5

State the shape of a molecule whose central atom is surrounded by:(a) Two regions of electron density(b) Three regions of electron density(c) Four regions of electr...

Question

State the shape of a molecule whose central atom is surrounded by:(a) Two regions of electron density(b) Three regions of electron density(c) Four regions of electron density

State the shape of a molecule whose central atom is surrounded by: (a) Two regions of electron density (b) Three regions of electron density (c) Four regions of electron density



Answers

List the correct electron and molecular geometries that correspond to
each set of electron groups around the central atom of a molecule.
\begin{equation}\begin{array}{l}{\text { a. four electron groups overall; three bonding groups and one lone pair }} \\ {\text { b. four electron groups overall; two bonding groups and two lone pair }} \\ {\text { c. five electron groups overall; four bonding groups and one lone pair }} \\ {\text { d. five electron groups overall; three bonding groups and two lone pairs }}\end{array}\end{equation}\begin{equation}\begin{array}{l}{\text { e. five electron groups overall; two bonding groups and three lone pairs }} \\ {\text { f. sixe electron groups overall; five bonding groups and one lone pair }} \\ {\text { g. six electron groups overall; four bonding groups and two lone pairs }}\end{array}\end{equation}

This question wants us to give the electron demon and geometries off a molecule that has fallen electron German on the central atom. A four bonding, the man and no no funding demands of Paul Bunyan and no, no London. Okay, so that is gonna be You have Santa Hajto. He you have fall on surrounded. And no, nobody in transit insists Tetra Hydra is, um Are you bonding? And, uh, tuna abundant. So if you have to leave on them So I say we have a you have to leave London and June on bonding. Okay, so this is some tea ship. Oh, sorry. This this looks like a sea so that, uh, we need since this, uh, nobody an electron doesn't mean to disappear. We're not sure enough. Underpaid. So this is T shit. Okay, Next one is, um, five bonding and one number pundits of fight Wonder And one no. London. So this is gonna be a buy. Bonds one shape 1234 by. And they're one number on them. Della's pair and one number bonding domain. So the molecular and a man is going to be see? Yeah, well, you know, the man is going to be helpful. He drum and then electron. Domini says squall. Sure. The, um the the electron. The menace off the hydrant and dandy. Ask the molecule at the many score Pyramid. No, I think this is too. Number one pair. Okay, so there's two number on the pair. They can t shirt to be the Monica Benjamin tree. And try and Ghana, by pure amine is the electron dummy. Yes. You turned to me, then, Uh, day is, um, four bonding and two non bonding. So if we have here for bonding and to numb bonding, so do you. Geometry is, uh he drunk Me, um electron German tree, Dominus After he drunk. And Monique you Jim, a tree is, uh, school play now.

All right, guys, We're going to be doing problem number twenty four of chapter nine in chemistry. The Central Science. So they want us to find the electron to Mae Gentry. And like the gentry of molecule that has the following election, the following is like trying to make it on its central idea. So three bonding demands and no non bonding domains. So we're going toe a in the middle, and we're going to be a three bonding domains. So we're going to have X here, bonded here, so that means that s so if we have three bonding and no non bonding funding than the electron domain geometry is going to be Well, first of all, if there no loon pairs on our central Adam, then our electron domain geometry is going to be equivalent to our to our molecular geometry. So that means that in this case are less under main geometry and our electric Gemma is going to be tribunal plainer from be, we're gonna have three bonding domains and one non bonding domain. So So we're going in the center and three exes bond to it and one lone pair, so we're gonna have so for electron domain geometry. We have four electron domains. Ain't three bombing on one non bonding. So then it's are electrons remain. Geometry is going to be Tetra Hydro and our molecular geometry that's going to be that's going to be triggered. Hope your middle. Now for sea, we're gonna have to bonding domains into non bonding domains. So eh, so it's fun to ex Adams and two lone Paris, that means E therefore bonding domains. So that means is going to be sorry there, before electron mean so as that means he's going to be Tetra Hydro. That's going to be electron to main geometry and em that if we have to Electra too, two bones and to lymph Paris than I'm really a gem. She's going to bed.

