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For each of the reactions shown below, give the single major product Clearly show all stereochemistry where appropriate_ Ou may write NR for no rcactionHBr (*s)CH M...

Question

For each of the reactions shown below, give the single major product Clearly show all stereochemistry where appropriate_ Ou may write NR for no rcactionHBr (*s)CH MgBr ether H;oEthot 2 H,0

For each of the reactions shown below, give the single major product Clearly show all stereochemistry where appropriate_ Ou may write NR for no rcaction HBr (*s) CH MgBr ether H;o Ethot 2 H,0



Answers

Give the major product(s) obtained from the reaction of each of the following with HBr:

We're taking a look at the major and minor products that we may fall. So in the first part we see that our kids can undergo electrical like edition reactions with H B R on what we form is the following. So we have to products here, and these are and equal populations in our reaction mixture. When products are forming in the second part that we have here, Ah, major product is as follows. So by Major, I mean that this product will be greater in concentration than any other structures that may be present. So in Thesafeside example, what we generate is another major product that is Burma. Nated, that is three Bruno to three. Damn Ethel Hexen. In the final example, what we form is one Bruno Bonney thaw cycle repenting.

Predict the major product off additional. HBR drew fallen Arkin's and the direction proceeds through a crab, dying for him on a tertiary carbon So this couple will receive berman being reaction proceeds. Flu comeback Italian form a nursery carbon so that carbon received woman See, the reaction can proceed for either secondary complicate time here or secondary capital time there. But this convict ABAC Italian. At this couple, I got into the tertiary one but shifting H minus from the next carbon. It generates tertiary crumpacker time at this carbon and this carbon will receive berman.

So first here you would create. So the ring opening occurs of the tertiary carbon to give a carbon cat on, like, civilly to the transition state. So here is that transition state, and this is going to come in right here. So then this would work. Um, so the brahmi and approaches 100 degrees from the c o h. Bond, as it would like in an SMT reaction. So then this would lead to you'd Havenaar and here you could have an s.

So this question we're talking about predicting major products from your action off HBR with different Al Keane's. So soon with eight, we're gonna start with this structure, right? So is god something that looks like this. I'm reading HBO to this. Um, the product is actually gonna be a little different than what would seem obvious you're actually going, Teoh produce. This is a product. And the reason for that is because as an intermediate obs draw this over here and read, I'm gonna form this car broke, and I now this has a spare hydrogen off here which can then to draw in blue kind of shift over causing, uh, the car behind on to move the tertiary carbon in a one to hydride shift, making our my major products be on that tertiary carbon. Right? So moving on to ah, to be eso this time we have a slightly different, uh, thing Looks like this HBR this time were a little too far away to do any of those fancy 1 200 shifts. Oh, or even a metal shift. So in this case, you'd expect just a normal reaction. All right, part C, we're going to start with, get this product and there's no need to do any sort of shifting for this one. I simply due to the fact that they're already conform a church here. Carver Cod, eso weaken. Just I expect this to be in a stable product. Uh, D is gonna be a very similar structure where we have the double bond one single way and again you conform a tertiary cardboard cut on here. So there's no need to do any sort of shifting or changing its stability. Uh, so you're actually going to form the same product? Uh, which is kind of exciting, So to move onto Parky eso. Now we've got something that, um he's gonna have another four carbons this time to muffles and then a guy right there. So we're actually going to form a metal shift on this one with addition of HPR eso. What that means is when I add HBR, my final product is actually going to look like come this. And the reason for that is I have Ah, this is an intermedia. And what can happen is since there's no available hydrants to move to a tertiary car back on this whole methyl group can actually shift over, causing the car behind on to be on a metal, but also armature sharing site, but also moving the methyl group completely, which causes are major product to be for him to the way it is. All right, then. Lastly, moving on to f We have something that looks like this. Ah, And again, there's not really a good way to shift this or change this, so we can just expected to add kind of on the edge like that.


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