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9.4) Tkc60-Hze towoc ofdotaics cinuit shown in thc figunc hes # voltase amplindeof IZ0VThc cnicttive an4i 7900 tc inductive nacunce [ 270 0 udtx mainancef 5000790 0...

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9.4) Tkc60-Hze towoc ofdotaics cinuit shown in thc figunc hes # voltase amplindeof IZ0VThc cnicttive an4i 7900 tc inductive nacunce [ 270 0 udtx mainancef 5000790 060 HzR=S0O nulU XL= 270 0i) What is thc Cupacitancc of thc capacitor?Mninductance of thc inductor?HL) Dcterminc thc toLa Impcdince 0i tc cucuItM) Calculatc the phasc ungk.Ool thc voltage sourcc rclutivc t0 thc =WechcualD1 A planar clec tromaenctic WJ€ / propieating In thr occn Alattin poin Pan#*n instentthe ckcctrka licld 0f th #ate

9.4) Tkc60-Hze towoc ofdotaics cinuit shown in thc figunc hes # voltase amplindeof IZ0VThc cnicttive an4i 7900 tc inductive nacunce [ 270 0 udtx mainancef 5000 790 0 60 Hz R=S0O n ulU XL= 270 0 i) What is thc Cupacitancc of thc capacitor? Mn inductance of thc inductor? HL) Dcterminc thc toLa Impcdince 0i tc cucuIt M) Calculatc the phasc ungk.Ool thc voltage sourcc rclutivc t0 thc = Wechcual D1 A planar clec tromaenctic WJ€ / propieating In thr occn Alattin poin Pan#*n instentthe ckcctrka licld 0f th #ate Egnen by E 3301 i08 mei JFCi Entude



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At least $25 \mu \mathrm{g}$ of tetrahydrocannabinol $(\mathrm{THC}),$ the active ingredient in marijuana, is required to produce intoxication. The molecular formula of $\mathrm{THC}$ is $\mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2}$. How many moles of THC does this 25 \mug represent? How many molecules? (b) Caffeine, a stimulant found in coffee, contains $49.5 \% \mathrm{C}$, $5.15 \% \mathrm{H}, 28.9 \% \mathrm{~N},$ and $16.5 \% \mathrm{O}$ by mass and has a molar mass of $195 \mathrm{~g} / \mathrm{mol}$. (c) Monosodium glutamate (MSG), a flavor enhancer in certain foods, contains $35.51 \% \mathrm{C}, 4.77 \% \mathrm{H}, 37.85 \% \mathrm{O},$ $8.29 \% \mathrm{~N},$ and $13.60 \% \mathrm{Na},$ and has a molar mass of $169 \mathrm{~g} / \mathrm{mol}$

Hi everyone. So in this question they asked the electronic compilation of four elements are given as and uh one is managed to reassure people. The second managed to two years to do before 30s managed to do is to to be 3420s. When I should we ask you to pay six years 23 people? Which of the following enrichment gives the character order in terms of increasing electronic equity of lemons. So option she is correct. Oh son. Yeah. See is correct. Mhm correct. Alder off. Okay. Increasing electronic entity of the lemon teas increasing. Okay. Mhm. Electronica activity. Mm. Mhm. Yeah. Of the element ease. Mm As follows. Yeah. One X two creation To be 6 3 ash too three p 1 we can say at live India smaller than Okay. One is to to rest. Oh yeah to be three that is nitrogen which is smaller than nice to us to be for decades oxygen. Mhm Yeah, it is smaller than 1" to 3 years to to be for you that is floating chlorine. Is the lament having a guest electronic. It'd in the periodic table Florrie is the Lemon Read I. Yeste 11 12 negativity in the periodic table and erotic devil. Thanks loved

Okay so the question RC low pass filter circuit has resistance R. Equals to 90 on. And the capacitance C. Is given eight nano ferret. Okay and we have to calculate the gain that is we out by we in for the frequency is given. Okay So part a frequency is given 600 hertz and we have to find out delta. We out divided by delta. We okay we know that delta tau delta being. It is the capacitor reactant divided by delta V. In that is the impudence. Okay it will be the square root of our square plus X. C. Square. Okay so we have to find out taxi. So X. C. That is one divided by omega psi. Omega is angular frequency. So it will be one divided by two pi fc frequencies given 600 hearts. So it will be one divided by two pi multiplied by 600 hearts. Multiplied by C. Is given 89 of Herod. So it will be eight multiplied bartenders to the par minus nine ferret. Okay so when we saw all this will exceed it will be 3.32 multiplied by 10 to the power four. Okay so we will find out, we will find out delta we out divided by delta V. In that is XC 3.32 multiplied by 10 to the power forum divided by the square root of our square. Are is given Or is even 90 on. So it will be 90 home Squire plus XC square that is again 3.3 to multiple buttons to the power for Squire. Okay what we can say Home is choir. Okay, so when we saw it will be nearly equals to one. Okay, so one will be the answer a party of this question and now again we will go to the part B that is for frequency is given 600 kHz. Okay, now frequency 600 kHz. So no problem. First of all we have to find out XC. That is one divided by two by fc. So it will be one divided by okay to buy frequency 600 Kilohertz or 600 multiply button. And the power three hearts. Okay, multiplied by C. That is 89 of error. So eight multiplayer Bataan is to be about nine minus nine. Farid. Okay so when we saw XC it will be 33.2 home. Okay so now delta V out divided by delta V. In that is XC divided by square root of our square plus X. C. Square. So it will be X. E. That is 33.2 on divided by the square root of our square. That is 90 oh me Squire Plus access where there is 33.2 home square. So when we saw it will be zero point 346. And this will be the answer of part vii of discussion. Thank you.

