5

Question 2Question 2 LOI, PO2, C3Solve the magnitude ud cosine angles of Fz shown in Fig Q2, if the resultant of forces is,F= 6501 250] -JoOk [24 marks]Fi=650Fig: Q...

Question

Question 2Question 2 LOI, PO2, C3Solve the magnitude ud cosine angles of Fz shown in Fig Q2, if the resultant of forces is,F= 6501 250] -JoOk [24 marks]Fi=650Fig: Q2Enter your answer

Question 2 Question 2 LOI, PO2, C3 Solve the magnitude ud cosine angles of Fz shown in Fig Q2, if the resultant of forces is,F= 6501 250] -JoOk [24 marks] Fi=650 Fig: Q2 Enter your answer



Answers

Find the angle between the forces given the magnitude of their resultant. (Hint: Write force 1 as a vector in the direction of the positive $x$ -axis and force 2 as a vector at an angle $\theta$ with the positive $x$ -axis.). Force 1:3000 pounds Force 2:1000 pounds Resultant Force:3750 pounds

In the given forces. The magnet deal on the debt off their resulting was given. We have to find the angle between the forces. So 45 is equal before the fight. Causey Data cause zero I plus 45 sign zero. Let's take the Trans victor zero Victor at zero degrees. So this is the reference. So no second, this sixties equals 60 course They die Bluff 69 Peter. So the resultant there's nothing more. Fortify a last 60 cost data I 60 scientific data with resultant within a month 90. The big will do 45 plus 60 cost eater with a smart if I plus 60 scientist who was quick. So this is solving this reading. 100 would be 45 60 Cost data holds girl plus Gator Whole script solving this they will get cost dollars Week will do 8100 minus 56 Go fight by 54 The busy So does cause in Verceles This 8100 minus Phi 65. My five For the busy never sequel. He doesn't 62 1 72 degrees

So in this problem we have a screw. I. And two forces F. One and F. Two are acting on the screw. I. We're tasked with finding the magnitude and direction of force to given given the magnitude and direction of the resultant force between F. One and F. Two. So I told F one has a magnitude of £80 and it's just along the positive Y axis. We're told that A result enforces the magnitude of £150 and it forms 100 20 degree angle with the X. Axis and 130 degrees with the negative Y axis. And we don't know any information about F. two. And that's what we're trying to figure out. So we actually start off by just running off our information What we currently know. So for F. one you can break this up into all of its X. Y and Z. Components. So because it's purely along the Y axis, there's no X. Component to it. Everything is just along the Y axis and the Y component For F two. We don't know anything about this yet. So some by your ex somebody Y and some values he and lastly for fr no we don't really know right now what all those components are but we can figure them out because we're given the angle and the magnitude. So frX, sorry, frX equals fr magnitude of fr times a co sign. And for exits alpha, right. And that's just the angle between the force and the X axis and it's the same thing for Y and Z. But if we plug in 120° in the alpha and £150 into fr you determine that forex Equals -75. You can write that in here, so negative 75. I okay, next, we'll move on to why? So um f r Y is equal to beat the same process, magnitude of fr times the co sign. Uh in this case it's going to be 130° and it's just it's bad in here. So you plug in a 130° and 150 for fr and F r Y about to be 96 £0.4. We're gonna add that component in plus 96 0.4 J. Now for the we don't know the angle that it forms with the positive Z axis. So we can we can use these two magnitudes and the total magnitude of fr to find what is he is. So remember when you're looking for magnitude, this is the type of expression you use, F R X squared, F r y squared plus F R Z squared. Right? And we know this value, this value in this value. So it should be fairly easy to find F R Z squared or F. Rz. So if you plug all of these numbers in, I'm gonna put that in a calculator really quickly. You should get a number around, depending on we around a number around 75 82 for Oh sorry, fr z squared two square both sides. Fr Z comes out to be 87 0.1. You can feel that end up here. So plus 87.1. Okay, Okay. Now I'm gonna make some room to remove this work. And our next step is to find what the X. Y and Z components of F two R. So we'll start with X. So zero plus X has to equal negative 75. Simple Enough. Right? So X is equal to negative 75. Let's do this. That's why now 80 plus Y has to equal 96.4. Also simple enough. Why must equal 16.4. Lastly for Z0 plus, Z Must Equal 87.1. So you know that Z is equal to 87 0.16 87.1. Okay. And now that we have all the X, Y and Z component, we can find the magnitude by screwing all of them some of those squares and taking the square root of that. Okay, I'm just typing this into a calculator and the final magnitude proud to be 116.1. So the magnitude of F two is equal to 116 .1 and he didn't hear his pounds to our next step is to find all of the components angles. So that's alpha, beta and gamma for F two. So to do that, we can use this little set of formulas and I'm gonna block us off So alpha, it's going to equal inverse co sign of. And just the right angle trick here, this is going to be Jason over their partners, so it's going to be the X component over All of F to the magnitude of F two. So x component here is negative 75, negative 75 Over an F two. We determine as 116.1. If you simplify this, alpha will come out to be 130 .2.2°. Next you'll be this process with beta. This is equal to co sign in Roscoe sign of 16.4, which is our white component over the total magnitude Together. now, Beta comes out to be 81.9° and get the point now but repeat this with gamma For the z component and that becomes 87.1 over 116.1 on the inside. And Gamma comes out to be yeah, 41.4°. So those are actually our final answers. So we know that F two has a magnitude of 100 £16.1 and these are all of the component angles.

