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Step 4 What the P-value for the test? 0,01 < 0.050,0050,010.05 P < 0.10,025 <0.05Step 5: MFe False The evlcence 0f dilterence tne population mean Scores Tr...

Question

Step 4 What the P-value for the test? 0,01 < 0.050,0050,010.05 P < 0.10,025 <0.05Step 5: MFe False The evlcence 0f dilterence tne population mean Scores Truenat slgnificant Ine 550 levelFalse

Step 4 What the P-value for the test? 0,01 < 0.05 0,005 0,01 0.05 P < 0.1 0,025 < 0.05 Step 5: MFe False The evlcence 0f dilterence tne population mean Scores True nat slgnificant Ine 550 level False



Answers

Conduct the appropriate test. A simple random sample of size $n=40$ is drawn from a population. The sample mean is found to be $108.5,$ and the sample standard deviation is found to be $17.9 .$ Test the claim that the population mean is greater than 100 at the $\alpha=0.05$ level of significance.

Now This time Isaac Statistic is 2.46 and my Alfa 0.1 My said statistic is 2.46 now. What I'm doing is I am going to take the people. Look, Alka later, Um, using an online tool and using a single tail test a one tailed test, I get my P value as 0.69 0.69 Now, since my P value that I've got is less than Alfa, I will reject. It's not, I will reject. It's not. This would be my answer.

Yeah we want to conduct the following test that after equals 0.5 immigrants. We want to test whether P one does not equal P two for example data X one and one X two M two. That is we want to conduct the test of the difference of population proportions P one and P two. To conduct this hypothesis test, we need to proceed with steps A through E. Listen to well first and a. We state our hypotheses this is H. R proportions are equal. If you want to speak to H one H A P one does not equal P. Two and P we can create our test steps. We have P hat one equals X. Number N one. We have to be the next to other into full P had equal 12 consecutive over and want them to be eating these numbers into our test statistic gives me not equals 19.3 point four are critical value at 5% significance in the table is er over 200 plus and minus 1.96 The P value is P equals two pc. Grieving after values are not equal 20.73 dust. We have an E that since P is greater than alpha and Xena is not in the critical region, we failed to reject the null hypothesis H nine.


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