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Divide using synthetic division.(6x5 4x3 2x2 5x+4)| X 2...

Question

Divide using synthetic division.(6x5 4x3 2x2 5x+4)| X 2

Divide using synthetic division. (6x5 4x3 2x2 5x+4)| X 2



Answers

Divide using synthetic division. $$\left(2 x^{3}-8 x^{2}+3 x-9\right) \div(x-4)$$

We'll divide using synthetic divisions and negative two goes into the box. The opposite sign of our ah factor. And then we had coefficients of one x to the third positive two X squared Negative three x and negative. Four. Give yourself some space and spot for the remainder and begin the process by dropping down the one. And then we multiply to get negative, too. Add to get zero multiplied to get zero, I had to get negative. Three. Multiply to get positive. Six. Add to get positive two and then interpret. We've got a remainder. Our constant Rx Terminar X wears the suits like X squared plus zero accent. You don't need to write minus three with remainder of two over what we were dividing by exposed to.

We want to divide negative three x to the fourth by X minus two. Using synthetic division If we're using synthetic division when we're divided by X minus K, this tells us that came was equal to here. So we'll use to as our value outside of the structure and then inside are just the coefficients of what we're dividing from, which would be negative. Three x to the fourth. And even though that's the only term we still need a zero execute zero X squared zero X plus zero. We do need to use every coefficient. I'd like to leave a spot for what our remainder will be, and then we begin the process by dropping down the first term negative. Three. Multiply to get negative. Six. Add to get negative. Six multiplied to get negative. 12. Add to get negative. 12. Multiply to get negative 24 at to get negative. 24. Multiply to get negative. 48. Add to get negative. 48. Interpret Remainder of negative 48 are constant linear X and X word term. So negative. Three. Excuse me, Cube term Negative three X cubed minus six X squared minus 12 x minus 24 Minus the remainder of 48 over X minus two. What we're dividing by. That's our question

So when this question was asked to divide using synthetic divisions. So we're just gonna write the coefficients of our first part. So we have X cubed minus four X squared plus six packs minds for So are coefficients are gonna be one negative for six and negative four. And then we're dividing this by we're gonna have its two year goes to minus two is your X minus two. So bring on this one. This becomes too, then this right here, made of two times two is native four. This is for them to end up with zero. Yes, this does work out. It's a clean division. So we actually now. Well, right. Right. From the answers, we have X squared minus two ax plus two as our solution to this question.

And we want to divide negative three x to the fourth by X plus two. And in order to do this, we are going to use synthetic division. Since we're dividing by something like X minus K, okay, would be negative to here so that we would be having X minus negative. Two is X plus two. So it with synthetic division we have a structure in that cave. Value is outside and inside are the coefficients. We have negative three x to the fore, but then we need every coefficient down to zero, uh, degree zero, which is a constant, and there aren't any. So it's negative. Three x 40 X cube zero X squared zero X plus zero like to leave a spot as a reminder that that what that last value is is the remainder. The process begins by dropping down the first term negative three. Then we multiply to get six. Add to get six. Multiply to get negative. 12. Add to get negative. 12. Multiply to get 24. Add to get 24. Multiply to get negative 48. Add to get negative 48 and then interpret remainder constant X X squared X Cube. So negative three x cubed plus six X squared, minus 12 X plus 24 minus remainder of 48 or what we're dividing by X Plus two is our question to.


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