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For the reaction below, use the pxidation number method to balance the equation under acidic conditions. SHOWALLYOLRWORK Complete the statements at the end Fe2+ Mn...

Question

For the reaction below, use the pxidation number method to balance the equation under acidic conditions. SHOWALLYOLRWORK Complete the statements at the end Fe2+ Mn04" IFe3+ Mn + (acidic conditions)

For the reaction below, use the pxidation number method to balance the equation under acidic conditions. SHOWALLYOLRWORK Complete the statements at the end Fe2+ Mn04" IFe3+ Mn + (acidic conditions)



Answers

Use the oxidation-number method to balance the following net ionic redox equations.
$$
\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq})+\mathrm{I}^{-}(\mathrm{aq}) \rightarrow \mathrm{Cr}^{3+}(\mathrm{aq})+\mathrm{I}_{2}(\mathrm{s}) \quad \text {(in acid solution)}
$$

To Balance two Equations. Um Which proceeding in a cd kikuyus media. Let's start with the first equation where zinc RE Experience 93, the informs two plus and energies. So The oxidation number changes from 0 to plus two, and oxidation state of nitrogen changes from um plus five two blast. Um So therefore think is being oxidized and nitrogen is being reduced. So now let's write down half reactions in the first half reaction. Think metal just loses two electrons and forms I think two plus iron. And this reaction is already balanced. So now let's balance the second reaction, which is reduction of nitrate to N. O. G. S. Yeah, so here we have to balance oxygen because nitrogen is already balanced and we're going to do it by adding three molecules of water to the right side of the equation. So now oxygen is balanced and we just need to so in two molecules of water obviously, yeah, now oxygen is balanced. There are three oxygen atoms on each side and we just need to balance hydrogen. Do this, we'll just add four ish plus to the left side and to balance the charge, We have to all set three electrons. So my estrogen changes oxidation number four plus five to plus two. Therefore it's a three electron reaction overall, it's a six electron reaction. So therefore we have to multiply them by three And nitrogen by two. Yeah, so here we also add for molecules of water and we also need to add mhm eight protons to the left to the left side. So now let's check the material balance. Sold three things on its site to nitrogen. Uh six oxygen's and eight hydrogen is yep, everything seems to be balanced. Now let's move on to the next equation where Manganese two plus he is oxidized to permanganate by uh this moto three minus and iron, which is in turn is reduced to bismuth three plus. So let's write down the cuff reactions. So let's start with oxidation half reaction. Which is the formation of permanganate from mandan ease two plus science. So to balance oxygen, we have to add four molecules of water. It was the left side and now we just need to build us hydrogen. So we had eight H plus. This is the right side of the equation And it's a five electron reaction. So we need to five elections to the right side to balance the church. So now the charge on this side is two plus. Therefore, Reaction is balanced. Not. Let's move on to the oxidation reaction to the reduction reaction, which is the formation of the small three plus from this model three miles. Mhm. And then we have to balance oxygen first and now we need to balance hydrogen. There are six hydrogen atoms on the right side. Therefore we have to six H plus to the left side. And moreover, we need to balance the charge so we are going we need to add to elections to the right side to the left side of the equation. So therefore overall it's a an electron reaction. Therefore we have to multiply manganese components by two And the basement components by five. So now let's write down total equation in the ionic form. And then we'll um calculate proper amount of more water and hydrogen on each side. So two MN 2 plus React. We re actually is eight molecules of water. We have five. This model three miners, uh 30 proteins. Mhm. And it forms too. And my love for minus I and II ins 16 gratins, five be small, three plus irons and 15 water molecules. So now let's look at water and H plus on each side. So there are more H plus on the right side on the left side of the equation. But there is more water on the left side on the right side of the equation. So now we can simply mathematically subtract might water and the hydrogen from which side and the final equation we look like the following. Okay. Yeah. Mhm. Thank you. Yeah. Mhm. Yeah. Yes. Yeah. Mm hmm. Now let's check the material balance to manganese on each side. five be smooth finish side. 14 hydrogen is on its site and 15 oxygen's on its side. So this reaction is balanced as well as the first reaction. Thank you very much for visiting my solution. I hope I helped you by

