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Question 15 Not yet answeredMarked out of 1.00Flag questionLet X be a discrete random variable with cumulative distrbution function given byX <10.40 1 < X< 3 F(x) = 0.60 3 < X <5 0.80 5 < X < 7 X> 7then P(x<3) =0.60none0.400.800.20
Question 15 Not yet answered Marked out of 1.00 Flag question Let X be a discrete random variable with cumulative distrbution function given by X <1 0.40 1 < X< 3 F(x) = 0.60 3 < X <5 0.80 5 < X < 7 X> 7 then P(x<3) = 0.60 none 0.40 0.80 0.20
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Use Table 1. Appendix 3, to construct a probability histogram for the binomial probability distribution for $n=20$ and $p=.5 .$ Notice that almost all the probability falls in the interval $5 \leq y \leq 15.$
Yeah that's probably have been given the cumulative distribution function. Capital F of X is equal 20. If X is less than zero. 0.2 Acts effects is between zero and five and one. Mhm. If X is greater than or equal to five and we would like to find a few different probabilities from us. Yeah, I would first like to find the probability That X is less than 2.8. Well this is just the definition of capital f. 2.8 mm Which is 0.2 times 2.8. We just plug it infrared. What's going on here? All we're going to do is take .2 times 2.8 and that's going to give us this probability and when we do This gives us .56. So these probabilities .56? Yeah, on b We would like to find the probability X is greater than 1.5. Well this is equal to 1- the probability X is less than or equal to 1.5 Which is 1 -101.5 Which is 1 -0.2 times 1.5. Mhm. It's always that 1 -2 times 1.5. And this gives us .7. On c we want the probability X is less than -2. Again this is just capital f of -2. And from the chart since this is less than zero this is just zero. Mhm. And um do you want the probability X is greater than six. Yeah Which is 1- the probability that X is less than or equal to search Just one -F of six. If such as ones, this is 1 -1 which is zero.
Saying about winter ball or we have the zero. It's less than equal to X. That is sick escape less than the cost of pain. This is a continuous probability distribution. So you have to find out be this excess less than bean. So you can see on distribution you can hustle this one. You can see the whole very off from 0 to 15. That's all right. Uh huh. And then the area that is greater than 15 it's not. Or none, because from the area absoluto 15 or the range from 0 15 this has bean filled out so that the area off the greater than PPC close to zero. We can also express this one US one minus p. Thanks. Access list. Um, in, however, this be less than 15. This this has probably probability of one so one and so on that c equals to zero. The answer for this one is zero