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4C)Calculate the molarity of the following solutions:a. A sample of NaCl weighing 0.190 grams dissolved in enough water to make 10.0 ml of solutionb. A 7.60 gram sa...

Question

4C)Calculate the molarity of the following solutions:a. A sample of NaCl weighing 0.190 grams dissolved in enough water to make 10.0 ml of solutionb. A 7.60 gram sample of glucose (C H,O ) dissolved in enough water to make a 200 ml solution:25 ml of solution that contains 1.75 grams of potassium sulfate (K SO )d. 4.50 grams of sodium hydroxide (NaOH) dissolved in 300 ml of water;

4C)Calculate the molarity of the following solutions: a. A sample of NaCl weighing 0.190 grams dissolved in enough water to make 10.0 ml of solution b. A 7.60 gram sample of glucose (C H,O ) dissolved in enough water to make a 200 ml solution: 25 ml of solution that contains 1.75 grams of potassium sulfate (K SO ) d. 4.50 grams of sodium hydroxide (NaOH) dissolved in 300 ml of water;



Answers

Calculate the molarity of each of the following: a. 1.00 moles of $\mathrm{NaCl}$ in $10.00 \mathrm{~L}$ of an $\mathrm{NaCl}$ solution b. $7.00 \mathrm{~g}$ of glucose in $10.00 \mathrm{~L}$ of a glucose solution c. $2.95 \mathrm{~g}$ of $\mathrm{KOH}$ in $700 . \mathrm{mL}$ of a KOH solution

So he's problems. Just want us to explore malaria. T in mill. Araji is capital M, and it is the moles over leaders. Pretty, pretty simple. And so the 1st 1 We have 2.0 moles and it tells us that we have. It's in four points years, their leaders and asthma. Larry. So you just do two divided by four and that is 40.5 equals 0.5 00 Because remember your sig figs. You have three here and three here. When you're dividing, you keep the smallest amount of sigfig so three and its capital M. And it's good to glucose Sogo's and a quick tip when you're doing these aren't long conversions in this problem. But when you do have long convergence and you start with, say, like a point two molar solution ah, highly recommend saying that it's a 20.2 moles per leader so that you know what to cancel up that that was a quick tip I have, and the next part we have a 4.0 grams of K o. H. Well, polarity requires us to get into moles. So first we have to use the molar mass But you can you look up or his Bearak periodic table and calculate. But it's 56.11 grams per one mole, and then you could do the next soul. You can see here that you just get rid of the grams and then Nyren moles. And now we can even just continue this chart and say that it tells us that we have 2.0 leaders so you can just take this four divided by 56.11 and then divide by two. And then we do that. That equals 20.35 when 0356 Moller and it's K O. H. So Mueller College and and this is correct Sig Figs as the zero doesn't count. And these next three are the actual account. And the smallest muster figs we have is three. And then for the last one we have five point 85 grams of salt are in a CEO, and again we have to get in the moles. So footballs in the top programs in the bottom, and now you can look it up. Or I would highly recommend on memorizing this one because it's very common, 58.44 grams for one mole. The grams cancel again, and they were the same thing. And be careful you're not. It tells us in no leaders, but we have to divide by leaders because that's what Miller it is. It's moles over the leaders, so don't make sure you don't put 400. Here. You have to put 4000.400 leaders, and then you get mulls over leaders. And if you just divide 5.5 divided by these two, you get point 25 zero moller and a quick tip with these things with these charts, what you can do is you can just write each thing as it's in the calculator. In one go, you could do 5.85 divided by five 58.44 and then you conclude to make sure to click, divide again, not multiply, and divide by 0.4. And then you get your answer. 0.250 Moeller and it is a n HCL solution. So in a C. L

