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1. (30) a) Calculate the entropy change for heating sample of 100.0 g of solid sucrose from 300 K to 320 K bar. Data: heat capacity Cem(s) 360.4 mol-1 K- , molar ma...

Question

1. (30) a) Calculate the entropy change for heating sample of 100.0 g of solid sucrose from 300 K to 320 K bar. Data: heat capacity Cem(s) 360.4 mol-1 K- , molar mass M 342.30 g mol-)b) Calculate the entropy change due to condensation of 1.0 g of water vapor at 373 K and bar given the molar mass of 18.02 gJmol and standard entropy 0f vaporization Hzo(l) HzO(g) AvapSo 122. J(mol K) (373 K, lbar)c) Calculate the entropy change due to combustion of 1.0 g of solid carbon at 298 K and bar given molar

1. (30) a) Calculate the entropy change for heating sample of 100.0 g of solid sucrose from 300 K to 320 K bar. Data: heat capacity Cem(s) 360.4 mol-1 K- , molar mass M 342.30 g mol-) b) Calculate the entropy change due to condensation of 1.0 g of water vapor at 373 K and bar given the molar mass of 18.02 gJmol and standard entropy 0f vaporization Hzo(l) HzO(g) AvapSo 122. J(mol K) (373 K, lbar) c) Calculate the entropy change due to combustion of 1.0 g of solid carbon at 298 K and bar given molar mass of 12.01 glmol and C(s) + 0z(g) COz(g) 4,So = 2.9 J(mol K) (298 K, Ibar)



Answers

The standard molar entropy of methanol vapor, $\mathrm{CH}_{3} \mathrm{OH}(\mathrm{g})$, is $239.8 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} .$ (a) Calculate the entropy change for the vaporization of $1 \mathrm{~mol}$ methanol (use data from Table $18.1$ or Appendix $J$. (b) Calculate the enthalpy of vaporization of methanol, assuming that $\Delta S^{\circ}$ doesn't depend on temperature and taking the boiling point of methanol to be $64.6^{\circ} \mathrm{C} .$

Then my dynamics is the branch of physics ideas with the relationship between heat and other forms of energy. So in particular it does describe how thermal energy is converted to and from other forms of energy and how this affects matter. So here we're looking at the inter conversion between methanol in the liquid form, in the gaseous form. So what we can do is calculate the entropic change and so the entropic change E. C. It's equal to the entropy of C. H. 30 H. In the gaseous phone. Subtract the entropy 12 CH 30 H. In the liquid form. And so this number comes out to be 113.0 joules per Kelvin. Permanent. Yeah. And so continuing on, the boiling point of methanol is given to us. And we can calculate the entropy of vaporization using the following equation delta H. With vaporization is equal to t adult s vaporization, where we just calculated this here outside valley there And so the temperature is 64.6°C. But we need to combat that to Calvin. And so in Kelvin that's 337.6 Calvin. So then we multiply these two values together. What we get is 38.2 kg jewels, part mom, and that is the entropy of vaporization of methanol.

Hello students in this question we have to calculate the entropy change when mass of water M equals to one kg from temperature T one equals to 27 degrees integrated. That is 300 Calvin is converted into superheated steam. That is T three temperature is 200 degrees integrate to suppose the boiling temperature T two of the water is 100 degrees integrated. So this is equal to 5 74 73 Calvin. Mhm And this is 373 Calvin. Okay so we can and we have the specific heat of dependency as for the liquid phase in the weber face actually and it is 1670 plus 0.49 temperature tight. Okay so no the net entropy change will be given by first of all from this temperature to this boiling temperature. So the specific heat will be taken here so we can write him or playerbase specific heat of the liquid molecular bait. Ellen of temperature T. To develop the temperature even so this can be taken as a weapon. Okay now this will change its face. So we'll convert into the were performed so M molecular be latent heat of vaporization, developing temperature T. To know after reaching this 100 disintegrated weapon that water vapor will convert into superheated steam. So we can right here that emery playerbase specific heat of the weapon face and Ellen temperature of T. three diverted temperature Tito. So this M can be taken out so where am it is equal to one kg. The specific heat of the liquid which is For two double 0. Natural law of temperature T two, which is 3 73 even which is 300 plus latent heat of vaporization, which is 23 multiplayer beta. Into the Power five, develop a temperature T two which is 3 73 plus a specific heat of the projection, which is this value. So +1670 plus 0.49 particular bait, Temperature T3, which is 473 marble herb natural log of 4 73 divided by 3 73. Okay, so after solving this, the net and therapy change Delta S. Will be 14 s. 7 5-1 jules per kilogram. Okay, so this will be the, sorry jule per kelvin. Okay, so this will be the answer for this problem. Okay, thank you.

