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Draw structural formulas for the major organic product of the reagents sboum OCH:FeBlaBrzOCHaYou do not have " considcr stercochemistry: Apply fomal = chuges =...

Question

Draw structural formulas for the major organic product of the reagents sboum OCH:FeBlaBrzOCHaYou do not have " considcr stercochemistry: Apply fomal = chuges = to any nitro groupB . If there more than onc major product possible, drawall ofthcm; Scpurate multiple products using the sign from the dropdown mcnuDaod

Draw structural formulas for the major organic product of the reagents sboum OCH: FeBla Brz OCHa You do not have " considcr stercochemistry: Apply fomal = chuges = to any nitro groupB . If there more than onc major product possible, drawall ofthcm; Scpurate multiple products using the sign from the dropdown mcnu Daod



Answers

Write structural formulas for all the products that would be obtained when each of the following alky halides is heated with sodium ethoxide in ethanol. When more than one product results, you should indicate which would be the major product and which would be the minor product(s). You may neglect cis-trans isomerism of the products when answering this question.
(FIGURES CANNOT COPY)

Let's take a look at more reactions of al canes. Well, let's take the first one with each 20 in each to us of four. Well, we know that that will produce the Markov Makov product in an alcohol so well, which carbon involving the, uh the l keen four carbons adjacent to the Al Cain will contain the alcohol. Well, the most stable carbon is that one. So that will be where the alcohol will be. And that will be your product stick. It will get the next one. Here we have this out keen with brahmi and water. So we know that that will produce the mark optical product relative to the alcohol. The alcohol would be the most stable. Be at the most stable carbon, and the Bruning will be at the last stable carbon. We know that boring nation produces the anti Markov Nukaga alcohol, which means less stable al keen or less stable alcohol of the Al King. So the less stable carbon is that one because a tertiary carbon is very, very stable. So that will be where alcohol will be produced, bro Ming. Now, this doesn't produce a carbo cat ion. So We're kind of just limited to a bro. Mean Adam here and abroad. Ming Adam. There those analysis. Well, this will cleave this double bond producing to Aldo hides. And from the looks of it, this molecule symmetric relative to that out keen. So it will just produce to molecules this Aldo hide, and that will be your final product.

Suppose we wanted predict different products. Well, let's try going through those. Suppose we have this car books sold gas it and we want to react it with associate to what would that produce? Well, this is a very common way to add chlorine. And we know when we have problems like acid. And we had Corinne, it would make any Solh allied. How about if we were to react this acid with this alcohol? And we have catalytic h two s 04 Well, we have an alcohol and we have an acid. This makes a nester. Let's try another problem. What if we had this natural? We wanted to react it with H 20 and catalytic h two s 04 Well, this is just saying h 20 with age plus, which we know to be adroll icis and well, that's what we will get. What's one too many carbons? Let's try another example. How about this LDA hide? We reacted with h two c r. 04 Well, chronic acid is a very common re agent for Jones Region, which is known toe oxidize alto hides in alcohols. And if we have a primary alcohol or unhealed hide that will oxidize that to a car. Books look acid about this reaction. OMG go to nature, Theo plus. Well, we know this is green yeard. The agreement pathway to creating a car broke. So gas it. And we know that this our ads one carbon. So we can kind of skip ahead a little bit and say we have our starting material where the bro Ming waas we have a carbon and then we have our acid that adds one additional carbon. And there we go. Let's try another reaction. Whoops and let's react it with N a O H h 20 with an acid workout. Well, any O. H and H 20 tells us that this is I drawl asses, but it's in a basic medium. So we would get and alcohol and a car box elit. But oh, you should be two, not three. But we haven't asked for work up, which tells us that it adds another hydration back into the system. Let's try another reaction. Let's try this re agent with H 20 and each to us before catalytic. Well, this is once again a hydraulic sis in an acidic medium. So we know that this will produce a carb oxalic acid and an ammonium I own in age three. Plus that monkey. Let's try another. But if we had this alcohol when we wanted to react it with each to Sierra four and eso seal, too. Now this is a little bit more tricky because now this is two steps that we haven't seen before. Well, we know this is Jones, so it'll make car box. So the gas it we know that. So that's our first product. Then we add to Yeah, what does that create? Well, we have CEO, so we'll make a nasal highlight. Not that bad, right? Let's try one last reaction. Let's have female and we add it to this anhydride. What would that produce? Well, let's let's assume this to be an equivalence. Let's assume that their equipment. So there's no excess. So the either. Well, since there's no excess, we know that really only one of those carbon eels will become and Esther Well, what about the other one? Well, if it was excess, we would have another Esther. What? It isn't so it will end up being an acid

