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Find the value of the sum_Xj' if X1 =7,X2 = -2,X3 = 9,X4 = -8...

Question

Find the value of the sum_Xj' if X1 =7,X2 = -2,X3 = 9,X4 = -8

Find the value of the sum_ Xj' if X1 =7,X2 = -2,X3 = 9,X4 = -8



Answers

Find the value of the indicated sum. $$\sum_{l=3}^{8}(l+1)^{2}$$

We work to find to force plus three eight raped here, we can see that the denominator can have in common number if we take to four times to on the numerator and times to on the denominator. We can reevaluate, Thin says for eight. And then we can go back to a problem and do. For AIDS plus three, AIDS is equal to 78

All right, so the atnegative eight plus negative three. So what I'm gonna do is I'm gonna just switch these songs because adding a negative is the same thing. It's attracting a positive. So a new one is gonna be negative. Eight. Momus. Very well. I'm gonna go back to the left, so I'm gonna go negative eight. Negative. Mom made a tanned negative. 11. So 123 And this gives Ah, negative 11.

So for this problem, I'm starting at negative. Three are three. Uh huh. Class negative. Eight. So, again, because of order of operation, I'm doing my brackets, parentheses and group B symbols first. So I have negative three. Plus, this becomes negative. Five, if you need to see it visually, remember, you're starting at 03 So this is positive three, and you're adding a negative. So you're moving to the left eight times. If you move eight, that's really three. You're gonna go past to the negative site. So this is That's why it's negative five. And then my next step, When I have two negatives together, I at them and I keep my negative science. So this is negative. Eight. If you need to see it in the number line again, I'm starting at negative three. And I'm adding a negative, some adding that way. Five. So that takes me all the way. So negative eight

Hey guys. So here this expression and we want to find the some of these two integers. And the first thing that we're going to do is we're going to look at the sign of these two integers and so, looking at expression, we see that we're adding to negative integers together. And when you add a negative plus another negative, you're always going to get a negative answer. And that's true for any numbers that you use. And so we can do now is we're going to add the absolute values of R two integers. So we do the absolute value of negative three, plus the absolute value of negative eight. And that gives us 11. However, like I just told you, when you have a negative plus and negative, you're always going to have a negative answer. So that means our answer is going to be negative. 11


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