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Led Mechanism Problem: Imines and Enamines wlth Hints and Feedback0 H:HO;H,o;Hzo...

Question

Led Mechanism Problem: Imines and Enamines wlth Hints and Feedback0 H:HO;H,o;Hzo

led Mechanism Problem: Imines and Enamines wlth Hints and Feedback 0 H: HO; H,o; Hzo



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Describe how the diodes in the previous problem should be connected.

So we're looking at Diet Coke noise, and they're pretty larger of natural products that used to derive from four C five ice cream. Instead, join and what we call the head tail fashion and so we want to look at is how they're generate it from what we call General Wrangel Jerry Rangel deal. Jeering a little posse, which is myself synthesized from reaction fantasy of the prostate and I suspension. He'll die Prostate. And so this problem in general is pretty close to 27. I'm Scientology problem 32 but we do want to draw structural gpt and shell out within synthesize tpp from L. A, P p and I. So we would first Hank PP fantasy that prostate always wash well drawing and that would first give us an enemy that that looks like this. But then they get them to find a product of good. What is our GDP?

Hi, everyone. So, 1st 20 you know, this is me till old searing. It is a so called proxy propane from me till Oh, Syria. So we know that there is a long pair present on this option. So these long bad will a tank on hate Johnson. So what Ill Gate is? That's true imprudently data. Yeah, Yeah. Okay. Oak, Syrian. Okay, Positively charged. Plus, we are minus now. This okay? Really A bank. So you kate eight or okay? Yes, to we are ch three. So you know br Yeah, minus the kitchen. A pack on carbon having me think off. Okay, Have it the entire group. You time. Second one is me till old Syrian. Yeah, Russia. Yeah, right. Ch three into all minus if you age. Nope. You know this Give you minus at banks on the less crowded. Citing. Okay, So engage, We do a minus. Yes, it evolved Then this is C H two. See age three. This guy's all minus now. He's all minus abstract hydrogen from good et awaits my Dave. They attack on it. Okay, so what gate kids PP old age. C h t If you're minus attacked a condom ch two Taliban carbon That it's Steri Kelly? Yeah, less him. Very carbon. Um duh carb. Thanks

First of all going D E road. So at the there are two forces D wade and DX, and this is point E of the given diagram in which support Force E Y will be in a forward direction. And from here there is a load of 12 Newtown and we have distance 60 m and this restrains as 3 m in the background. Okay, this is 6 m and this is team meeting. So now taking movement about D which will be quest to zero so we can write e y multiplied by six minus 12 multiplied by nine equals to zero. So from here, magnitude O E. Y is 18 kilometers Newton in upward direction. So this is the answer for the support reaction at point e. Okay, No, consider the equilibrium of forces along the way direction hence we can, right minus d y bless E y minus 12 equals to zero. So from here, minus the white plus 18 minus 12 records to geo. So from here, dy is equal to 6 kg newton and as there is no force along the acceleration so d X will be equal to zero. Okay, so now no, we will grow the part of the city of the given back. The Barbie city of the Given bar will look like this. Okay, this is going to see mhm which have normal relations seaway. And this is the way. And from here we have d X and from here we have to be right. And from here we have B X, and this is uniformly distributed. Load uniformly distributed. Load off 3 kg Newton for meat and distances. This is 4 m and this is to me. Okay, so no, considering equilibrium momentum movements about the weekend, right? Submission of M V equals to zero. So from here, see why multiplied by four plus the way manipulated by six minus 3 to 6 into six by two equals two. So from here we get see way multiplied by four and we have delight equals to six from the above relations So six multiplied by six multiplied by 54 equals two. So from here, C Y is equal to 4.5 kg Newton in a power direction. This is the answer for that support reaction at point C in vertical direction. Okay, so now movie forward. We have who now we will take equilibrium of forces along Extra directions to submission of effects will be close to zero. So from here we can write BX minus d X equals to zero as the T X equals to zero. So from here, B X will also be equals two no taking equilibrium of forces along the Y direction. So submission of f y equals to zero. So from here we can right be right plus c y plus dy minus 3 to 6 equals to zero. So from here B y plus C y is 4.5 kg Newton and dy is six cologne Newton minus 18 g. So from here, the way comes out to be 75 kill you. Okay? No, similarly, we will grow the bar. Maybe this is a bar. This is point A and this is point the Okay, so now we have two forces on a This is a way and this is X and yeah, a moment which is along this direction. So it is, um okay. And we have two forces on the point B, which is one is here. The X and another one is here the way. Okay and the distance from these two points is equals. Two cremated from the geometry. Okay, this is support reaction. So now, considering the colonial forces along, the acceleration we have submission of FX equals to zero. So from here we can write minus b X plus X equals two Jesus. So as B X equals to zero from the other relations. So he calls to chief. Okay, so this is the support creation at it in X direction. So no, considering equilibrium of forces along the Y direction, we get submission of fy calls to zero so we can write minus B Y plus a Y equals two and we have b y equals to 7.5 kilometers from the our relations. So we can write 7.5 plus a Y calls to zero. So from here, anyway, comes out to be 7.5 kg newton in our direction. So this is the answer for the support reaction at a in Y direction. Okay, so no taking moment or about a we get submission of movement about a equals to zero. So from here we can right m e bless B y, manipulated by three equals to zero so from here we can, right. M e plus B y is 7.5 kg Newton from above multiplied by three quarters to So from here he get m equals two minus 22.5 kg Newton meter and the the direction of moment about a will be counterclockwise. So we can write 22.5. Hello, Newton meter in counterclockwise direction. Counterclockwise direction. So this is the moment about 0.8. Okay, so, no, we can summarize the result as X equals to zero. Behave X equals to zero a y equals to 7.5 kg Newton in upward direction and moment about a s equals two 22.5 kg Newton meter in a counterclockwise direction. And at sea we have we have C y close to 4.5 kilo Newton in a forward direction and we have X anyway equals 2 18 kg Newton and again up over direction. So these are the results or the support creations at asked point that is a pharmacy and e. So these are our final isn't. We have simply calculated these results by one by one by drawing free body diagrams of them and by taking moment or balancing force along accent right direction. Okay,

In this problem, I can write the reaction edge. Just look at it carefully. 80 c o h e t c o h. In the action with on reaction with e t MD Biard, we'll keep the compound Urz will give the compound edge e T at so according to the given option Option eight, correct. Therefore, therefore often a age option eight, correct, then said for this problem, therefore, of sunny, correct answer for this problem. I hope you understand the reaction of this problem.


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