To predict the electron pair geometry and molecular structure of each of the following molecules or Polly Atomic ions. We must first draw the Louis structure. Then, from the Lewis structure, using the Vesper model, we can determine the electron pair, geometry and molecular structure. The first one is I O F five. Iodine has seven valence electrons. Oxygen has six. Florian has seven. There are five of them, giving us a total of 48 valence electrons. We'll put iodine in the middle, surrounded with five florins and one oxygen that used up 12 valence electrons. So we have 36 left over 36 is just enough to give an octet to everything with iodine having 12 electrons surrounding it. Because iodine can take on an expanded octet more than the eight, it's probably best to reduce the formal charges to double bond the oxygen toe iodine. However, whether you do or don't, the electron group, geometry and molecular structure will stay the same, so I won't this time. We have six electron groups surrounding iodine. Six electron groups corresponds to an electron group geometry of Octa. He'd RL, and because all of them are bonding, the molecular geometry is also octahedron. The next one is P O. C. L. Three. Phosphorus has five valence electrons. Oxygen has six. Chlorine has seven, but there are three of them. Given us a total of 32 valence electrons, we'll put phosphorus in the middle, surrounded with three chlorine and one oxygen. Eight valence electrons were used, so we have 24 left over. That's just enough to given octet to everything, however, because phosphorus can accept an expanded octet. I'm going to double bond it this times to reduce the formal charge on oxygen to zero and phosphorus to zero. Because there are four electron groups were counting the double bond as one group. That's why I refer to call it electron groups rather than electron pairs. So the electron group geometry would be Tetra Hydro with four electron groups. And because they're all bonding single and double bonds, the molecular structure is also Tetra hydro. The next one is sealed to S. C. O. Chlorine has seven valence electrons there, two of them as he has six. Oxygen has six, giving us a total of 26 valence electrons. We'll put selenium in the middle, surround it with two chlorine xenon oxygen used up six valence electrons. We have 20 left over 20 is more than enough to given octet to everything. And again, I'm going to double bond here so I can reduce the formal charge on oxygen to zero and to valence electrons air left over to put a lone pair on selenium. So we have three bonding pairs. Two or single bonds. One is a double bond and alone pair for a total of four electron groups. I guess electron groups not pairs. So four electron groups is Tetra hydro all electron group geometry. And because three of them are bonding with one lone pair that results in a tribunal parameter all molecular structure, the next one is C L S O plus C. L has seven valence electrons. Chlorine has six. I'm sorry. Sulfur has six. Chlorine has seven. Sulfur has six. Oxygen has six minus one because of the plus. One charge gives us a total of 18 valence electrons. We'll put a chlorine and I oxygen around. Sulfur tells us sulfur is the central atom. We used up four valence electrons. We have 14 left over. We can use 12 in order to give oxygen and octet, and again I'll double bond the oxygen, and we still have two left over to put on sulfur, so it now has an octet. There are three electron groups surrounding sulfur. Three electron groups corresponds to an electron group geometry of tribunal plainer because one of them is a lone pair than the molecular geometry is bent or V shaped at 120 degrees. The next one is F two s. O Florian has seven valence electrons there, two of them sulfur has six. Oxygen has six total of 26 valence electrons. We'll put sulfur in the middle because they tell us to put two florins around it and one oxygen. We used up six valence electrons. We have 20 left over. 18 of them could be used to given octet toe all the peripheral atoms. And then we have two left over to put on sulfur, which can accommodate an expanded octet. And again, whether you double bonded the oxygen or not, you'll get the same electron group geometry and molecular structure as I will. We have four electron group surrounding sulfur for electron groups is an electron group, geometry of Tetra Hydro because one of them is a lone pair. We're then going to have a molecular geometry of tribunal parameter. All the next one is N O to minus nitrogen has five valence electrons. Oxygen has six there. Two of them, plus one more because of the one minus charge gives us 18 valence electrons with nitrogen in the middle and two oxygen surrounding it. We've used up four of the 18. We have 14 valence electrons left over. 12 of them can be used to given octet to the peripheral atoms and the last two will go on nitrogen. One of these nitrogen needs to be double bonded in order to I'm sorry, one of these n o bonds needs to be double bonded. It doesn't matter which one. There are two possible resonant structures. This then gives us three electron groups surrounding nitrogen. Three electron groups is an electron group. Geometry of tribunal plainer. When one of them is a lone pair, the molecular structure is bent or V shaped at 120 degrees. Then for the last one, we have s I 044 minus silicone has four valence electrons. Oxygen has six therefore of them, plus Forem, or because of the four minus charge, gives us 32 valence electrons when we put silicone in the middle and the four electrons are four oxygen surrounding it. We've used up eight of the 32 Valence electrons, so we have 24 left over, which is just enough to given octet toe all of the oxygen's. Because there are four electron groups surrounding the silicone, it has the Tetra he'd RL electron group geometry and because all of them are lone pairs, it's I'm sorry. All of them are bonding pairs then the molecular structure is also Tetra Hydro all don't forget to put your brackets and a four minus on the outside.

