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Online Lab 3 chem IC0 Specific heat (Protected View) Word {Unlicensed Product)Review]VietHelpTell me Khat You wantto dong:5 Unlessyou nced to cdit is safer to stay ...

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Online Lab 3 chem IC0 Specific heat (Protected View) Word {Unlicensed Product)Review]VietHelpTell me Khat You wantto dong:5 Unlessyou nced to cdit is safer to stay in Protected Viem Jct is inactive. To use for free sign in and use the Web version.Enable EditingActivateUse free at Office.€Dath SbertInttruclor Slgaatune;Feenet lon GoceTnal | 25.$ 2 53 leiJTnl ?Meeuz mcual ubjectAMis o4c Eno EteetecuniMuso4 24" with Haidt~Muxs o[ 4k Ketrt in t6c 02Tann rlufc & Wict [Ihc Fene24 4656TOOttc

Online Lab 3 chem IC0 Specific heat (Protected View) Word {Unlicensed Product) Review] Viet Help Tell me Khat You wantto do ng: 5 Unlessyou nced to cdit is safer to stay in Protected Viem Jct is inactive. To use for free sign in and use the Web version. Enable Editing Activate Use free at Office.€ Dath Sbert Inttruclor Slgaatune; Feenet lon Goce Tnal | 25.$ 2 53 leiJ Tnl ? Meeuz mcual ubject AMis o4c Eno Eteetecuni Muso4 24" with Haidt ~Muxs o[ 4k Ketrt in t6c 02 Tann rlufc & Wict [Ihc Fene 24 465 6TOOttc Gknien elnncnn-utt cehnenaen Fannacfmneemaurg 4 Eaesta Flealcrcde MlluktLNat IueHenlah Lt [ Spccific hczt of Mc.l (L4 Specilic E hclm II | A a HaL eu Lt epe 0| nuelal ( Table I1 EArdb' CcC 6Gnmr Ce (metal}



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A recent research report describes the photolytic removal of a protecting group as a potential means of drug delivery for drugs possessing a suitable carboxylic acid functionality: (FIGURES CAN'T COPY) (a) What does the term 'prodrug' mean? (b) Draw the structure of the prodrug from which ibuprofen will be released upon irradiation, and name the functional group that is cleaved upon drug release. (c) The reaction shown above can be monitored by following the appearance of an absorption at $300 \mathrm{nm}$ arising from compound A. In what part of the electronic spectrum does the $300 \mathrm{nm}$ absorption lie? [Data: C. P. Mccoy et al. (2007) $J .$ Am. Chem. Soc., vol. $129, \text { p. } 9572 .]$

So the graph has us showing that the graph of one over the concentration of C two F four versus time is linear. And so there should ring a bell that when this is the case, the reaction is second order with respect to this reactive So second order with respect to see, to have four is this information we need to solve the rate lock. Since we know it's second order, the rate law is going to be great equal to first, a constant K times the concentration of C two at four square to the second power because its second order now to figure out the rate constant and all the other information fast. Or we're going to have to use the integrated rate long 1st 2nd reaction that is one over, in this case, the conservation C to F four. Whatever. The reaction is equal to Katie one over the initial concentration of seats for And so I'm just gonna plug in something information so we can find the great loss. So our natural concentrations 0.1 and I'll just use the demonstration at the next time. Slots of those 0.8 and the time to get there is 56 seconds. And so when you do all that, you'll find that K is equal to 0.446 And remember, watched units. It's the second order. It's gonna be leaders her moles per second Next. Uh, if we want to figure out what, uh, the conservation of us 600 seconds, we're going to again use the integrated rate law. So I was copied this from above, and this time we're gonna we have K or look, and we have a news time. 600 seconds. And now we can solve. For we're looking for is this concentration at the other time in so now, plugging in que is still 0.446 Our time that we're looking for is 600 seconds or initial concentration is still quite one so we can solve for concentration of seats who have four. And that is equal to, um, 0.271 Moller. And that makes sense. If you just look at the trend on the graph, the last question requires just a little bit of thinking. But then at the end, it's really just the same problem for you to hear. So we're asked for the reaction of the 90% complete. Well, if we started at 0.1 more, what would be 90% of this complete? So you take 90% off 0.1. That's 0.9 So we're looking for one. Is it become 10.1 minus 0.9 Moeller, just 0.1 So, in other words, this is our initial concentration right here. And we're looking for the time that it takes for that to be our final concentration. So I'll just plug it directly. We have one over the final concentration that were looking for equals. K t k. Two years we're looking for K. Is we already know that plus one over the initial concentration. My And if I plug in Okay, I confined. What's he is? And the time is equal to 2017 wait nine sex

So we are already provided by the reaction. But let me write it first platinum and it's three to see him, too. Nice water. It's pretty. NH 32 It's too c l positive plus seal Negative. So at temperature, constant K 25 degrees equals R. Then at 15 degrees, it will be 15 are so again, just substituting in the values we have. A natural law came 50 divided by G 25 equals natural or 15 equals he raise to power a divided by our divided by one by who's 73. Waas 25 minus one, divided by 273 plus 50 again continuing natural lock 15 equals e eight 25. Divided by are multiplied with to 98 screen 23 for the solving this for the value off a eight equals 298 multiplied 3 to 3. Okay, are natural. 15 divided by 25. It gives 86 point six eight killer dudes for this is the amount off activation energy required

Question here. First of all states a situation where we have at the lead in Glassell, which is a major component of antifreeze. So first of all, it basically asked what type of enzymes catalyze is the reactions from Oxo Effin OIC acid, oxalic acid. So this is what we're going to be known as a occid. Oh, reductase reaction is because we're either oxidation being reducing the particular reaction for be here, us that the treatment for the ingestion of ethylene glassell is an intravenous solution of ethanol. How might this prevent toxic levels of oxalic acid in the body? This is because for this particular case, what group you're being you're basically removing is the ethanol group from this particular structure. So in order to prevent that from basically turning to something toxic, you basically add ethanol in order to counter act such reaction

For the reaction to be a second order graph off one upon C four h. I think versus time should be straight. Let's see the craft. Here is the one upon C four age six versus time We have time is 200 seconds. 200 400 600 800 1000 and 1200. Then we have seen 75 later off Later for most 7500 1 25 150 Day 1 75 and 200. The graph for this is then at 600 somewhere with 0.1 25 to one for stay at 800 is 1 50. Then it drive hundreds from 70 five. Yeah, this line should be a trade line since they graft Mr Graph for fun upon, See for age six versus time. He's a straight line. Is this straight line on a stick? Harder? Oh, reaction. His second order reaction for that? No. For let's get glue defense Trade constant for a second order reaction rate. Constant is one upon Heidi minus one upon heart. Sarah, anything will do. Yeah. Be for slow. Physical too. Yeah. Therefore is he called when? 45 minus 100 change off concentration upon change of time. The book case he could toe rate constant is their 0.6 liters caramel seconds.


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