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What is the product of each of the following reactions?...

Question

What is the product of each of the following reactions?

What is the product of each of the following reactions?



Answers

What is the product of each of the following reactions?

This question asked us to draw the product of each of these reactions. But before we start and want to do a quick recap of what a deal's older reaction looks like, because that's what all of these are. They're all deals, older reactions. So in the deals, all the reaction. We have a dying this is the simplest dying. And then a Dina filed dying file could be a double or a triple bond on. Both of these can have any other sort of attachment from them. But this is the simplest version. So all that happens is this. Double Bonds swings over here. This one's things over here, Miss Ones things back here. And we always always end up with this six numbered ring with a double bond left over on the dying inside. So this is going to be the basis of each product. So I'm gonna draw all of our reactions to look more like this, so it's easier to see. So for part A, we have the same dying that I drew above. If you draw it in that form and then our Diana file is a triple bond, in this case with some key tones attached to it that look like this. So here we're gonna do the same thing. This will swing here. This will swing here missile swing here and so that six members bring that we had above. We have that double bottom left over on the dying side, always. And then in this case, because they're dina file was a triple bond instead of a double bond. We have an extra pie bond over there, said That ends up being a double bond as well. And then we'll just throw those key tones that we're on our dying a file right on that side of the ring. So there's our product for part A for part B. We have the same dying, and then our dona file here is another triple bond with that's Sinai Group on it. So we'll do the same thing we did before. We'll swing all electrons around and get that 600 ring with the double bond left over on the die inside. In this case, we also have a double one left over on the Diana Farrell side because it was a triple bond and our substance, you went there as well. For part C Now we're getting a little bit more complicated. So start with are dying here. This has extra metal groups coming off of it and then are dying. A file is actually part of a ring. Um, and so that looks like this. But we're going to be exact same reaction. So those swings here, this swings here in this swings here just like before. So we get that same six member ring. But now we have some metal groups on the dying side, and the Diana file side has the rest of that ring that we had before. So that is our product for part C. And then for part D, we'll start with our dying again. So here is the basis, and then we have two methyl groups on each side here, Um, and then our dina file Is this six numbered ring like this solder the same thing. This swings here, this swings here. This swings here, Um, and we get that same basis, six member ring. Except now we have two methyl groups on each of those carbons and then the dining A file. Uh, the rest of that looks like this. So there's our product for a party

This question asked us to draw the two major products from each of these reactions. These air deals, older reactions. So a very simple deals Older reaction. Looks like this. We have a dying, um, and then a dying a file, and we're just gonna do some electron swinging here, so this will swing here. This will swing here, and this will swing here, and we always end up with a six numbered ring with one double bond leftover on the dying sites. Look going to be the basis of each of these reactions. So report A If I draw about in the same form as I had above, we have that dying just with the medical group attached to it and then are in Diana file. Here is the triple bonds. That just means we'll have one extra pipe left over, and then we have a Sinai group on their, um And so the reason we have two major products here is because we could have the CNN here on the same side as the methyl group or on the opposite side, like I've drawn here. Um, in some cases, you will have only one major product because you can you'll be able to draw residents contributors like we did in problem 40 that will align them correctly. But here, Because we can't do that with a metal group, we're gonna have to Major Brox. So for the first one, I'm gonna put the CN on top and the muscle on the bottom so we'll do that same electron movement like this, and we'll get that six members ring. We always have one double bond looked on the dying side in this case because the Diana file was a triple bond. That means we have one left over there as well are methyl group is down here, and the scion of there is up here. There is one product, and then we can also do the same thing with the Sino group on the same side as the metal. So we do that, um, we will get a product that looks like this. So now our CNN is just on the same side of the methyl group, So those are two products for problem 42. Uh, sorry for part a there, and then for part B, we have this dying, um, with a metal group on, uh, the second carbon there and then are donated. Viral is the same as before, so we can start with, um, the group's opposite each other here. So if we do that, this looks like that. So there is our 600 ring one double bond on the dying up side, and then we have an extra on the dying file side since it was a triple bond. And with this orientation are groups are opposite each other like this. Or if we wanted to put them on the same side like this, then we would get this product. You know, Michael groups in the same place. But now I got to sign a group up top here. So those are our two products for apart beat.