Suppose we want to predict the products of various different car bookseller gas A derivatives. Well, in the first case, we haven't Elkana Mohei light, and we're adding a file to it. And the key thing to note is, styles are very similar, very similar to alcohol's in the way they function. So in fact, this will make something called the Dia wester because it's not exactly an Esther because it isn't an alcohol being reacted. Instead, it would be I sold for Adam instead of the alcohol. But nonetheless, there is an Esther Bond, which is called a thigh. Oh, Esther Bond. This functional group is a thigh wester, and that will be your product. What about in the next question about on Elkana will highlight with excess ammonium or a money or an ami rather excess A means Well, this will make a name. I this a my plus we will have and ammonium salt and that will be a side product. But it is still in organic product. No. What about this example? We have an anhydride and an alcohol. Well, it seems like it will be making an Esther, which would be a correct assumption with an out with a carb oxalic acid group, and I have drawn this poorly. Let's try that again. I will make the 1st 1 a acid. And the 2nd 1 we'll have our buster again. This Esther group could be placed on the other. Um, Carbonell, I just due to space and how I was drawing it, it would not have fit. So I put it on the other one. But either way would be correct, because both of those are identical. How about this, Markle, For this reaction, if we had this car books look acid or a rather ah hydroxy topics like acid. And we're and we reacted it with catalytic age to us a four. Well, this would close the ring, and we'd get a 123456 member ring. We would get a nester. And on the fourth member, 65 before we have a metal group. And that will be a major organic product. Would be this, Esther, because we have an alcohol in a car. Books. Look, acid. What about this reaction? Well, if you remember from reactions of benzene, this seems to be a Friedel craps ace. Elation. So if you pick anywhere on this benzene ring. I will just pick this carbon right here. It will form this key tone. What about this reaction? What would this produce? Well, this reaction would produce an Esther because we have a Elkana will highlight and in alcohol. And we know that strong derivatives can make go too weak. Just we cannot go too strong, so it will make. And am I'd for Sarria Nestor. Plus, we're doing this in the presence of period ing, so we will have an organic salt that would be produced and that will be our major organic products for this reaction.

Let's explore some of the reactions of natural groups. No. If we react this compound with K C N and then reacted with H 20 and H to us a foreign catalytic amount, what would we produce? Well, we know that the first step is a secondary. Hey, well, cane with Kay CNN. So we know that this will be in S and two, so our stereo center will invert and we will be left with this. Now, what about the second reaction? And this is a subtle point about the definition of a catalyst. And the definition of a catalyst is something that is used free agent used and produced. So a catalyst in chemical senses is a re agent or a molecule that is used for a reaction to occur. But it's also one of the ending products, which is why we don't include it in a balanced chemical reaction. If we use up a catalyst and we produce it, it's a one for one deal, and it cancels out. But the catalyst is produced. So if the question is which of these molecules will react with h 20 n h to us before the answer is both because both of them are pretty identical. The only difference is that they have different stereo centers. But this reaction does not depend on that. So both of them are identical. We can treat them as identical substances. H two and H two us of four, we know is the hydraulic cysts of naturals into carb oxalic acids. So if the question was which one would react first, well, it could be either. It's a 50 50 chance that it could be one or the other half of the times. That will be 1/2 the times it will be the other. But in the end, that catalyst is being produced again. So there's no reason why it wouldn't react with the molecule once again. Which is why, in the end, it would be both natural groups reacting with the car Books look, acid are reacting with the water and sulfuric acid to produce carbon gases because, say, one of them is made into a carb oxalic acid. And now we have this re agent back that will just react again. What about this reaction? A natural with diable? Well, we know that Dybul is a reducing agent and it's very similar to lithium aluminum hydride, so we can assume that it would make and I'll died. So let's counter carbons to make sure natural is always get a little bit confusing because there is 1/4 carbon right there. 1234 That will be your product. Now where does the water come in? Well, there's a transition state in the mechanism that the water will end up being used to actually create this album hide. So our product is in fact the elder hide. What about this reaction? A green eared re agent to a natural Well, we know that Griner is an organic metallic, so we know it will probably reduce our natural. So we will have a carbon eel compound of some kind. But where does this metal come in? Well, typically, we have used grin you'd re agent as a way to add carbon carbon bonds to Carbonell groups. Well, this is no different because instead of making an alto hide like Die Ball did this green Udrih agent will make a key tone and it will be this our group, which is CH three, which is right there and with an acid work up. Because when you re agent is a basic re agent, what about this reaction? We have an am, I'd and we are reacting it with h 20 h to us a four catalytic. Well, this will make a carb oxalic acid and an ammonium salt. Because we know that hydraulics this an acidic conditions reads to this product, and there would be NHs. 04 bounded to that. But that's just a small, subtle point about that. What about this Esther? We reacted this Esther with green agree agent in excess with the city conditions. Of course. What would we produce? Well, we'd produce a symmetrical alcohol. So we know that our our groups ch three ch two and it will be a symmetric alcohol, then that will be a product.


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