This question asks us to calculate each of the following quantities for a It wants the polarity of the solution prepared by diluting 37 mil milliliters of 370.250 Moeller potassium chloride to 150 milliliters. This uses the simple equation. See one of the one equal see to be, too, Um and so we begin with the initial concentration tells us was 0.25 Mueller the initial volume. We're taking his 37 milliliters and does the fall you. The final volume will be 150 milliliters. So you plug in those three parts, divide by 1 50 on both sides to get the second concentration by itself. And that simply gives this 0.617 Miller. So this is the concentration. After you dilute this initial solution to 150 milliliters and B, it wants the polarity of the solution prepared by diluting 25.71 milliliters of 0.706 Mueller ammonium sulfate 2 500 millilitres. It's a very similar set up the initial concentration 5000.706 Moeller the initial volume. 25.71 milliliters the final volume. 500 milliliters. Sulfur seat to, and you get 0.363 Bowler for See It's a little bit more complicated. It tells us that it wants the polarity of sodium ion in a solution made by mixing 3.58 milliliters of 0.348 Moeller sodium chloride with 500 milliliters of 6.81 times, 10 to the negative second Mueller sodium sulfate. And to assume the volumes or additive so we have to do is figure out how many moles sodium ions we get from each of those two solutions. Then divide that by the total volume of the solution to get the polarity of sodium miles. So for the sodium chloride solution, it tells us it was 0.348 bowler or 0.348 miles per leader. We multiply that by the volume, but we need volume units and leaders to cancel out. So we divide this by 1000 so middle leaders and leaders will cancel and then we're left with moles of sodium chloride. But we want moles of sodium ions. So we do this unit conversion for every one mole of sodium chloride. There is one mole of sodium ions because there's one sodium in this formula and then that will cancel. Moles and sodium chloride were left with moles of sodium ions. So from the sodium chloride solution, we will get 0.125 Moles of studying minds now for the sodium sulphate solution and tells us the concentration with 6.81 times 10 to the negative second molar or most per liter. Similarly, we multiply by the volume, but again, we need that leader. So divide by 1000 so the mill leaders and leaders cancel. We're left with moles of sodium sulphate again do a unit conversion, but this time sodium sulfate has to sodium ions per one sodium sulfate, so it's 2 to 1. Moles of sodium sulfate cancel. We're left with moles of sodium ions. So from the sodium sulphate Klute solution, we get 0.681 moles of sodium ions. So to find the concentration of Saudi Iam's sodium ions, we add these two moles together. 0.125 plus points here 681 moles of sodium and we divide by the volume We got 3.58 milliliters from the first solution and 500 from the second. So this is most per mil leaders. We need moles per leader. So we multiplied by 1000 milliliters. Cancel and we're left with moles per leader. And if you do this bath, you would find that the concentration of sodium ions by mixing these 22 solutions is 0.138 Moeller.

