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AMet (1 mM)Control10410410310311.0%%98 LB 40102102101 10' (%) 30 6.11% 7.36% 100 100 rate ool 101 102 103 104 ool 101 102 103 104 20 PI Met (10 mM) Met (20 mM)...

Question

AMet (1 mM)Control10410410310311.0%%98 LB 40102102101 10' (%) 30 6.11% 7.36% 100 100 rate ool 101 102 103 104 ool 101 102 103 104 20 PI Met (10 mM) Met (20 mM) Apoptotic 104 104 10 103 10313.1%%8'0z102102Control mM) mM) mM) Met 3 29 ` Met Met 10110'10.1% 6.96% 109 109 100 101 102 103 104 100 101 102 103 104Annexin V

A Met (1 mM) Control 104 104 103 103 11.0% %98 L B 40 102 102 101 10' (%) 30 6.11% 7.36% 100 100 rate ool 101 102 103 104 ool 101 102 103 104 20 PI Met (10 mM) Met (20 mM) Apoptotic 104 104 10 103 103 13.1% %8'0z 102 102 Control mM) mM) mM) Met 3 29 ` Met Met 101 10' 10.1% 6.96% 109 109 100 101 102 103 104 100 101 102 103 104 Annexin V



Answers

Arrange the following in descending order: a. $10 \mathrm{~cm}$ b. $1 \mathrm{~m}$ c. $100 \mathrm{~mm}$ d. $1 \mathrm{~km}$

So our model, once we put our data in, we find out comes out to be this and we'll show what those input variables are here in just a second. This is the length of the arbor chair in centimeters and this is the girth, so the circumference around in centimeters as well. And our lowest value is 1 24 for the input and the highest looks like it's about 100 and 68. So part A. We can input 140. And I actually have the equation I have, I have the graph of the data graft and there does appear to be just a little bit of a Kirby situation here and have the graph line up and then I'm going to go to value under second and calculate and I can plug in each of these values. When I type in 1 40 I find out that my equation would predict 107.4 for the girth for part B. Though plugging in 1 72 1 72 is outside the domain. So that's not meaningful for this because it's extrapolating PART C. In putting 164 that's within the domain. So again, I can do second value and second function or second calculating value and type in 1 64. And that predicts that the girth would be 123.8 centimeters. And then for part D, if we had a length of 158 centimeters, second calculate and the value and plugging in 1 58 tells me it would predict that the girth is 119.7 centimeters.

So in this problem We need to determine how many mm there are at 1.35 ft. So We're going to set up dimensional analysis. So we have 1.35 ft. We're going to pervert that two and were given that there are 36.3" in a meter. So we're going to use that as a conversion factor as well. And then we're going to convert m two from off my 5000. So the math will be 1.3412 divided by 36.3 times 1000. And we end up getting this as the answer. So as long as our us cancel out to give us the units that we are looking for, we know that we are calculating this correct. So now let's rewrite this in scientific notation. You exported on 10 is positive because we have to move the decimal place two places to the right. But that's what needs to be after the first digit. So You can see that if we move the decimal place to place to the right, we get 443. So among the answer choices, you'll see that this is answer choice A We're picking the answer choice. Be sure that you are picking the one with the correct form of scientific notation and the decimal place needs to be in the correct place

Well, everyone, this is Ricky and they were working on a problem. Five from a model test number six. And so this is a question asking us about sphere that's inscribed in a cube. And what the ratio of the falling sphere to the booth. All right, So to start this question, let's write down the formulas for both of our severe and for acute first fear, 4/3 choir cute. And for the volume of the Cube, a heart issues this will rather Cuba's the length aside. Yes, threes as cute. And then, if we translate this where the length of side ISS equal to the radius spear, get or rather the diameter of the spear, get what you are. That's a cute Wallace to paint way Now if we look at the ratio votes spear. Q. Start with Why are huge? Huge. You see that? Ready? I drop out. And for my what a fine two. Everything's fine Pi over 63.14 over six, which is about 0.52 I hope this video is helpful. Seeing that

So for part A. Here we have 7.59 times 10 to the seven meters. We can rewrite this as 75.9 times 10 to the six meters and then that could be re written as 75.9 maggot meters. Since one mega meter is tend to the six meters and then we can use the same process for the rest. For part B, you have 0.74 meters. That can be rewritten as 7.4 times 10 to the negative three meters, which is equal to 7.4 millimeters since one millimeter is 10 to the minus three meters. For part C, we have 8.8 times 10 to the negative 11 meters. That can be rewritten as 88 times 10 to the negative 12 meters, which is equal to 88 PICO meters. Since one PICO meter is 10 to the minus 12 meters and then finally for Part D, you have 1.63 times 10 to the 13 meters which we can rewrite as 16.3 times, 10 to the 12 meters, which is equal to 16.3 tera meters since one terra meter is tend to the 12 meters


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