So the question here us us. What shape do we expect the molecules of the following description? So, for a it states that we have Central Adam with two lone pairs and three bonds, too. Other atoms. So first of all, this indicates that our electron so as we have three bonds into in Paris of three plus two secrets of five which is, of course, our electron domain. So within the veiled shall electron pair propulsion theory. And if we look at the table, five election domains and two lone pairs indicates to us that we have a t shaped. So this is going to be t shaped, um, for be here. It says we have a central Adam to lone pairs and two other bonds. So two plus two equals four of, of course, equal to our equaling tau Elektron domain. So in four electron remains that we have two lone pairs with it, this is going to be a bent or a V shaped same thing. So it's going to be bent geometry and see here gives us a central to lone pairs and four bonds. So to lone pairs plus four, bond is equal to six electron domains, and if it has to lone pairs associated with that, it's going to give us a square plainer geometry. So it's going to be a square plainer, and that would be the geometries to our descriptions here.


Similar Solved Questions

5 answers
The function graphed to the right is of the form y = cos (x - d) or y = sin (x - d), where d is the least positive value Determine the equation of the graph.Choose the correct equation of the graph.0A y =cos3y = sin3y =Cos3y = sin3
The function graphed to the right is of the form y = cos (x - d) or y = sin (x - d), where d is the least positive value Determine the equation of the graph. Choose the correct equation of the graph. 0A y =cos 3 y = sin 3 y =Cos 3 y = sin 3...
5 answers
QUESTION 21The first matc of & piratc ship shoots the noonday Sun with sertantand mnenrgetthcnlteuci clock is 4 PM. (GMi) What are the longitude and |athtude of the ship? J (12pt1tnr couh on Occemozr 21 Thc tirc [ the ships
QUESTION 21 The first matc of & piratc ship shoots the noonday Sun with sertantand mnenrgetthcnlteuci clock is 4 PM. (GMi) What are the longitude and |athtude of the ship? J (12pt1 tnr couh on Occemozr 21 Thc tirc [ the ships...
5 answers
For what valuc or values of a .thc set{(1,01) (0.a.2) (a?01)} forms a basis for R3?A) aer-Xo.1} B) aer- {o.-1} C) ae{-1.0.I} D) a =[ E) aer-{LO.I}Sectiginiz cevabin icaretlercligini gorene kaclar beklevin z Soruyu bos birakmak isterseniz isar5.00 Puan
For what valuc or values of a .thc set {(1,01) (0.a.2) (a?01)} forms a basis for R3? A) aer-Xo.1} B) aer- {o.-1} C) ae{-1.0.I} D) a =[ E) aer-{LO.I} Sectiginiz cevabin icaretlercligini gorene kaclar beklevin z Soruyu bos birakmak isterseniz isar 5.00 Puan...
5 answers
Question 13 (1 point)Find the derivative:Y = Zx 2 Sx3 + 2x01)-14x3 15x2 + 22) 114x1 _ 15x23) `14x 3 _ 15x204)-14x1 . 15x2 + 2
Question 13 (1 point) Find the derivative: Y = Zx 2 Sx3 + 2x 01)-14x3 15x2 + 2 2) 114x1 _ 15x2 3) `14x 3 _ 15x2 04)-14x1 . 15x2 + 2...
5 answers
Find the general solution to the differential equations.$$y^{prime}=yleft(x^{2}+1ight)$$
Find the general solution to the differential equations. $$ y^{prime}=yleft(x^{2}+1 ight) $$...
5 answers
Whats the product in the following reaction?1) DIBALH (1 equiv), -78 *2) Hio"Ph'HOOHOHOHOHCOHCPhPhPhPhPh"
Whats the product in the following reaction? 1) DIBALH (1 equiv), -78 * 2) Hio" Ph' HO OH OH OH OHC OHC Ph Ph Ph Ph Ph"...
1 answers
Solve each system of equations using matrices (row operations). If the system has no solution, say that it is inconsistent. $$ \left\{\begin{array}{r} -4 x+y=5 \\ 2 x-y+z-w=5 \\ z+w=4 \end{array}\right. $$
