5

Match the cquilibrium constant (Kc) values with the descriptions of the reactions 5.7 x 10*5 2.8 * 10' 13x 40 7 81x 10-9 no decemable reaction takes placeequi...

Question

Match the cquilibrium constant (Kc) values with the descriptions of the reactions 5.7 x 10*5 2.8 * 10' 13x 40 7 81x 10-9 no decemable reaction takes placeequilibrium that favors productsequilibrium that favors reactantsrcaction gocs to completion

Match the cquilibrium constant (Kc) values with the descriptions of the reactions 5.7 x 10*5 2.8 * 10' 13x 40 7 81x 10-9 no decemable reaction takes place equilibrium that favors products equilibrium that favors reactants rcaction gocs to completion



Answers

Estimate the value of the equilibrium constant at 525 K for each reaction in Problem 73.

All right. Hello, everybody. Today we're going to be finding the equilibrium concentrations for some reaction. So let's get right into our first reaction is to seal minus plus B R. Two giving us seal to gas and to be armed. All right, pretty simple. Let's first make our half reaction. So starting with the chlorine of to seal minus a quiz produces cl to gas. We have, ah, negative to charge on the left side. So we're gonna add in two electrons on the right side. Easy does our second reaction with our bro me br to liquid produces two br minus a quiz. We have, ah, negative to charge on the right side. So we're gonna add in two electrons on the left. Easy and everything balances out two electrons on both sides. Um, you'll notice our topside electrons on the right. That means oxidation. And for bottom half reaction, electrons on the left means reduction. All right, now, let's look at our e. Not about so r e not for the reduction of, um, for the reduction of seal, too is equal to 1.36 volts. And are he not for the reduction off br to is equal to 1.8 volts, obviously are sealed to is being oxidized. So are you not for theocracy? Gatien of two c l minus is gonna be the negative off our reduction of seal to which is negative 1.36 polls adding them all together we get r e not total is equal to, um negative 1.36 folds plus 1.8 wolves, which gives us a sum total of sorry. I'm in a little bit of a break. Um, which gives us a sum total of negative zero point to eat. Awesome. All right, the finder equilibrium concentration. We just use our variant of nurse law, which says that l and Q Q being our equilibrium is equal to N e. Not over 0.257 Very handy with liquid. So we know and is too, because from up here we have two electrons being transferred so me of two times negative 0.28 over 0.257 which ultimately ends up giving us an equilibrium constant of negative 21.8. Uh, sorry. That's not actually the equilibrium constant because we still have our Ln que here, so q is gonna be equal to e to the negative 21.8, which will actually end up giving us 3.4 times 10 to the negative. All right. Um, and because our Q is less than one, that means that this reaction does not favor the products are you know, it favors the reactions. Awesome. All right, let's move on to our next one. Okay, so now we have f e two. Plus a curious plus a G plus a curious giving us f e three plus agrees. And Eiji solid. So strict. Us down we have are 2/2 reactions. F b two plus two feet three plus, um, we have a greater charge on our right side, so we need to add in one electron to fix that on the But on our second half reaction, we have 80 plus a quiz becoming a G solid and extra charge on our left side. So add in one electron to fix that. We have one electron in both half reactions, So we're going on that count. Okay, let's move on to our e nuts. So I e not original for F E three plus is going to be equal to 0.771 worlds. Um, coming back up here kind of forgot. Electrons on the right means oxidation. And for a second half reaction, electrons on left means reduction. All right, since this is since our first half reaction is oxidation, that means that 0.771 is actually going to be negative. 0.771 Meanwhile, there are e not for, um our silver is 0.799 horribles. That's the same because it's that stays the same, because of which means I e not total is going to be equal to 0.7994 volts minus 0.771 bolts, which is gonna be equal to 0.2 uh, eight volts. Notice we leave off this four cause of sick fix as All right. So now let's use our version of Nor Inslaw again. We have Ellen Q equals Andy. Not over a 0.257 Which is going to be our end is one, because one electron over here r e not is 0.2 a and over a 0.257 Which gives us e not our Sorry, None. Nina. A value of 1.0. Not in, actually. My bet. That should be 1.1 due to 666 Therefore, our Q is gonna be equal to e to the power of 1.1, which is 3.0 since our Q is greater than one. Therefore, this reaction does saver the products. Awesome. So that's your answer. Thank you very much. Have a good day.