And this problem, You're supposed to use the oxidation of her method to balance this Redox equation. So if you're gonna do that, you've got to be able to assign the oxidation numbers to the all the elements on the reactant and product side so that you can tell which things are undergoing oxidation reduction. So once you do that, you see that the chlorine goes from oxidation state of negative one to an oxidation state of positive one. I'm gonna write that down because we're gonna call that kind of 1/2 reaction. I see that nitrogen goes from a plus five oxidation state to a plus two oxidation state. So in order for chloride the chlorine to become plus one, it had to gain two electrons and in order for nitrogen go from plus five plus two, it had to gain three electrons. So I'm gonna balance those electrons because they can't gain or lose Maur. I've got a multiply the top one by three in the bottom one by two and I've got to go through and add the coefficients. Now, the coefficients that I'm adding in there are gonna end up in the equation and I've got to be careful to put the coefficients in that came with each of those compounds. So this chlorine here, that oxidation number goes up here or that coefficient. I'm sorry. Goes up there for the h n 03 That is this nitrogen. So the two goes in front for the h o C l. The oxygen. The coefficient here goes up to that reactant or sorry, that product on. And then the other nitrogen with an oxidation number of plus to that gets a coefficient of two. Now, you've got to be careful and examine the water. Sometimes he needs to be a coefficient there. Um, even though it may not look like it, um, there's definitely not gonna be one in this reaction, because all he had was changes in chlorine and nitrogen. Sometimes there's a change in oxidation state of oxygen or hydrogen in there, and you've got to be careful to pay attention to a water molecule. But not in this one

To balance to redox reaction shown in the screen, which take place in in ECO CCD conditions. So let's start with the first reaction oxidation of tin two plus between four plus by higher date and iron. So let's start with uh oxidation reaction first. So Tin two plus loses two electrons And becomes 10 4 plus. And this reaction doesn't need any additional balancing. So additionally, um how to date is reduced to idea. Mhm. Then we have to balance this reaction in the media. Okay, so first let's balance Aydin and Now we have to add three water molecules to the right side of the equation to balance, sorry, six water molecules to the right side of the equation to balance oxygen. So now there are six oxygen atoms on its side. So now we have to balance hydrogen and church. So on the right there are 12 hydrogen. Therefore we need to add 12 hydrogen. Okay, to the left side of the equation. Now let's calculate the total charge on the left, So its 12th -2. So it's 10 and On the right side and that charges zero. So therefore we have to have 10 electrons to the left side of the equation. So now it's balance and basically 10 electrons means that each idea and five plus gets five electrons and is reduced to eyes and zero. Which makes sense. So now we can balance oxidation reaction. We just simply to which we've already done. And now we can calculate the overall net reaction. So overall it's tera electron reaction. So therefore we have to multiply teen by five. Um 2nd reaction by one. Yeah, So now let's write down the total reaction. So 5:15 to plus. Okay reacts. We is too Mhm violate an ions 12 broughton's Uh huh. And it forms um five teen four plus One idea in and six water molecules. So let's check for the church balance is plus 20 on the right and on the left, head stem minus to plus 12, which makes 20. So there are 12 hydrogen is on the left, 12 hydrogen is on the right, 5 15 items on the left, five teen items on the right to I. D. In atoms on the right to I jin atoms on the left, so in six oxygen's on this side. So therefore it's balanced. Now let's move on to the next equation, which is the oxidation of arsenic oh 33 minus two, arsenic oh 43 minus. So this is oxidation because oxidation number of arsenic changes from last 32 plus five and it's oxidized by brahman which is reduced in turn. Yeah. Now let's balance that equation in the echoes a cd media. So first we'll start with oxidation reaction. So in the oxidation reaction mhm uh are saying oh 33 minus is oxidized to are saying oh 43 minus. So we have to balance oxygen first. So therefore we add one water molecule to the left side of the equation. So now we have four oxygen atoms on the each side. Now we need to balance hydrogen so we add to protons to the right side of the equation. So and now we need to balance charge. The net charge on the left side of the equation is negative three on the right side, it's negative one. Therefore we have to add two elections. Which makes perfect sense because arsenic is oxidized from plus 32 plus life. So it's a two electron process. So in the second in the reduction reaction brahman, Mhm who is reduced to to brahman negative bromides by getting two electrons. So therefore overall it's a two different process. And we have to multiply each equation by one. So let's write down the overall reaction. It's our Singapore three. Three minus. Yeah. Glass one Water molecule plus for I mean, yeah, forming uh one arson 89 RC vehicle for three minus last two broad mites plus two products. So let's again calculate the charge on the right hand, left side of the equation. So on the raft it's three minus on the right. It's uh three minus as well because it's three, it's negative three plus negative two plus two. So it's negative three in total. To prominence on the left. Two province on the right. Uh two proteins on the left to proteins on the right, for oxygen on the left, for oxygen on the right and one arsenic on each side. So therefore this reaction is balanced. Thank you very much for watching this video. I hope I helped you

