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# $$e^{-i z}=e^{y-x i}=e^{y} \cos x-i e^{y} \sin x$$...

## Question

###### $$e^{-i z}=e^{y-x i}=e^{y} \cos x-i e^{y} \sin x$$

$$e^{-i z}=e^{y-x i}=e^{y} \cos x-i e^{y} \sin x$$

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