This question asked us to draw the products of each of these reactions. These air, both deals, older reactions. So just to quickly recap a deal's older reaction, we have a dying and a dying A file these air, the simplest two examples of those, and we'll have some electrons moving around here. So this will move over here. This move over here in this back here, and we will always get a six member ring with a one single pi bon left over on the dying side. Um, and so I'm gonna orient each of these in this way to make it easier to see. So for part A, we have a five member green here that has already oriented correctly, and then our dining are joining file. Looks like this. And then we have this key tone coming off of it like this. So if we do that reaction here, this comes here. This comes here and that goes back there were going to get a bicycle IQ, um, ring. So first we have our six number ring that we always get with. That one double bond looked over on the dying side. Um, and then the leftover carbon from If I remembered, ring will just be in the middle. So it's like this and then the rest of Dinah file it's just right over here like this. So that is one way to draw. It will also often see these drawn in this sort of, um, drawings. And then this one up here is the other end of the remembered ring. This is where our Dina filed waas. And then we have, um, that key tone over here. So either one of those ways of drawing this product is correct. And then for part B will do the same thing. So we have our dying already in the correct confirmation, and then we'll put our Diana file like that here. This is the same Diana file we had in a part. A. And so we'll do that same electron movement like this. So we'll get a new a six numbered ring with that double bond left over. We have the rest of that old one between those two car end carbons, and then we have the rest of the Diana file. Or you can draw this one in that other confirmation as well. So it would look like this, which have two carbons up top now. And, um, that key tone the left over. Over here. So again, two ways to draw this product.