Advance. This is the problem based on additional factors. Here it is given to forces having the magnitude 13 Newton and 17 Newton are acting and a tangle 45 with positive excesses on one country degree with positive X success. As soon in the figure we're toe find the resultant off Afghan, plus a magnitude as Bella's direction. So Afghan factor can be written in components. For Mitch, you have to resolve this factor into its components of everyone cause 45 kept plus F one signed 45 Jacob Substitute develop Everyone is 30 cost 45 years burn upon roto I kept plus 30 into Bon upon to Jacob. So it is to be 15 road to I Care plus 15 roots. Jacob Newton. Similarly, I have to force to be dissolved into its company. Uh, it will be seven minus 70. Sign up 30 icap Well, so it is to be minus 35 Cap plus 35 a road trip. Jacob Newton so rejected. Forced off a one plus a new Cabinet. Allies 15 route toe I Cab has 15 route to Jacob plus minus 35. I kept less. 35. Route three J cap so it can be written as 15 route to minus 35 camp because 15 route to plus 35 four or three. Jacob. So you will get minus 30.79 I kept, plus 81.76 Jacob Newton. Now we have toe fire it the magnitude and direction off it magnitude off. It would be rude. Off minus 13 179 Holy Squared it was 81.764 is 12 on solving it. It's a magnitude ability 44.55 noted on the direction had probably 10 in worse off by component upon. So it is around. It was 60.2 kids protective X axis. Yeah, that's all. Thanks for