In this question I've been asked to determine the equilibrium question K. And since we are dealing with state functions, thermodynamic state functions we can use the expression standard keeps energy change is equal to negative Paracin Lynn K. And this is our equilibrium constant that we're looking. So making K substitute formula we get cape being equal to the exponent of negative and it gives energy change divided by our routine. So the main goal here in the first part of the question is to just remind this standard gives energy change and we know this to be and that gives energy change can be calculated from standard and they will be changed minus T. Multiplied by standard entropy change. So since we are dealing with state functions for example for these two we can use this expression to say for example the standard entropy change is equal to the sum of the entropy changes of formation of the reactions of the product minus the sum of and that entropy change of formation of the reactions. And we always have to make sure that we multiply by the respective strict geometric coefficient because these expressions or these parameters are always given in Permal of substance. So we always have to make sure that we multiply by the respective documentary coefficient. Now applying this, we can use the same expression on the standard entropy change. So are playing this would get this from our data booklets all appendices. This is going to be one, one More of product, multiplied by 9.16 Multiple miners to multiplied by three 3.2. So this gives us a standard entropy change of negative 57 point 24 and the season tell a joke. Then we can do the same for the standard entropy change. This is equal to one more. Multiplied by The entropy change which is equal to 304 0.4 minus two moles. Multiplied by 240.1. And this is going to be equal to negative 175 .8. And this is in Joel's pair. No. Now that we have our standard entropy change and our standard entropy change. We can then use this formula to take your mind there. Standard keeps energy change and we take the standard gives energy change and plug it in here to finally get our equilibrium constant. So the standard keeps energy change to achieve standard is equal to negative five 7.25. This is in college also. We multiply by 10 to the poetry to get it in jewels because our standard entropy changes also in job. So this multiplied by there should be minus our temperature which is 655 Kelvin Multiplied by the entropy change which is negative. one point Okay, so our deal turkey standard. It's going to be equal to 5.7 Times 10 to the powerful. Sure what? This tells us. We have a standard mm Then that keeps energy change. That is greater than zero. So it tells us that under standard conditions this reaction is not spontaneous. It needs an external force or external source of energy for it to kicks that all to initially get it, get a drink. So now that we have our delta G standard. We then use this formula, this initial formula here to determine our equilibrium constant K. So our K. is going to be equal to the exponent of negative 5.7 to extend to the powerful divided by Uh which is 8.314. Multiplied by the temperature of 655 Children. So our K here is going to be equal to 2.41 multiplied by 10 to the power negative what? So we do the same for remaining part of the question that is we calculate the standard and then change this is equal to two, multiplied by wonderful 26 -1. 30.9 When there's one multiplied by zero, this is zero. Because understand that conditions for a pure element this standard and they'll be changing formation is zero because all of these are referenced under Few elements. eight standard condition This is going to be equal to negative 1.7. So for this one to calculate our standard, let's first of all calculate our standard standard gives energy change. If we use this formula we're going to get to Want to play it by -1 one, multiplied by 3.1 -1, multiplied by zero To get a negative 5.1 killer job. And for us to then get delta is the standard entropy change. This is going to be the entropy change -1.7 times 20 poetry Miners. The standard keeps energy change off negative 5.1 times 10 to the power three divided by two nine. was These are standard conditions at 25° sources here. What we're doing we are using this formula. Yeah. To data mine our standard entropy chain. So now that we have our standard entropy change, this is equal to standard entropy change is equal trump 11.404 in Joel's pair. Sure. So now that we have this you can then use this formula again to say to achieve is equal to delta age standard minus t daughter is standard. Now this is now going to be evaluated at a temperature of six. Quite fine. Remember all this what we're doing here. We're evaluating these under standard conditions of 25 Degrees sources. So now we want to account for the temperature that we've been given Which is 255 kills. So we can then say it all to change standard is equal to -1.7. to understand to the poetry -655 multiplied by 1 1.40. Sure. So our delta chief standard he is going to be equal to negative 9.1 from stand to the power trade in job. Now that we have our don't Turkey, we then use this formula to get our equilibrium constant, so our equilibrium constant K is going to be the exponents of negative Gibbs, which is negative 9.1 times 10 to the power train, divided by our great point 314 Times 655. So our K is going to be equal to five point then.

