5

'Ilews AjaneIaJ SI aseajjap a8je| AJaN1e/a4 3q ue) paseaia: ssew a41 31l4m e Juunp Moy uleidx3 '8 ABjaua 341 Ju313 uoisSI}...

Question

'Ilews AjaneIaJ SI aseajjap a8je| AJaN1e/a4 3q ue) paseaia: ssew a41 31l4m e Juunp Moy uleidx3 '8 ABjaua 341 Ju313 uoisSI}

'Ilews AjaneIaJ SI aseajjap a8je| AJaN1e/a4 3q ue) paseaia: ssew a41 31l4m e Juunp Moy uleidx3 '8 ABjaua 341 Ju313 uoisSI}



Answers

I Icre, ycllow procipirare (S) is of (a) $\mathrm{PbCrO}_{4}$ (b) $\mathrm{PbCO}_{3}$ (c) $\mathrm{PbCl}_{2}$ (d) $\mathrm{Fc}(\mathrm{OII})_{3}$

In this problem I can write the reaction and CST CH two managed to in perchance of action or two 0-5° integrate will give this compound CS three CH 20 H. And this component to denso. PBL three will give CST CH two beyond and this compound in pageants of GCN we'll give CST CH two M. C. And this component presence of AL I am at full well finally give CST CH two NHCS three. This is compounded by this is component so according to the option, option C it correct here, option siege, correct answer.

In this problem, I can write the reaction age. Just look at it carefully Jordan also. Food ECU was Yes. Any to co three ACT was will give the product age I need to S. 04 ac was plus Jordan CP three solid and I can also write DDX an edge. Just look at it carefully. Yeah, I didn't. Also for it was blessing do any H C 03 Oculus will give will give any two S 04 Backwash plus Jordan CO three solid plus slash two plus CO two. So according to the option in this problem, option beach, correct option B. Each got it.

Hello and welcome to this video solution of numerous. Here we are given a link comprehension. So here in statement one were given that and iron or a on roasting with sodium carbonate and lying in the presence of air gives to compound PNC. And you're from option the second part the solution be in concentrated. It's alan reaction with production furrows and it gives a blue color on precipitated of compound their cost solution of C. On treatment with considerate statistical gives a yellow colored compound E. And the compound even treat it with a seal gives an orange red compound F. Which is used as an ox raise anything. So you have to make certain predictions to come into the solution. So let me show you how it's made. So first of all we take for if he oh she had to poetry thus eight and a two freedom global neck And with air that is given seven or 2 good line gives you to a free two or three that's eight the name so Seattle four. That's it. It's a frustration. Next we have if we two or three reacting with concentrate sales that is given gives you who official three Last three H 2. Right now this official tree reacts with who before if he 10 6 that is protection fellow sign a great this gives you the blue solution pushing blue solution of if the four if he CN six whole trade plus 12 cases. Mm Next From three we have two any he wanted to see our well for That's 8/10 of food gives you we need to the odd 47 is the yellow color solution. Greatness in A. Two so four. That's it too. No you have in A to see our two or seven. Okay, last case here is the orange color substance of people pr two or seven that's 2010. So this is the so let us state what is A what is B. The first we have me is If you see a 23, this is a Next we have every two or 3 SCB or Yes. So this suits also be ready And in in 204 this is C. Right BNC. That is mentioned. Yes. Now this pushing blue books. Mhm. Yeah. Yeah. Whoa it is. Mhm. Okay. To see again this election with the this one your local er this is E and we have orange. What are some common? It does if Yeah. Right. I hope this is clear to you and have a very good rest of the day. Thank you.

Were given a special vector function and were asked to find the derivative of the vector function. The unit Tangent Vector AT T equals one second derivative of the vector function and the cross product of the derivative of the vector function with the second derivative, the vector function. Special function is our of t equals t t squared two cubed recognize from the book. This is the twisted cubic. We have the components functions of our r t T squared and cubed, which are all differential. So our is differential and our prime of tea is by definition the vector who's functions whose component functions are the derivatives of the component functions of our. So we have one to t three t squared and so we have that are prime of one is equal to one, 23 and that the norm of our prime of one is equal to the square root of one plus four plus knowing which is the square root of 14. And so we have that the unit tangent vector t of one is equal to by definition are prime of one over the norm of our prime. Avorn, we just exist. Since the normal prime of oranges. Non zero. This is the vector 123 divided by 14. Which can you refute me as one of the Route 14 two of every 14 three over route 14. This is the unit tension vector at one second derivative of our well notice that the component functions part prime or 12 tea and 30 square in these rural differential. So we have that are prime is differential and that our prime of tea is by definition defector who's component functions are the derivatives of the component functions of our prime. So we have zero to and 60 and we have that our prime tea crossed with our double prime of tea is equal to this is the determinant of the matrix I j k First row, Second row is going to be our kind of tea, which is one to t three t squared. In the third row is article prime, a 50 which is zero to 16. And so expanding down the first column we get to tee times 60 is 12 t squared minus two times three t squared is minus 60 squared. So I simply get 60 squared. Why minus one time. 60 years. 60. Well, we're staying on the first column. So instead of doing that, this is minus J times 60 years 60 j minus que temps two, which is two k and then the last term drops out since coefficient zero and this is equal to six. T squared I minus 60 j plus tu que?


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