So here for part A. We know that there's no capacitor, so the, uh, the reactive capacitance is equaling. Zero. The react, the inductive react Ince's equaling two pi times the frequency times the induct in CE And you know that here this would be equaling two pi times. And for the first case, 60 Hertz, then three. Miller Henry's so three times 10 to the negative Third Henry's and we find that the inductive reactant is equal in 1.131 comes. We know that then, for the impotence, this would be equaling r squared the resistance squared plus the difference between the inductive um react. It's minus the capacitive reactor Is quantity squared all raised And this some rather is all raised to the 1/2 power. We know that this value is zero because there isn't any capacitor and so solving this would be equaling 40 arms Ah squared plus 1.131 comes squared, all raised to the 1/2 power and we find that the incidence for 60 hertz is 40.2 thumbs. This would be one answer for party. Second answer for part A, um would simply be the impotence see equaling again 40 arms and then squared, plus two pi times the frequency here being 10 kilohertz or 10 1000 hertz multiplied by again. Three. Miller Henry's three times 10 The negative Third Henry's This entire term would be squared and this sum would be raised to the 1/2 power. And we find that Z, the impotence at 10 kilohertz would be equaling 192.7 thumbs. So this would be our answer for the frequency being 10 kilohertz and so four part B simply asking us to compare these values. And we know that then, at a frequency equaling 60 hertz and a capacitive reactant ce um, of equal in 531 comes the value of impotence Z would be 13 times as high as without the capacitor. So we can say loaf at at low frequencies. Uh, the capacitor makes a large difference, and four part be continuing for part B, but at frequency equaling 10 kilohertz, we know that in the capacitive reactor s equaling 531 comes. Um, the value of impotence is the same, so we can say at high frequencies the capacitor because they the capacitors effect, um, is much lower were much smaller. That is the end of the solution. Thank you for watching.

So here we know that first for part A the inductive reactions would be equaling two pi times the frequency times the induct in CE. So this would be to pi times the frequency of 60 hertz times the inductive of three Miller Henry's were three times 10 to the negative Third Henry's and this is equally 1.131 comes then for the capacitive reactant. So this would be equaling one over to pi times the frequency 60 hertz times the capacitance of five micro Farid So five times 10 to the native six marrieds And this is equaling 530 0.52 homes. And so we can then say that here the impotence would be equaling r squared plus x of l minus except see quantity squared, all raised to the 1/2 power. We know that here this is gonna go to zero and we can say that Then the impotence would be equaling the difference between the inductive capacitance. Sorry, the inductive reactant ce My apologies. 1.131 comes minus the capacitive reactant CE 530.52 comes quantity squared raised to the 1/2 power and so essentially Z is equaling. The impotence is equaling. 529. We can save point 39 homes. So this would be at 60 hertz and then continued on for party. No, we have 10,000 hurts. So ex of El Equaling two pi times This will be 10 kilohertz, or 10,000 hurts well supplied by the induct in CE of three times 10 to the negative Third Henry's and this is equal of 188.5 arms. And then the capacitive reactor ants would be won over two pi times the frequency of 10,000 hertz multiplied by again five Micro fair. It's so five times 10th of negative six marrieds and we find that the capacitive reactor is here is 3.183 thumbs and the infants would then be equaling again R r squared to zero. So here we're simply taking the inductive react in ce mai esti capacitive reactor. It's quantity squared, all raised to the 1/2 power and this is gonna be equaling 1 88.5 minus 3.183 quantity squared raised to the 1/2 power and the impotence is equaling. 185 points. 317 thumbs. This would be our impotence essentially at 10,000 hertz for part A or 10 kilohertz for part B. Ah, why're the compared these values and compared these values of Z in which there is also resistor? Well, there we can say that here the resistance are is there's not contribute greatly to the total impotence. And we can say that here the capacitor dominates at low frequencies and here the induct er dominates at high frequencies. Is that essentially comparing to example 20 to 12? That is the end of the solution. Thank you for walking.


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