So during the condensation of one mall a vapor of methanol to a liquid, the system is always at equilibrium under our constant pressure and temperature. So in this case the heat can be rejected. So in other words we have Q. P. Is equal to -1.0 multiplied by adults. H. vaporization Is equal to negative 38 kilo jewels. Where the delta S. The measure of the change of disorder is equal to Q. P. The heater continent pressure divided by T temperature in kelvin. Well, we can plug in the values so we have negative 38 kg joules what we calculated divided by 25-7 3 Calvin. What we get is negative 1-7.5 jules park Calvin. And so what we can look at is the entropy of the liquid. What delta S. Of the liquid is equal to the change in entropy at the entropy of the vapor, So that is negative 1-7.5 jewels for Kelvin. What we just calculated at 255 that's entropy of the paper jules put kelvin. Finally, we get is 1 to 7.48 jewels Park kelvin.

Since eyes and converted. Well water this is or or melding. So the entropy the changing and therapy for you them is given by delta at fusion. This is that changing the standard until before. He wasn't divided by I'm preacher former building or temperature for Cuban. Now here we have been given six point 0 to 5. Hello Jewel Permal. So we convert into jewel Permal for this. They were deployed by 1000. I understand with the power three and temperature here is or kill them. We all know for Susan the ice melts at real degree senses. Okay so that's why in Calvin it would be 2003 Calvin. So that's why here it will be to someone gets me. So solving it will be Delta is for fusion is given by 22 0.1 new park Calvin bottom. So now yeah we all know that molar mass of water. Smaller moss off water. Mm 18 drum for moon. So this is the mask for one mole for one mole. The mass of water will waiting Graham. Okay so that's why since these entropy is also in dual for Calvin Pirmin like this and copy is also for carmen. So here we can say that now 18 grounds of ice ice is the form of water. Here. Miles showing a changing and drop E. Doing change and then drop E. That is them to. Yes you then in what 22.1 dual park cabin or dual Calvin and walls. Okay so this is for carmen like so now if 18 g I smelled for the entropy of you than 22.1 dual per gallon. So as required in the caution one g eyes. Miles one big round eyes mels So in changing and drop it doing change in entropy change in and drop B. He went by 22.1 Divided by 18 market by by one. So solving it will be 1.28 june park Calvin or dual Kallen in walls. Now the part so the question is about water to weapons conversion is convert them and from water weapon. So this is changing and therapy for weaponization which is given by the anti itch for vaporization. That is changing standard and helping for weaponization divided by temperature for boiling point. So here in this question we have been given the standard and before weaponization. The standard and tell P for authorization is 14.63. Hello jules. So it is to address the power three jewels. So now the temperature for boiling point for water. So we all know the boiling point of water is 100 and these cells. Yes so when it is converted to Calvin it will be 100 degrees Celsius plus 2 73 That is Teresa 1° Galvin. So Divided by 3 73 Solving it will be 108.9 dual poor Calvin formal all dual Calvin and worst mall in world border. No again we can say that again we can say that 18 g of 18 g off H tool. That is water. The crisis the horizons they'll show a change to show mm change in an entropy in and trophy. Uh huh. That is delta as all representation Is given by 108.9 dual for Calvin per mole. All europe or Calvin Permal or dual Calvin. And we are small and work both are correct. So this is for caramel. So for one more this is the same as we didn't part for one more. The and dropping for the authorization. The entropy for weaponization is 108.9 jules for Calvin. Similarly for one mould a mosque of water. He's 18 grand because Mama says 18 grand Parmalee. So therefore 36 g H. two. That is water. That part. I just to show rep arises. You show a change in it changed in and drop me there it is. Delta is for a parade organization is given by or tortoises from it will be given by 100.108.9 Multiply by 36 divided by 18 So it will be 217 points 85. Do for carbon or door cabinet


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