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# By the distributive law (iii) in the text: $(\mathbf{a}+\mathbf{b}) \times(\mathbf{a}-\mathbf{b})=(\mathbf{a}+\mathbf{b}) \times \mathbf{a}-(\mathbf{a}+\mathbf{b}... ## Question ###### By the distributive law (iii) in the text: \[ (\mathbf{a}+\mathbf{b}) \times(\mathbf{a}-\mathbf{b})=(\mathbf{a}+\mathbf{b}) \times \mathbf{a}-(\mathbf{a}+\mathbf{b}) \times \mathbf{b}=\mathbf{a} \times \mathbf{a}+\mathbf{b} \times \mathbf{a}-\mathbf{a} \times \mathbf{b}-\mathbf{b} \times \mathbf{b}=2 \mathbf{b} \times \mathbf{a}$ since $\mathbf{a} \times \mathbf{a}=\mathbf{0}, \mathbf{b} \times \mathbf{b}=\mathbf{0},$ and $-\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{a}$

By the distributive law (iii) in the text: $(\mathbf{a}+\mathbf{b}) \times(\mathbf{a}-\mathbf{b})=(\mathbf{a}+\mathbf{b}) \times \mathbf{a}-(\mathbf{a}+\mathbf{b}) \times \mathbf{b}=\mathbf{a} \times \mathbf{a}+\mathbf{b} \times \mathbf{a}-\mathbf{a} \times \mathbf{b}-\mathbf{b} \times \mathbf{b}=2 \mathbf{b} \times \mathbf{a}$ since $\mathbf{a} \times \mathbf{a}=\mathbf{0}, \mathbf{b} \times \mathbf{b}=\mathbf{0},$ and $-\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{a}$ #### Similar Solved Questions

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FRE-LABORATORX ASSIGNMENT for MOLECULAR WEIGHT BY FREEZING POINT DEPRESSION Before YOu can start this experiment YOu must: Correctly solve problem Pass an question computer quiz I)You measure the molecular weight of an unknown by measuring its freezing point depressie solvent: Given the following DA...
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