Okay. This problem is having its predict the major product for each of these reactions. Okay, So what I have first is this one. So this is the secondary alcohol reacting with HBR and heat. And the reason I know it's a secondary alcohol is because if this is my alcohol, the carbon in which the alcohol attached to is connected to 12 other carbons. Okay, so keep in mind that this is a secondary alcohol cases that secondary alcohol is going to go ahead and get propagated by my very ascetic acid hbr resulting in this product. So what I'm doing is just duplicating this because it's just it's just a small change. I'm only adding one extra hydrogen case O H two instead of oh, each day. So that's gonna have a positive charge on the auction. And then I have my bromide I owned right here. Okay, so now I can have my s and one reaction. So, technically, we could actually have an s and two reaction here in which this all Kurds simultaneously because secondary alcohols, um, we won't have as much started hundreds as perhaps a church, very alcohol. But this is most likely going to occur in an s and one reaction. Okay, so what I'm gonna do is I'm gonna move the electrons onto this auction between that carbon auction bone resulting in a car broke iodine on the carbon. Okay. And the reason I did this in the first place is because water is a good leading a group, much better than alcohol. Okay, so this is going to result in the falling intermediates have my ch three ch two ch with a positive charge. That's because I've moved electrons away from it, and I'm gonna have my c h three. And then I have my bro might on here. Oh, and don't forget, we had the explosion of water, so it's gonna be just floating around now. Okay, so my bromide ion is gonna come in and attack this carbon because it has a positive charge at once. More electrons is going to move on to that carbon resulting in this product. So ch three siege to C H connection to a bro me, and then we have the siege three. Okay, so that is my product. Okay, Next step. Let's go into this one. So here I have a tertiary alcohol reacting with HDL and the reason I know it's a torture alcohol is because if this much alcohol the carbon in which the alcohol's attached to is connected to 123 other carbons Okay, so that's a tertiary alcohol that's important in this process, because that's gonna be indicative of an s and one reaction. So I have my alcohol. It's gonna get propagated by my super strong acid H deal, and we're gonna be left with this product. Do you think that move over here? Ch three. Okay, so this is just always to now with a pause it charge. Okay, so I'm the reason I did this is because I know I want toe eventually make a new product. So alcohol's those are not good leaving groups at all. That's because if we expel our hydroxide, we're gonna have hydroxide and hydroxide are very strong bases there, just being too reactive to be left alone. Okay, So if I have, if I printed my alcohol and have water instead, that water is gonna be considered un reactive enough to be able to be left alone. And if we're to make it leave case, I'm gonna have my call leave, start my water leave resulting in this my tertiary carb academy. The reason that could just leave. And the reason we know it's a as in one direction is because usually at least for us and two reactions, we would have a new cliff all such as Korean come in and attack that carbon simultaneously as this one reliefs. But we can't have that simply because we have too much stuff going on. It's too hysterical 100 for this core, and I want to come in. And that's because we have this metal group we have the presence of this cycle contain. It's just too much. There's too much going on, and that corn is just not gonna have enough room to come in. So that's why this isn't s in one direction and why these steps occur in two sequential steps. Okay, So because I left, I made that water leave. I'm gonna have my age to in the solution. I still have my chloride ion. That core right on ion is gonna come in attack that carbon resulting in the explosion hoops, not the explosion of safety. I'm just gonna go ahead and attack that carbon. So I should be left with this. So ch three and then my chlorine a Iot is now attached. So it's just a Korean case about is a tertiary alcohol highlight just like that? Okay, next up is this one. So this is a secondary alcohol. Reckon with HBR and heat. Okay, So the reason, of course, the reason we notes in a secondary alcohol because the carbon in which my uncle's attached to it is connected to 12 other carbons. So let's keep that in mind, because this is particularly important for this problem. Okay, so my secondary alcohol is gonna go ahead and get Pronin bite my HBR, resulting in the same exact thing. It's just one extra 100 you know? So did you get that moving over here? Okay. And all I'm doing is adding that extra hydrogen onto my previous alcohol. So now that now that the water Okay, so now the same steps as always. I'm going to have the bromide ion first of all, okay? And it's at the ready for a future nuclear Filic attack. Okay? So, again, this isn't s And one reaction one, because it's a secondary carbon and two, we have potential for other things which I'm about to get into. Okay, so I'm gonna have my water leave because it's a much better lean group than alcohol to resulting sodium hydroxide. So it's just hydroxide. So it's gonna be ch three c A r c ch three ch three and then my c h with a positive charge. Now and then we have the connection to the series three. Okay. And then, of course, we have water. Okay, so see how we have that secondary carbon cut on. So this carbon is connected to 12 of the carbons, Meaning it's a second. Their car broke down. So secondary carbon cut ons for s. And when directions are, you know, they're pretty good, but they had the potential to be better. And what I mean by potential, if it is capable of becoming a tertiary carbon cut on, it's going to do exactly that. Okay, That's because church here carbon atoms are much more stable than secondary carbon headlines. So what I'm gonna do is I'm going to move this metal group onto this carbon to relieve this carbon of its secondary carbon kind of in nature. Okay, so in the process of doing that, I'm going to go ahead and move the posit charge onto this. Carbon resulted in a tertiary car broke down. So I know that might be all confusing, but maybe if I draw the product will make sense. So ch three c ch three and then we moved the metal group onto this carbon, so it's no longer there, and right now it's gonna be attached to this carbon. So ch three there and and the connection to my ch three. So what I used to have was a positive charge there, but of