and the resulting solution is zero the morality of the CN minus and the resulting solution is 0.400 Mueller and the mill Arat E of the C L minus and the resulting solution is 0.1 to 0 Mueller.

Calculate the polarity from grams and mill leaders. We first need to convert the grams into moles. Then we can divide the moles by the leaders. I've taken the liberty and written the mill leaders directly as leaders. I've already divided by 1000 in all of these problems. So take the grams, used commander mass of the substance in consideration in this case, chloride and be on the molar mass of sodium in a and then divide by the 100 milliliters already converted to leaders Do the same thing, then with the sulfate using the Moeller massive sulfate and then with calcium, using the molar mass of calcium, where 50 milliliters, of course, is 500.5 leaders.

No. Hello. We have to calculate any strength. So I need a strength. Mhm. Yeah I need a strength. Is the Mueller concentration of each iron Mueller concentration of each iron multiplied by the violence is squired. This is the definition of ionic strength. Okay so what is the formula of this? I nick a strength will be equal to half some medicine of see I gerica Harrisburg and I is Valid from 12 and okay so now we have to calculate any strength of the buffer. Okay so we have buffer solution is a mixture of is a mixture it is a mixture of sodium bar bitten sodium bar beaten barbie Wooten which is any B. A. R. And it is a concentration of 0.1 moller. Okay less magnesium. Yeah magnetism fast fit formulas M GPO Four and it is a concentration ist 0.01 Moeller. Now we have to calculate for the ionic strength of this buffer. So apply the formula of any strength. House see of any Jed of Anika. Always good. Bless sea of beer instead of be Erica. Always good. Let's see of MG JED of MG ca Holy square. Let's C. of. e 04 instead of pio Forca foley square. Now for the values in this formula and get the answer. Uh huh. Concentration of any. Yes is 0.1 into one ca square. Yes but See Barca cancer tradition is 0.1. Gentlemen, Valenca square Last 0.01 Going square MG has a charge of plus two. And fast fit is the charge of minus two plus 0.1 into man minus Toca square and here is minus one. So when we calculate this We will get the value 0.14 more than. Thank you.


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