Solve each system of equations using matrices (row operations). If the system has no solution, say that it is inconsistent. $$ \left\{\begin{array}{r} -4 x+y=5 \\ 2 x-y+z-w=5 \\ z+w=4 \end{array}\right. $$...
5 answers
Let f(x,Y,2) = xy+ z_ X =t+s- 3t, y = 3rt, z = $8_ Use the Chain Rule to calculate the partial derivatives. (Use symbolic notation and fractions where needed Express the answer in terms of independent variables )dfdf dt
Let f(x,Y,2) = xy+ z_ X =t+s- 3t, y = 3rt, z = $8_ Use the Chain Rule to calculate the partial derivatives. (Use symbolic notation and fractions where needed Express the answer in terms of independent variables ) df df dt...
5 answers
Use the table to answer the questions below.Substance HgS (s 02 Hg Hg IsOz4H" (kJ/mol) 58.261.4296.8a) Calculate 4 HPInfor the reaction HgS (s) Oz (g) Hg (I) + 5Oz (g).b) If 5.00 g of HgS are reacted, how many kJ of heat will the reaction release? f.w. (HgS = 232.66 g/mol)
Use the table to answer the questions below. Substance HgS (s 02 Hg Hg IsOz 4H" (kJ/mol) 58.2 61.4 296.8 a) Calculate 4 HPInfor the reaction HgS (s) Oz (g) Hg (I) + 5Oz (g). b) If 5.00 g of HgS are reacted, how many kJ of heat will the reaction release? f.w. (HgS = 232.66 g/mol)...
5 answers
If the Kruskal-Wallis test and one-way analysis of variance are both used with three sets of independent samples, will both tests always result in the same conclusion?
If the Kruskal-Wallis test and one-way analysis of variance are both used with three sets of independent samples, will both tests always result in the same conclusion?...
5 answers
Which of the following substances would you predict to have thehighest ΔHvap?Group of answer choices:CH3ClHClHOCH2CH2OHCH3CH2OHCH3CH2CH2CH3Please include notes so I can use it to study andunderstand better. Thank you!
Which of the following substances would you predict to have the highest ΔHvap? Group of answer choices: CH3Cl HCl HOCH2CH2OH CH3CH2OH CH3CH2CH2CH3 Please include notes so I can use it to study and understand better. Thank you!...
5 answers
See if you can corplete the following table using only what IS on this page Hint: Tio of thc entries are for the same clemenElement Nuclear Symbol Symbol INAtomic Mass Protons Neutrons Electrons Number Number
See if you can corplete the following table using only what IS on this page Hint: Tio of thc entries are for the same clemen Element Nuclear Symbol Symbol IN Atomic Mass Protons Neutrons Electrons Number Number...
5 answers
Determine whether the table represents discrete probability distribution0.25 0 5 0. 15OA NoB) YesQuestion 5 (1 point)Listenchain has 628 outlets in the United States The follow A fast-food restaurant and presents the number of outlets in population and location them by city 628 to test market & new menu outlet is chosen at random from the
Determine whether the table represents discrete probability distribution 0.25 0 5 0. 15 OA No B) Yes Question 5 (1 point) Listen chain has 628 outlets in the United States The follow A fast-food restaurant and presents the number of outlets in population and location them by city 628 to test market ...
5 answers
Use integration by parts fudvJvduintegrate | e sin( 3x)dr. Specify what is your and &
Use integration by parts fudv Jvdu integrate | e sin( 3x)dr. Specify what is your and &...
5 answers
11 Pant ~Bock9 To rector should W (-1.-.6 ) BuTE the given 00# U 1 766) (4Y Hic Sigrs 1 V attempls E This - 1 maenituut H md 4 unt Check my work V SS "tscor}e " that
1 1 Pant ~Bock 9 To rector should W (-1.-.6 ) BuTE the given 00# U 1 766) (4Y Hic Sigrs 1 V attempls E This - 1 maenituut H md 4 unt Check my work V SS "tscor}e " that...

-- 0.021136--