So we want to find the magnitude and direction of the resultant wind. Two forces air acting on an object. One of our forces is 30. Newton's forming an angle of 45 degrees with the X axis. The other force is 70. Newton's forming an angle of 120 degrees with the X axis. So what we're gonna do is use trigonometry to help us find the components of each factor. And then we can easily do vector addition to get the components of our resultant vector. So to start the components of our first vector F one first, we want to remind ourselves that the horizontal component is going to be our Tshosane data. Where are is the magnitude of our vector and why is r sine data? So our first vector F one is going to have components of 30 consigned 45 degrees and 30 time sign 45 degrees. Simplifying that cosign 45 is one over square root too. So we have 30 over square to, and same thing with signed 40 fives else's one over square it too. So our components oh, are identical. So dirty over to 30 over around two. Our second vector has components 70 co zone 1 20 and 70 Sign 1 20 So coastline of 120 degrees is negative. Half, I said we had 70 times negative half and then sign of 120 degrees is square in 3/2. So let's simplify that to get negative. 35 and 35. Grab three. Those are components of F. Teoh, our second director over here. So now we can just add those components together and the corresponding opponents. So 30 over rad too. Plus negative 35 or minus 35. That's the horizontal component of our results, Inspector. And the vertical component is 30 over rad too, plus 35 grabbed three. If we get the decimal values using our calculator, that would be negative. 13 point 787 and 81 0.83 fire. You could see that a result in vector would be in the second quadrant, Probably something like that. So now we need to find the magnitude of our results in factor. So we need to take the square root of the sons of the squares of the components. So in our calculator, I'm going to do. Negative. 13.78 seven squared plus 81 point feet +35 squared. And that's going to give us 82.9 80. So that's the magnitude of our resulted director of one plus two. Now we need to figure out the direction. What is this angle measure? From the X axis to the resultant, we can use trigonometry to help us again. We can use sign in verse, co sign inversion tangent. Inverse. It doesn't really matter. I'm gonna use tangent. Inverse. We know that Tangin inverse of the vertical component over the horizontal component is going to give us our angle measure. So we're gonna do tan in verse, uh, 81.835 over negative 13.787 And that's going to give us negative et point for 37 breeds. Make sure you're in degree load on your calculator. Unless the question is specifically asking you for radiance. Now, the negative 80.437 degrees is not in Quadrant two. That's in quadrant four. So we need to think about this. We need quadrant to angle measure so we can take the absolute value of negative. 80.437 And that gives us our reference angle. So this angle right here is negative. 80. Excuse me. 80.437 So, what we're going to do to get the angle measure that we want use? Subtract 80.437 from 180 and that will give us 99 0.563 degrees. That's the direction. So are resultant. So remember, we have two parts to answer the direction and the magnitude of the result.