Hey, guys, Lives three problem three. In this problem, we need to calculate they believe one constant want to give in reactions. You know, the relationship between the standard free energy change and the Caribbean constant is given by this situation and particularly Bram. The standard free energy change is going to zero. Therefore, we can write down the relation between the Libyan constant and mm, that stranded free energy s this one. Okay, it will be premises. You can draw exponential. Negative. The standard financial change divided very hearty. And the gas constant is a country eight point. Human jewels. Children in verse one mole in verse one. The temperature is given us 25 researchers. Let's converted to kill Venice compared to 73. So we get to 98 Kelvin. Okay. Now, to populate the first, uh, the liberal constant from the first reaction, which is glucose six phosphate is converting to glucose. If we look at the chart, we'll get that this standard, friend and you change is given us negative. Starting 0.8. Kill a June farm one. Let's converted to Julia. You know, jewelry, jewel by multiplying by 1000, so we get 1308 100 13,800 jewels. Family. Now we can calculate what is the equilibrium constant? Then K equals music and do ex woman shin negative negative harden. Come on, Given the way the gas constant reaches eight, pointed few on you. Molin her son Kevin Anderson wanted by by that temperature to 90 87. So when we do this calculation, we will get Explanation 1300 100,088 divided by 2477.29 and we will get the relevant living constants to 62. Therefore, developed the liberal constant for the reaction A, which is a conversion off glucose six phosphate to glucose at 25 degrees Celsius and page seventies to 62. This is the Libyan constant. Let's go to the second one. Congressional reflectors, toe glucose and the electors in this case, the guest. Constant ease. 15. Negative 15.9 individual family lives converted to Jill per month. 15,900 joules per month. No, we can inside to the values and what we get is the value is explanation. 6.42 Explanation 6.42 gives US 600 15, therefore they could live in constant for the convention off letters to glucose and realtors at 25 reviews, searches and page 7600 and 15 now the final one conversion off Malek to figure it. In this case, the standard for energy changes 3.1 you know, just permanent or 3100 Jews per month live since onto the values here, which gives us exponential negative 1.25 and develop explanation with 1.25 years. 0.29 Therefore, the equilibrium constant for the conversion off Maliti Favorite 25 give you Celsius and which seventies? Zero point.

For this question. We need to know how to identify whether a equation is in a favor off the formation of products or react in space on their equilibrium. Constant So we know what I'd equilibrium constantly say it as this. And it's basically the ratio off, the concentration of product and the concentration of the reactant. And if the ratio is bigger than one, that means it's in the favor of product information. Because the ratio is bigger than one. That means the topside, a speaker in the bottom side. So there are more product formation than the formation of reacted. And if K is lesson one, that means it's in favor of production of reactive. And so if we look at the numbers given, we look for the numbers that bigger than one. And those are the equations that are in favor of formation of products, and the rest are in the favor of formation off reactant. So for B and C, they are number is bigger than one. That means they're in favor of information of product, and the rest A. D and E are in favor of Formacion. Off reacted


