5

8 Exercise 2: Using iabid diat Kstnucturo 13 clcmenurtas 2 ol Ine H M 1 ncig noi use d Ina lodO 1 comdounas: 1 1 1 ID crowt { Irucluralommulas cncminny 1 F DUMcmid ...

Question

8 Exercise 2: Using iabid diat Kstnucturo 13 clcmenurtas 2 ol Ine H M 1 ncig noi use d Ina lodO 1 comdounas: 1 1 1 ID crowt { Irucluralommulas cncminny 1 F DUMcmid E J Ocir1Dumoici coreouc

8 Exercise 2: Using iabid diat Kstnucturo 1 3 clcmenurtas 2 ol Ine H M 1 ncig noi use d Ina lodO 1 comdounas: 1 1 1 ID crowt { Irucluralommulas cncminny 1 F DUMcmid E J Ocir 1 Dumoici coreouc



Answers

$[\mathbf{M}]$ In Exercises $14-17,$ follow the instructions given for Exercises $3-6 .$
$$
4 x_{1}^{2}-6 x_{1} x_{2}-10 x_{1} x_{3}-10 x_{1} x_{4}-6 x_{2} x_{3}-6 x_{2} x_{4}-2 x_{3} x_{4}
$$

So here we have this matrix and we are asked to find M 13. Now, this will be a minor of this matrix and this minor can be found by deleting the corresponding rows and columns. The one here tells us that we must delete row one. So we delete all of these elements. The three here tells us that we must elite. Call him three. So we delete all of these elements. The remaining elements form M 13 which are four native 75 and eight. We can find this determined by multiplying diagnosis. So we have four times eight minus five times that you have seven. So in a 32 plus 35 and we get 67 so this minor has a value of 67.

So here we have this matrix A and we asked to find M 21 or a minor 21. In order, find the minor. We must delete the rows and columns that are given to us. So the two here tells us that we must elite row too. So we delete all of this and the one here tells us that we must delete. Call it one. Now the minor is simply the elements that are left or native to a 39 And we can easily find the determined of this. So it's simply native two times nine by us to be times it. So we have native 18 my ass 24. So we add the two together. So negative 18 by eso 24. So we get negative 42 as this minor

So here we have a matrix and we are asked to find the minor. Um, 33. We can find this minor by deleting the corresponding rows and columns. The three here tells us that we must elite row three. So that would be all of these elements. The three here tells us that we must delete Call him three. So that would be all of these elements. So I am 33 is simply one for negative. 25 Now we can find this. Determine it. So we multiply diagonally and subtract. So we had up with five minus native aid or five plus eight and we get 13. It's the value of this minor is 13.

So in this question we have to make two transformations to our one plus Arto Onda minus r one plus R three. So here, only the first tour event as it is untainted. Oneto one toe this will become a zero. Do those are four minus one That this three This is two plus before And this five plus for their this main He had a vin one minus 10 three miners toe that is one minus two minus on that this minus three and minus eight minus. So that is my understanding. So that is my


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