All right. The question is we have to find mill arat E, which is small. M. This is also similarity. So it's saying if 55 mill leader off water is added to 25 millimeter off any CL solution which is sodium chloride solution, So dilution Law states that ah, polarity times volume. It calls to new Miller tee times volume. So here from the question, the polarity for sodium chloride is 0.119 m, and then and and the volume is 25 mills. We have to find the new new concentration and to and were given that Ah, 55 mills off water is added to any seal solution. So our total volume, it's gonna be 55 plus 25 is 80 mils. So now if we take from this here from the dilution law, all we gotta do is we gotta find that so we could take that over to the left inside and divide all of this by fee too. So if we do that, our new him to will be the bad kinds that divide by that. And this m here is also called us mole for leader. Okay, Since we all. We have both the units of all human millimeter. It's not necessary right now to convert this to leader. But if we were to have leader here and if we were to have Miller leader here, we have to convert that either to leader or either we could convert that familiar. So am to after you do Cal to do the calculation 0.119 times 25 if I buy 80. So if you want to include the unit, I hear we could do that over here. If so, that's going to be millimeter. That's also being Mueller leader that meal leader and bad militar cancels. So all you would have here would be this divide, right? That so 0.19 times 25 to buy by 80 that's gonna be zero point 3718 one a. And the unit will be this one multiple leader, because this and that has this email in this ML has been canceled. So just do it like that. Okay, so on the other question, it's the same concept. It's just changing the concentration. So it says 125 Mel off water is added to 45.3 male of 0.701 ml sodium hydroxide solution Okay, so for let's suppose Immonen view on this is for sodium hydroxide. So from the question, the the polarity is 0.701 right and notice Volume has been changed. 45.3 45.3 is the volume We have to find that. And now it's saying 125 ml of water is being added to 45.3 of similar concept applies here. Since this is being added here, the concentration will change, but the volume has to be added. So if you were to take if I were to add that that's gonna be 100 70 0.3 million a year. So I'm simply going to change that number here point No, no one. And this is also going to be a multiple leader. Cause more clarity Capital M music close to moles per liter. So way have both of this union on email. So it's just going to cancel. So 45 going pre 80. So that's gonna be 100 70.3. Okay, so that's and that will be cancelled. If you were to multiply that and then divide that it's gonna be seven. No. One times 45.3 to bed. 170.3. So you knew polarity will be 0.1. It 64 You could either right. Bad or you could also read. Begin. It's the same thing. All right, So for the third question, same concept. So what's our new concentration? 125 Mel off 125. Sorry about that. Ah, under 25. So? Ok, so the polarity here, I'm about three point no one. I m and our volume is 125 familiar off. Potassium hydroxide solution. We had to find this number. Now. Notice how much of water is being added here. So 550 meals of water has been added here. So high 50 m mills of water is added to 125 mils of potassium hydroxide. It's so our new new volumes gonna be cross 125. It's going to be 625. So if you will If I were to just copy paste that here in numbers me on and then it's gonna be. So that's going to be 125. This this whole element is off. I seem hydroxide on the mirror and into nominator. 625. So if you were to calculate that 01 came some 125 divided. But it's 625. You have zero point 60 to 62. Okay, 5 50 plus 125 6 75 Oh, I'm so sorry. It should be 6 75 year. Do you add bad number? It's gonna be 6 75 I'm sorry. So if you were to take that new number here, it's a 3.0. On ah, times 125 Divide, raise 675. 0.557 Okay, last but not least so. It's saying 335 mills, 335 mils of water is being added to 7 75 75.3 mills off calcium chloride solution. So if you were to add that up here, let's take care of the volume for since I missed it up in the previous part. 3 35 plus 75. It's going to be 410.3. That's going Teoh new volume. And then here it's, Ah, 75.3 millions. The volume of calcium chloride. So for polarity, it's saying 2.7 That's going to the same concept here. You're gonna plug in the polarity, uh, calcium chloride and then in here 100 there. Okay, 3 35 Oh, no. So it's gonna be 70 5.3. It's going to be. This will be the your addition off the new volume. 710.3. Mills Mills, If you were to calculate at my friend 2.7 times 75.3 D read by 410.3. It's gonna be 0.379 If you were to round that up to second decimal, you could just write it as three point right. That's the end of the day. I wish in law. Thank you so much.

So in this problem, we want to find the mole. Aren t so polarities capital m and the equals the moles divided by the leaders Similarity is a concentration. And so first, for all the problems we have to get moles and leaders and that we can solve. So for the 1st 1 that tells us out, right, that we have 10.5 is use your moles and we have 0.200 leaders and that equals 2.50 Moeller Capital am Glucose is glucose solution Now the next one 73.0 grams of hcl. Now be careful. Don't make don't just divide by V leaders here because we needed in moles. So the molar mass is 36.46 and I would highly recommend either memorizing this one or, uh or you can look it up or your direct able to solve. But it's a good one to memorize, since it's very common. And then since we the grams cancel right here, grams air cancelled then then we want to have Since we have moles on top, we need leaders in the bottom. So we have 2.0 leaders has given in the question and when you, uh, do 73 divided by 36.46 divided by two that equals 1.0 Moeller hcl solution quips. And now on the last one, it's the same thing. Both anyway. H you have 30.0 grams of n a o. H. And again like BHL one above. Use more master 9.99 grams per one more And then again, this time it says 315 milliliters. But we need it in leaders so we can just do a quick virgin Our head witches 3.350 leaders is through an 30 milliliters. So you put that they're making most of leaders because the grams will cancel again and then the equals 2.14 Moeller and in which


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