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Question

Hame: Areth FSi Oiil V BUvC 0( Jnl41- Tre Idllitirg Lula raFrezertthe 862 (In "eetsk awnc Intamtet & 93%Con Jcncu Mlereaunol Ua Popuaron ilinuar | Doyinon al nr 030 (77 wrkelat Ahobb e; ANI GAlCick Ir Lun "001icil67neJuroutotHnnt credl cukca balw and Oli Lu Aal ko Gont Aaltid i0 Ilti7 ceema Rlc"eCuninlecbceGchahicy !l Uapcf_lajan 'nice" Ion / eetetnf6orn, 0578 0( T9m #inave to EetiJa slled dexoton Detabct ~geree"d 4u7diD1 Sert LfC canldenie Ilne popudlimt Alnosu

hame: Areth FSi Oiil V BUvC 0( Jnl41- Tre Idllitirg Lula raFrezertthe 862 (In "eetsk awnc Intamtet & 93%Con Jcncu Mlereaunol Ua Popuaron ilinuar | Doyinon al nr 030 (77 wrkelat Ahobb e; ANI GAl Cick Ir Lun "0 01icil 67neJuroutot Hnnt credl cukca balw and Oli Lu Aal ko Gont Aaltid i0 Ilti7 ceema Rlc"e Cuninle cbce Gchahicy !l Ua pcf_lajan 'nice" Ion / eetetnf 6orn, 0578 0( T9m #inave to EetiJa slled dexoton Detabct ~geree"d 4u7diD1 Sert LfC canldenie Ilne popudlimt Alnosu (ntun



Answers

The sccond ionizarion cncrgics of the $\mathrm{C}, \mathrm{N}, \mathrm{O}$ and $\mathrm{F}$ aroms are such rhar (a) $\mathrm{C}>>\mathrm{N}>\mathrm{F}>\mathrm{C}$ (b) $\mathrm{F}>\mathrm{O}>\mathrm{N}>\mathrm{C}$ (c) $C>\mathrm{O}>\mathrm{N}>\mathrm{T}$ (d) $\mathrm{O}>\mathrm{F}>\mathrm{N}>\mathrm{C}$

In this problem four X is very greater than our the value of B X is approximately equal to do not ideas. Ari Squire by to execute so I'll bring it further. I can write the value of ideas approximately equal to it will be X xq by you, not Ari square which is required to to multiplication three multiplication 10 to the power minus pi p. Multiplication tend to depart -1 m whole cube by 1.26. multiplication, 10 to the power -6 Multiplication, tend to the par -2 m. Hold to the Power Pole, which is approximately 0.5. Kay at the answer.

Chinese solution when directed with stool and avoided give some right sector own additional access this compound. So could you inform general which hard place here's the correct terms.

In this problem, I can write DDX in it see http CH two C 00 H. This compound in pageants of Cl two A red P. That to be dad reaction. It will give the compound edge, see http C h C L C. O AT and this compound in perchance of alcoholic kO edge. The hydro chlorination happened here and the compound formed the CH two double 1 C h c o egg. Therefore, according to the option of indeed correct option, the is correct answer. I hope you understand the solution.

In this problem, the only incorrect statement, the only incorrect statement about any two as 2 or three 5-2 age it cannot used to remove is in of extents of I too, as it can be used as to remove extensive I. Too. But here in this problem, it is given that it cannot be used to remove extensive I. Too, so it is incorrect statement. While all the other statement given in B c. D. Option are correct in this problem. Therefore, BCB are correct and said.


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