Similar Solved Questions

5 answers
GEOMETRYSurface area of a sphereThe radius R of a sphere is 4.8 cm, Calculate the sphere's surface area AjUse the value 3.14 for T, and round your answer to the nearest tenth_A = 0 cm2
GEOMETRY Surface area of a sphere The radius R of a sphere is 4.8 cm, Calculate the sphere's surface area Aj Use the value 3.14 for T, and round your answer to the nearest tenth_ A = 0 cm 2...
3 answers
U Anstede States thal Americans the the and 1 approval 1 "5 the Wi ainong the job of the 1 the sample of5 the"Pr # We President What randomlv
U Anstede States thal Americans the the and 1 approval 1 "5 the Wi ainong the job of the 1 the sample of5 the"Pr # We President What randomlv...
5 answers
S) Circle #he i0,1 each pav that mof € stabl Use arematre t jutify Yewr felfctidnj Ans 7Ja bl t Jfb l-U
s) Circle #he i0,1 each pav that mof € stabl Use arematre t jutify Yewr felfctidnj Ans 7Ja bl t Jfb l-U...
5 answers
Calculate the_molurity of acctie acid solutionAssuming the density of vinegar used is O0Sg/ml , determine the muss_S vinegar used in gramnsf: Determine the mass ofaccticacid in the vinegar sample (Molar mass of = acetic acid 60 gImol)Determine the mass perccnt of acctic acid in the vincgar soluti %o(m/m)h: Calculate the percenlage crror in the experimental value of mass % of acetic acid
Calculate the_molurity of acctie acid solution Assuming the density of vinegar used is O0Sg/ml , determine the muss_S vinegar used in gramns f: Determine the mass ofaccticacid in the vinegar sample (Molar mass of = acetic acid 60 gImol) Determine the mass perccnt of acctic acid in the vincgar soluti...
5 answers
Let a € RnThe average of the elements of a isavg(a) = 11a nThe root-mean-square (RMS) value:az + + az Ilall rms(a) = = n VnQ Show thatlavg(a)l < rms(a)
Let a € Rn The average of the elements of a is avg(a) = 11a n The root-mean-square (RMS) value: az + + az Ilall rms(a) = = n Vn Q Show that lavg(a)l < rms(a)...
5 answers
Given that standard normal random variable_ compute the following probabilities (to decimals)- Use Table in AppendixP(-1.98 < 2 < 49)0.6416b: P(.52 <2 < 1.22)0.1773
Given that standard normal random variable_ compute the following probabilities (to decimals)- Use Table in Appendix P(-1.98 < 2 < 49) 0.6416 b: P(.52 <2 < 1.22) 0.1773...
5 answers
Worker 1Old Method New Method 32 35 37 31 35 29 28 25 41 34 44 40 35 27 31 32 34 312 3 s { 9
Worker 1 Old Method New Method 32 35 37 31 35 29 28 25 41 34 44 40 35 27 31 32 34 31 2 3 s { 9...
5 answers
40 ElEln cotlec -In[ secz] HcAuestcn FlaaEpol Joano Panpew2 + 4, Inksine] % Select one:Enswered Hakhaly WonkangiZzootzdn
40 El Eln cotlec -In[ secz] Hc Auestcn Flaa Epol Joano Panpew 2 + 4, Inksine] % Select one: Enswered Hakhaly Wonkangi Zzootzdn...
5 answers
Vwntningjon Z0 0120 Raint) Alemp: 2 el 5Jlnd the probability that if 8 different-sized Washers are arrenged in row; theybe arranged in order of sizeEnter your answer &s & fraction or round to the first nonzero decimal; P(8 in order of size) -
Vwntningjon Z0 0120 Raint) Alemp: 2 el 5 Jlnd the probability that if 8 different-sized Washers are arrenged in row; they be arranged in order of size Enter your answer &s & fraction or round to the first nonzero decimal; P(8 in order of size) -...
5 answers
Use the Quotient Rule to find the derivative of the function. g(x) 9 sin x9(x)cos(x) sin (x
Use the Quotient Rule to find the derivative of the function. g(x) 9 sin x 9(x) cos(x) sin (x...
5 answers
Aminophylline is infusing at 30 mL/hr: The drug is mixed 250 mg in 500 mL DsW: How many mg/hour is the client receiving?Answer:
Aminophylline is infusing at 30 mL/hr: The drug is mixed 250 mg in 500 mL DsW: How many mg/hour is the client receiving? Answer:...
1 answers
A home purchased for $\$ 140,000$ increases in value by $5 \%$ per year. a) Find the general term of the geometric sequence that models the future value of the house. b) How much is the home worth 8 yr after it is purchased? (Hint: Think carefully about what number to substitute for $n .$ ) Round the answer to the nearest dollar.
A home purchased for $\$ 140,000$ increases in value by $5 \%$ per year. a) Find the general term of the geometric sequence that models the future value of the house. b) How much is the home worth 8 yr after it is purchased? (Hint: Think carefully about what number to substitute for $n .$ ) Round th...
5 answers
Solve.What percent of 68 is $17 ?$
Solve. What percent of 68 is $17 ?$...
5 answers
Use the matrices below to answer the question ~4 3 0 c = [2 D = 51 5 T 3 d 2Let Q = CD if defined find Matrix Q
Use the matrices below to answer the question ~4 3 0 c = [2 D = 51 5 T 3 d 2 Let Q = CD if defined find Matrix Q...
5 answers
10. Find the determinant of matrix What does the value of the determinant tell you about both the rank and the nullity of 4? What does it tell you about the system Ax where b is any column vector from RJ?
10. Find the determinant of matrix What does the value of the determinant tell you about both the rank and the nullity of 4? What does it tell you about the system Ax where b is any column vector from RJ?...

-- 0.019086--