Similar Solved Questions

5 answers
Assume (X,Y) have pmnf22 +V f(,y) = T =1,2,3.V = 0,1_ 31Find the pinf ol X Find P(X2 > 2(Y + 1)).
Assume (X,Y) have pmnf 22 +V f(,y) = T =1,2,3.V = 0,1_ 31 Find the pinf ol X Find P(X2 > 2(Y + 1))....
5 answers
Indicate the relationship between molecules A and D (diastereomers, enantiomers_ epimers or anomers):00 +
Indicate the relationship between molecules A and D (diastereomers, enantiomers_ epimers or anomers): 00 +...
2 answers
In each case; show that the given g(x) has a fixed point at the given and use (4.2.2) to show that fixed point iteration can converge to it
In each case; show that the given g(x) has a fixed point at the given and use (4.2.2) to show that fixed point iteration can converge to it...
5 answers
In the diagram below AB is the tangent of the circle, FG is the diameter and 0 is the center of the circle. Find the size of the angles (state geometrical reason in each case a) ZBFG or Zy (2 marks)b) LEOF(2 marks)c) LFEG(2 marks)d) ZEGF(2 marks)
In the diagram below AB is the tangent of the circle, FG is the diameter and 0 is the center of the circle. Find the size of the angles (state geometrical reason in each case a) ZBFG or Zy (2 marks) b) LEOF (2 marks) c) LFEG (2 marks) d) ZEGF (2 marks)...
5 answers
Let A and B be the two events of 3 sample $ such that RAUB)-0.85,PAnb) = 0.35.P(BnA)-= 0.30 Find PAIB) J
Let A and B be the two events of 3 sample $ such that RAUB)-0.85,PAnb) = 0.35.P(BnA)-= 0.30 Find PAIB) J...
1 answers
A $1.0 \mathrm{cm}^{3}$ air bubble is released from the sandy bottom of a warm, shallow sea, where the gauge pressure is 1.5 atm. The bubble rises slowly enough that the air inside remains at the same constant temperature as the water. What is the volume of the bubble as it reaches the surface? b. As the bubble rises, is heat energy transferred from the water to the bubble or from the bubble to the water? Explain.
A $1.0 \mathrm{cm}^{3}$ air bubble is released from the sandy bottom of a warm, shallow sea, where the gauge pressure is 1.5 atm. The bubble rises slowly enough that the air inside remains at the same constant temperature as the water. What is the volume of the bubble as it reaches the surface? b. A...
5 answers
QUESTION 32Consider the following roaction:2 CzH4 (g)Oz (g)COz (g)H2O (g)How many moles of COz cun be producod by the roaction ol 0.480 molos of = CzH4 and 08 molas ot 02? A 0.480 roles 8.0.960 moles C.0.240 molas D: 0.884 moles E0.720 moles
QUESTION 32 Consider the following roaction: 2 CzH4 (g) Oz (g) COz (g) H2O (g) How many moles of COz cun be producod by the roaction ol 0.480 molos of = CzH4 and 08 molas ot 02? A 0.480 roles 8.0.960 moles C.0.240 molas D: 0.884 moles E0.720 moles...
1 answers
Factor the given expressions completely. Each is from the technical area indicated. $a^{4}+8 a^{2} \pi^{2} f^{2}+16 \pi^{4} f^{4} \quad$ (periodic motion: energy)
Factor the given expressions completely. Each is from the technical area indicated. $a^{4}+8 a^{2} \pi^{2} f^{2}+16 \pi^{4} f^{4} \quad$ (periodic motion: energy)...
1 answers
One of $\sin \theta, \cos \theta,$ and $\tan \theta$ is given. Find the other two if $\theta$ lies in the specified interval. $$\begin{aligned}&\tan \theta=2\\&\theta \text { in }\left[0, \frac{\pi}{2}\right]\end{aligned}$$
One of $\sin \theta, \cos \theta,$ and $\tan \theta$ is given. Find the other two if $\theta$ lies in the specified interval. $$\begin{aligned}&\tan \theta=2\\&\theta \text { in }\left[0, \frac{\pi}{2}\right]\end{aligned}$$...
5 answers
Cool drivecsee his girlfriend who attends another collegeThe 160. km trip takes km/hWhat was the average speed for the trip?b) The return trip over the same route takes 3.0 because of heavy traffic What is the average Epced for the return trip? km/h(c) What is the average speed far the entire trip? km/h
Cool drivec see his girlfriend who attends another college The 160. km trip takes km/h What was the average speed for the trip? b) The return trip over the same route takes 3.0 because of heavy traffic What is the average Epced for the return trip? km/h (c) What is the average speed far the entire t...
5 answers
In Exercises 75–78, determine whether each statement makes sense or does not make sense, and explain your reasoning.The weightlifter does more work in raising 300 kilograms above her head than Atlas, who is supporting the entire world.
In Exercises 75–78, determine whether each statement makes sense or does not make sense, and explain your reasoning. The weightlifter does more work in raising 300 kilograms above her head than Atlas, who is supporting the entire world....
5 answers
In the diagram below, the electric field at point A is &_ What is the electric field at point B in terms of 8?A. 168B. 48C.28D. 8/2E. 8/4F. 8/16
In the diagram below, the electric field at point A is &_ What is the electric field at point B in terms of 8? A. 168 B. 48 C.28 D. 8/2 E. 8/4 F. 8/16...
4 answers
You are given thatis in the nullspace of; What is a?Answer:
You are given that is in the nullspace of ; What is a? Answer:...
5 answers
Consider this reaction: H2lg) 1zlg) ` ~> 2Hlig) It is found that at 625 K the equilibrium partial pressures for the reaction above are Ph2 0.132 atm; Pi2 0.295 atm and PHI = 1.61atm: Use this information to calculate AGo at that temperaturein kJImolQuestion 185 ptradioisotope decays into bismuth-213 and an alpha particle. What was the radioisotope?
Consider this reaction: H2lg) 1zlg) ` ~> 2Hlig) It is found that at 625 K the equilibrium partial pressures for the reaction above are Ph2 0.132 atm; Pi2 0.295 atm and PHI = 1.61atm: Use this information to calculate AGo at that temperaturein kJImol Question 18 5 pt radioisotope decays into bismu...

-- 0.018650--