In a solar eclipse. Um, the moon, earth and sun are in the same line, so the moon is between the earth and the sun. So the force exerted by the sun on the moon is what we need first. So a force equals G m m over R squared. So in this case, we're gonna have Obviously, in all cases, G is 6.67 times 10 to the negative 11th power in s I based units. Mm capital am would be the mass of the sun. The mass of the sun is 1.99 times 10 to the 30th power in S I based units, which are kilograms, um, mass of the moon. See if I have this written down. I believe that I do not have this written down, so I'm going to google it. Mass of the moon in kilograms is 7.3 five times 10 to the 22nd power kilograms and ah, I'm gonna write capital. Are is from earth to son, 149 0.6 times 10 to the ninth power meters. And then I'm going to lower case R, which is from Earth to the moon um, uh, radius from earth to moon in kilometers or in meters. I was googling this. It says that it is 1737 kilometers, but kilometers are times 10 to the third power. So I'm going to erase that, and I'm going to write times 10 to the third power meters. Now, I need to adjust my generic equation here. Um, the denominator is going to be radius from Sunday Earth minus radius from Moon Earth, which is probably negligible anyway. And then square g m m over r minus r squared. I'm gonna put this in the calculator, and I'm just gonna use all the numbers that I have written down for you and ah, 6.67 times 10 to the negative. 11th power times 1.99 times 10 to the 30th. Power times 7.35 times 10 to the 22nd power. All of that divided by quantity. 149 0.6 times. 10 to the ninth Power minus 1737 times 10. Do the third hour squared. And this gives me to two significant digits. 4.36 times 10 to the 20th power. Nunes, I'm just going to take away Ah, the radius. Little are And see if that really makes any difference If you take a little our way away, Uh, there we go. Take a little our way. Gives you four point three six also. So, um, little are is really negligible. It is very, very small compared Teoh Big are That's interesting to note. B force on the earth. So, in part B, um, we're gonna replace this m with the mass of the earth. A mess of the earth is 5.97 times 10 to the 24th kilograms. And since, um, little are was negligible, it's really the same equation. So all I have to dio is right. F equals G. I am, um e it's an e over our square. Put that into a calculator. 5.97 times 10 to the 24th Power. Uh, looks like I actually just salt sea getting ahead of myself. Apparently. So this is actually see the force of the sun on the earth. And I did get an answer of 3.54 times 10 to the 22nd Power News So let's look at what be was Apparently I skipped be a red sea instead B is asking us about Earth on the moon. So earth on the moon so f equals G. This has to be mass Earth, mess moon over the radius Earth Moon That's a little R squared. So, Miss Earth, this is massive, man. And little are so I have to put those in. So let me go ahead and do that, okay? I already have mess Earth in from the last problem. So now I need mess of the moon 7.35 times 10 to 22nd power. Um, over our this time are is little are 1737 times 10 to the third power squared. I put all of these in a calculator and I get 9.70 times 10 to the 24th Power Newtons. So the last part asks us Ah, why the sun doesn't ah, pull the moon away from the earth? Well, the force exerted by the sun on the moon is a and we can see that that is to the 20th power. Um, the force exerted by the earth on the moon is be. That's to the 24th power. And so the force exerted by the Earth this is in D force exerted by the Earth is much greater than the force exerted by the sun on the mirror.