course, because I relieved that carbon of its posit charged by moving this metal group onto it. I now have the positive charge on this carbon. Okay, so this whole process is favorable because we want from a secondary car. We got on to a church or a carp academy, and that's considered to be more stable. And this is all facilitated because in an s and one reaction, we have to sequential steps. So not just not just a new profile coming in, and at the same time my leaving group leaves, we're gonna have that leaving group leave, and then it's gonna be stable for a little bit. And then that relatively weak nuclear falcon come in after things are at the ready. So this is considered at the ready because it is much more stable now. Okay, So I'm gonna have my bro, Might I don't come in attack this stable, but has the potential to be even more stable by the addition of a new profile onto that carbon. So we should end up with this ch three c now connected to a bro me and then the remainder of my compound series three ch ch three and then finally ch three. Okay, so that would be my product for this one. Okay, next time we want to this one. Okay, so this is a secondary alcohol, because my here's my carbon contingency 12 other carbons and that alcohol is gonna get pregnant by my HBR. So it's going to result in this. So it's always too same thing is always and then my bromide on. Okay, So this is another case where we have a secondary alcohol and then we eventually make water. We're gonna make that water leave, resulting in a secondary carpet cut on. Okay, so in the previous example, we had, um let me see. We had this method group leave. Actually, I'll highlight that. We had this metal group leave, and then we eventually put it onto this carbon. Right? So if we look over here, won't happen if we made this metal group leave, right, because right now we have a secondary carpet condom. If it if it were to have the potential to be even more stable via tertiary carbon cut on, we would do so. Right? So if we were to move this metal group onto this secondary carbapenem and we would end up with this where we have a secondary carpet cotton still. So what's the deal? How come that happen? Why can't we just move a metal group onto that second car were cut onto relieved of its secondary carbohydrate nature? The reason is because we're not gonna move a meth group at all. In fact, we're gonna move the hydrogen. Okay? So don't forget that carbons need for about a total. We still have that hydrogen. They're connected, that carbon. So we're gonna move the hydrogen over here into that secondary carbon government resulting in. So that's gonna have 100 then we result in a primary or sorry. Tertiary car broke down. Okay, so that's considered much more stable now. Okay, so, no, my bromide ion can come in an attack. That carbon resulting in this product so brought me connected to it. Okay, so that's that, and I'll circle that. Okay, so moving onto the next one. So this one, this is a secondary alcohol record of HDL and heat. So I'm gonna have my same thing is always have my alcohol reacts with that age. Feel we're acting with a oh, h two. Okay, so something is always going to make that always to leave to result in a secondary carpet cut on. Okay, so we see that secondary car with time, and we see now we have this metal group right here, so we see a potential chair share carbon cut on, and we're gonna do exactly that. We're gonna move this 100 over there onto that carbon, and that will result in a tertiary carbon cut. So again, if we see the potential for tertiary carbon come from a secondary or even primary, Um the carpet got on. We're gonna do that. Okay, so we have this group still there, and we now have the hydrogen there. But because we lost that 100 in on this carbon, that carbon is not gonna have a positive charge. Right, cause we moved electrons away from the carbon. Okay, so that has a puzzle charge now and then. Of course, I still have my call right on. It's gonna come in as a nuclear file. An attack, that carpet. So actually election, regardless, because some teachers might have you be very specific about where they want your arrows drawn to. So in this case, it's moving onto this carbon not onto this positive charge. That posit charge is just a symbol. Okay, so I'm gonna go ahead and result in that product. So have my metal group and at my core in there, that will be my product. Okay, next up, I have this secondary alcohol, so this might be confusing, but here's my carbon connected to my alcohol that Carmen's connected to want to other carbons. Okay, so this is kind of a mixture of skeletal and condense structure, so Michael is gonna go ahead and get pregnant by my HBO, resulting in same exact molecule. Only difference is that I have the extra hydrogen now, so duplicate that. Move it over here, add a second hydrogen case of that. That auction that has a positive charge. Wanna go ahead and make that alcohol slash water leaves? Okay. So that water is a much better looking group than my previous alcohol. It's considered to be a much better leaving group now, so that will result in the fall in compound. So ch ch three with a positive charge on that carbon. Okay, so again, I have my call, right? I'm because I deep resonated that you feel so I have chloride right there. Okay, so that call, right? It has the potential to move on to straight onto that carbon resulting in my product. But again, we have a secondary car because it has the potential to be even better than that. So I'm gonna race that corny for now. And I'm gonna move stuff around to a bunch to get my tertiary carpet cut on And what I have right here, one bond away is my hydrogen. Okay, so that Hodgins gonna go ahead and travel. Actually, it's actually considered too far. So I'm gonna actually move this hydrogen onto this carbon, okay? And I'm going to go ahead and result in this product. So have a ch three their ch to now on ch three. And then I have my deposit charge right here. Okay? So again, we didn't use this one and that simply because it was too far. Okay, so we used the one red one bond over which is right here. Okay? And that's still results in a tertiary. Carter, cut on. Right, Because this carbon is connected to 123 other carbons. Okay, so, church, your car we got on right there. And now is the time where my chloride on and come in and attack that torture carpet cut right there. And then that should result in the following ch two ch three. Then all connected to that is my corn. Okay, little circle that and then zoom out so we can get it on the same screen. And by the way, this is my product in the previous one. Okay, so here we go.


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