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What is the total energy equired for tne following reaction to progress?1 1 !Reaction Coordinate...

Question

What is the total energy equired for tne following reaction to progress?1 1 !Reaction Coordinate

What is the total energy equired for tne following reaction to progress? 1 1 ! Reaction Coordinate



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Compute the energy released in the reaction in part (a) of the preceding problem.

In this problem of nuclear physics, we have to find the energy relate in the reactions. First reaction is this is helium four plus helium four is converted into lithium six. List. This is due to Stadium and second is helium four. So this is the alpha particle or we can say plus helium three. So this is is converted into deuterium plus this is lithium, this is five and 30 X. Image deuterium less treaty um is converted into first. This is night here. First vintage neutron plus this would be helium. So first the formula to evaluate the energy religion is is the energy released. So this is calculated at delta and that is the mass defect multiple with C square. So master of helium is equals two, 4.0 2603 at McMaster unit. Similarly same for here and master of lithium six is equal to 6.1 51 two atomic mass unit. And massive detainee um is equal to 2.1 for ethnic marks on it. And now massive helium food is again this is 4.0 to 603 at McMaster unit. And mass of message, helium three is equals two, three point 016 to nine 60 29 at McMartin. It myself deuterium is equals two 2.14 ethnic martian. It and mass of lithium five equals to 5.1 25 ft atomic mass unit. Myself. Deuterium is equal to 2.14 atomic mass unit. And MYSELF three Tm is equal to 3.16 at McMaster unit. And now mass of a neutron, most of neutron is equal to 1.0 86658665 atomic mass unit. And mass of helium is equal schools 4.0 2603 atomic mass unit. So first we would evaluate the master effects. So this is delta M. One and in this direction this is delta M two. And here this will be delta M. Three. So Mark defect and firstly ex energy equals two. So must defect for but is equals to the stage minus 0.239 0 to 391 for atomic mass unit. Similarly multi effect for the X and B is equal to the stage minus 0.8 double zero 85 atomic mass unit must affect for 30 X. And A Z equals to this age plus positive. So this was 0.1889 ft two atomic mass unit. And now energy is delta multiple early C square and we have you multiple early C squared equals 931.5 mega electron world. So this is he is equal to here. Daily time, particularly see square. So this is equals two minus 22.37 mega electron world. So energy one and he had energy to is equal to we have to first multiply mass with C square. So this would be equals two minus 7.46 mega electron work. Similarly. Energy released in the third reaction is equal to this is daytime multiple C square, so this would be equal to 17.6 mega electron work. So this is the right answer. Yeah.

From the given figure. The volume off the gas increases from two litre poetry leader by the external Pressure is also provided as 2.5. So we have Delta V that is changing volume that is three litre minus two. Leader, the changes one leader. The external pressure P is 2.5 medium on the changes. Wyndham is greater than zero. Let me write all this. So external pressure. The X T is equal to 2.5 on Delta V is greater than zero. That mean expanding system loses the energy so expanding system that means loss off energy which states that it will have a negative sign were him. So book done is acquittal negative pressure external multiplied by change in will you substituting the values we have booked? Done is a quintal negative to 50 2.5 jewels, which is equally villain toe negative. Zero point 25 Hello, Jules.

We have to find out how much energy is released during these reactions. And the first one is you solution A do one H one plus three realized seven. It's that the Can write to 84 that is to 3 4 of two Helium Party. And some energy is released. So the atomic mass or one x 18 at 1.0078. You And the atomic mass of 37 is 37.0160. You. And the total is there 8.0238. You and similar. 2 84. Atomic mass is 8.005-0. If you to the march different must be different. Delta M. is close to 8.0238 U -8.00 52. If you while solving this, regard this 0.01863 to you. And the energy do later Energy is exposed to deal. Time is multiplied by 9:31.5 mega electron ball for you. And this is the master You know. So that E. is a question of 0.01 day 63 to you is multiplied by 9:31.5 mega electron volt is you. This is 17.4 mega I left on both. So now the value of energy is released 17.4 mega electron. This is the answer. And the second part is there C five. The reaction is one age 3 Plus one edge to Egypt 2 80 four plus continue. And so here The one Edge 3 is equal to 3.16054. And the one edge to each dead 2.01410. And the total is the total value is that we can write it 5.03, And the atomic mass off 24. It's four point of al 0- 604. And the atomic mass of zero and 1 is 1.008 double 64. And this is the total value of 5.01126 ft for the March Defense is you. The all time music was 25 on 03154 minus 5.011264 is zero G 01 double 89. You so the energy is you 0.01889. You is multiplied by nothing at this point 931.5 mega electron board. But you know, this is 17, 17.6 mega electron. So the answer should be 17.6 mega electron volts

In this question. We're going to draw the energy diagram for reaction Where the equity around Constant to see quota one. So now let's write a general equilibrium reaction. So we have the reactant on the box. So the equilibrium constant is he quality product of the concentrations of the products raised, the big power off the coefficient. Any reaction? So we have the paradox, Maria City court for Jones in the reaction, and we have the reactant. So if the equilibrium constant is equal to one, then they'll be equal concentrations of products on the reactor arms. So therefore, both sides of the reaction Ah, energetically favourable. Okay, You know, that's represent this in an energy dark. We have the reactions. Okay, then, because if your transition states until we get silly, So the highest energy structure is the transition states. Also, that's true. The ignition energy, which is a difference between the initially dot com and the tradition states of actually activation energy. Let's trophy, and then she level of good looks. So, seeing that both sides of the reaction, uh, energetically your problem reactant on it, but it's will resign at the scene. Energy. Thank you. So This is the and it's adorable. Also, we can recall that a free energy of the reaction is Nick Lowe City Free Energy. Okay, put ups minus pre energy of the reactions. Okay, Um, seen that the energy of the reactant on the products are equal. Therefore the free energy change energy. The paradox equals me. Energy free energy change off theory option will be equal toe zoo.


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