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Solution of NaOH was standardized with Potassium Hydrogen Phthalate (molar mass - (pts) 204.22 grams mole) to the pale pink endpoint Mass of KHP 0.301 grams Volume ...

Question

Solution of NaOH was standardized with Potassium Hydrogen Phthalate (molar mass - (pts) 204.22 grams mole) to the pale pink endpoint Mass of KHP 0.301 grams Volume of NaOH needed 29.30 mL; What the Molarity of thc NaOH?0,05110,05050.05030.0507

solution of NaOH was standardized with Potassium Hydrogen Phthalate (molar mass - (pts) 204.22 grams mole) to the pale pink endpoint Mass of KHP 0.301 grams Volume of NaOH needed 29.30 mL; What the Molarity of thc NaOH? 0,0511 0,0505 0.0503 0.0507



Answers

A solution of sodium hydroxide is standardized against potassium hydrogen phthalate. From the following data, calculate the molarity of the $\mathrm{NaOH}$ solution. mass of KHP $\quad 0.5536 \mathrm{~g}$ buret reading before titration $0.23 \mathrm{~mL}$ buret reading after titration $37.26 \mathrm{~mL}$

Hello. But this is uh the balanced chemical reaction for what is going on. So we can calculate the mole of GHP. Which is to go to the mass of Malema's. The mass was given us 0.0 sorry 0.1082 And of course the mullahs mass just get the individual mass. Individual mullah masses. Sorry for potassium for hydrogen endeavor phosphorus they just add them up. These are just constant. Okay that's gonna give you 204.22 So if you divide it you're gonna get this citizen number of most of PHP. Okay now when you have this expression right here the more ratio is gonna be one is 21 everywhere. Right? So you have one more PHP being neutralized by one mole of sodium hydroxide. Okay because this one is the one right? Therefore what would this give you the one? We just come with? The albeit is equivalent? So because the 1 to 1 ratio is gonna be the same thing for sodium hydroxide. So the number of moles of sodium hydroxide is also 10.5 to 9. Okay, Because the more ratio is one is one, of course, once you have that there is a similarity with, the similarity is the number of most of the volume, volume uh, steady four by 67 military. Okay. So you're gonna find the modularity and this is gonna be our final answer for the modularity of sodium hydroxide. Okay, thank you very much.

Chapter six Problem 80 tells us about a reaction between sodium hydroxide and the molecule K H P. So we have sodium hydroxide reacting with K H P. And we're told that K HP has one acidic hydrogen. So we have 10 h i on from any ohh reacting with one acidic hydrogen, giving us each to oh, and since we have one of each of thes, we know that our equation is balanced or that any wage and K H P have a 1 to 1 relationship. So we're given some information about K, H, P and about the amount of sodium hydroxide, and we want to know the polarity of sodium hydroxide. So whether we can solve this is converting the grams of Cage P two moles of Cage P. Then, since one mole of K H P is equivalent to one mole of Joh will have the most of any away from there. Finally, we'll do moles divided by leaders of a nail each to get our mill Araji. So let's begin. We're starting out with K H P. And we know that we have 0.10 82 Gramps, we're given the molar Mass here, where one mole is equivalent to 204.22 grams. So that gives us 0.53 moles. Remember that this is also equivalent to the moles of any O. H. So to get the polarity of any Ohh, we'll take the number of moles and divide with a number of leaders, which in this case, 0.3467 That gives us our final polarity of 0.15 Moeller.

Here's another K H P calculation. And in this calculation, um, we're trying to find how many grams what just happened there. How many grams of K. H. P were used. Okay, so here's the information that I'm given. I'm given that 20.46 mill leaders of a 0.100 bowler solution. Those are all zeros of any oh, age. That's how much sodium hydroxide it took. Teoh, um, react completely with a known amount of gave with an unknown amount of cage P. So what I'm going to do as I'm gonna figure out how many balls of ohh were used and that's gonna equal bulls of Cage P. And then I'm gonna convert moles of Cage P to That's one and that's to two grams of K h. P. And it's not going to very much based to do that. But I got nothing but space, so make sure my cameras on and we will begin. Okay, So to figure out our moles of any O h, we're gonna multiply Armel Araji, by our volume, which was 0.2 zero 46 leaders make my zero a little nicer here in that equals zero 0.0 2046 malls of any O. H, which is also equal to moles. Ohh! Minus which will be equal to malls, ofc, hp. So there there's first part of our problem done. Next, we're going to take, um, our moles of cage P and multiply that by at the bowler mass, which is 204 0.22 Let me double check that grams per mole. And the answer is 0.41 78 grams of potassium hydrogen valley. And I should Member mentioned again Cage P is potassium hydrogen Sally. Okay.

And this problem we're going. Teoh, do a little work with potassium Hydrogen valley, which is and for this problem were given the following information que hp, which have shown you the abbreviation, has a molar mass of 204.22 104 0.22 grams per mole. And in this problem, we are told that we have 0.10 eight to, I think grams of Cage and we use it to standardize an asset. And it requires 34.67 Miller leaders of sodium hydroxide to neutralize that Cage peak. It's pretty simple problem. It's gonna be two steps. Step one. My court just fell down. I gotta take a moment. Would step one, We're going to get moles of age, which will equal moles of anyway. Then we will calculate my polarity if I take your moles of anyways divided by leaders of any weight which, given let's do it Number one. We were given 0.1082 grams of GHB in order to find our moles recently divide by the older man's, which we were given as to 4.22 and our answer for This is and will wrong Later. 5.2 nine 8 to 1 times 10 to the minus four malls. And then her second step. We're gonna take moles. 5.2982 one times 10 to the minus fourth mold. Divide that by our leaders Just right here. 0.34 No, my bad. 0.0 3467 leaders. And the answer is 0.15 You ate Moller. Sodium had dropped, problem solved.


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