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Use the sample data and confidence Iavel plvun below comprole parts through (d); dna Vetd holp pravoni blood clota cortaun patonts clinical Irials , ornong 4101 pa...

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Use the sample data and confidence Iavel plvun below comprole parts through (d); dna Vetd holp pravoni blood clota cortaun patonts clinical Irials , ornong 4101 palonta Urojted with renction nausen Construct 99%0 confidence Intorval for thio proportlon Movueu Fuactiona (Round Ihruo docimal placos nuudud } Construct tno confidence intorval;druq; 1944 dovulopud Ihu udvefua(Round thrug decimal places &5 needed )Wrile etaiertent that correcty interprets Ine conlidenco intorval. Choose Ine corre

Use the sample data and confidence Iavel plvun below comprole parts through (d); dna Vetd holp pravoni blood clota cortaun patonts clinical Irials , ornong 4101 palonta Urojted with renction nausen Construct 99%0 confidence Intorval for thio proportlon Movueu Fuactiona (Round Ihruo docimal placos nuudud } Construct tno confidence intorval; druq; 1944 dovulopud Ihu udvefua (Round thrug decimal places &5 needed ) Wrile etaiertent that correcty interprets Ine conlidenco intorval. Choose Ine correct answer below There I5 & 937 chance that the Inuc valuc Ihe populallon proportion wll fall between (he lower bound and [he upper bound 99* samp*@ proportions will fall between the lower bound and the uppor bound: One has 99*X confidence Inal Iha sample proportion oqual Ihu population proponvon: One has 99% confidence that Ine interval from Iha lower bound (0 the uppor bound aclually does contain the true value of tha popuiatlon proponlon



Answers

The confidence interval for the median of a set of values less than or equal to 25 in number can be found by ordering the data from smallest to largest, finding the median, and using Table J. For example, to find the $95 \%$ confidence interval of the true median for $17,19,3,8,10,15,1,23,2,12,$ order the data: $$ 1,2,3,8,10,12,15,17,19,23 $$ From Table $\mathrm{J}$, select $n=10$ and $\alpha=0.05,$ and find the critical value. Use the two-tailed row. In this case, the critical value is $1 .$ Add 1 to this value to get $2 .$ In the ordered list, count from the left two numbers and from the right two numbers, and use these numbers to get the confidence interval, as shown: $$ \begin{array}{l}{1,2,3,8,10,12,15,17,19,23} \\ {2 \leq \mathrm{MD} \leq 19}\end{array} $$ Always add 1 to the number obtained from the table before counting. For example, if the critical value is $3,$ then count 4 values from the left and right. For Exercises 21 through 25 , find the confidence interval of the median, indicated in parentheses, for each set of data. $$ \begin{array}{l}{101,115,143,106,100,142,157,163,155,141,145,} \\ {153,152,147,143,115,164,160,147,150(90 \%)}\end{array} $$

Brooklyn 25 order the data values from the smallest to the largest, just 12 and 14. And 14, 15 and 16 on 17 and 18. And 19, 19 and 21 23 25 27 32 33 35 39 41 42 47. So determined The critical values Imperial and J, using up as equal to 0.5 and then is able to train. So the critical values is even toe find. So K is equal to the critical values plus one. So five plus one, she's six and the boundaries off the confidence in terms for the meeting or then the fix. Smallest value and the sixth largest value. Eso 123456 So the median inbounded between 17 and 33.

Problem. 24. The order. The native values from the smallest to the launches, which is one, 235 and six eight and 10, 15 and 15, 21 24 31 33 41 42 54 and 56 58 and 65 determined the critical value in Table Jane. He was in Alpha's April 2 opening toe all one and then is equal to 19, which is stale, uh, the two tails. So the critical value is April 23 and case equal to the critical value across one which is equal force through the boundaries for the confidence interval for the meeting are then the forces smallest value and the force largest value. So the median funds between five and 54.

A problem. 21. Order the red value from the smallest to the largest. 2346 and nine well, and 15 and 15 and 16 and 18 and 22 25 30. So determined. The critical value in Table J, using ALPA's equal 200% minus 19. 5% which is 5% is offering a five. So the two teams within is equal to 12, so the critical value is equal to two and one with a critical values. Okay is equal to critical value, plus one which is equal to three. So the boundaries off the confidence interval for the median are then the third smallest and the third largest value in the sort of death listed. So the median is bounded between six and it went into

Problem. 23. The order off the data values from the smallest to the largest is 4.24 point five on 4.74 point eight and 5.1 and 5.2 and 5.6 and 6.3, 6.3 and 7.1, 7.2, 7.8 and 8.2, 9.3 and 9.3 and 9.5 on 9.6. So your mind, uh, the critical value in In table using Table J and Alfa is equal to offering to go to and then is equal to 16 toe failed eso. The critical value is equal to two, so the K is equal toe the critical value plus one which is equal to three. So the boundaries off the confidence interval for the median are in the third smallest and the third largest very in the Sorted data, which is a 4.7 and 9.3


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