Yeah. All right. So, we want to balance these equations and acidic solution. Redox reactions, Right? So, first of all, we need to separate them into oxidation half and reduction have. So, how do we know which one is oxidize? Which one is reduced? Now, if we look at the oxidation states nitrogenous plus five here. But here it is minus three. This production. All right. And so zinc is zero here and plus two here. So, it's oxidation that increase increase in oxidation state due to loss of electrons. Right? So, so that's oxidation. So, let's separate into oxidation. Have in oxidation half. We have zinc Uh huh. To zinc. Two plus. Now, we need to balance the charges. We uh two electrons here to balance the positive and the reduction we have in three minus form image. For less. We need to balance the oxygen's. You have three oxygen's on the left. So we add three moles of H 20 here. All right. You know the hydrogen We now have uh six Here, 100 games on the right. So we add 10 had regained is here. Okay. And that makes the And the charges. They have 10 plus -1 And one here, it makes a difference of eight. All right. So, uh, we add eight electrons on the and this one. So we uh, electrons on this equation then uh, we need to add the two equations, but we need to have some number of electrons for each for both equations. So, we will multiply this equation by four. Now, when we do that, we have four most of zinc was In the three the last 10 most of President Irons. All right. So we have the electrons. We cancel out and then the form oh, okay. Zinc two plus less. An image four plus was the age to uh, right. So, that's a good question. No, I could have Crimea plus three. All right then. Uh, on the right hand side is plus six. So that's oxidation. And the other one's reduction business plus five here must plus three on the right hand side. All right. So the oxidation, the the oxidation half is from cream Young. I bless Yeah. To form CR 207 to make this, uh, fellas the Crimeans by Putin to here. And the oxygen you have seven there. So, uh seven most of water. And that makes the hydrogen is 14 On the left hand side. So we had 14 handing in areas on the right hand side. And that makes the charges Plus six on the left hand side. Well, my list to here 14. and your friends of six, right? They're friends of sex. Like Positive sex. So we add six electrons here. Then the reduction we have this 93, 9 is to form the three plus. All right, so the oxygen's three on the left. So we had three moles of H20. Right then dehydrate use we uh six year because we have six high regions on the right Then they charges plastics for the Hydrogen 9 -1. Last three here. So, it makes a difference of two electrons. So two plus two. So, you have had two electrons here. Okay. To add the two equations, we need to have the cinema of most of electrons for each for both equations. So we will multiply this by three. Right, So now we have to sleep uh a big plus less. Three be uh realign this. Let's not dehydrated the hydrogen ions. Uh You have a difference of fourth in the Mhm. Yeah. 14 Hydrogen Miles from There. They have to off. Uh we have 18 For this one. So, the difference of four having an IAS perform c uh two also join us. Three Last two years of water. Yeah, You have seven. Most of water for the first question. They have 12 here. Mm. We have nine here on the second equation. So, difference of two. Then a 3rd 1 that when aidan is zero here, but it's the last five years. So that's oxidation Lorraine. Okay, so new york's nation have it will be uh two to form. I owe the minus You have three oxygen's on the right? So you add Yeah, three moles of H 20. I had read in a six year to last six months of hydrogen. Yes. Six months of six months of paid again. Ass yeah. All right. Six. All right. So then the electrons, the charges charges too. Mm So, we need to balance The idea is first. So, we will delete all this best. All right. So, the higher diet, we have two of the iodine. So we have to put two here to balance the A dies. And that makes the oxygen's six on the right hand side. So at six months of 82. So now we have six uh 12 hydrogen. So we have to add 12 hydrogen ions here. All right. So if we check the charges, We have my -2 and 12 plus two years. So we have 10, 10 plus two plus 10 different. So, we had 10 electrons on this than the reduction reduction. We have oh CL -2 Form. See uh minus. So we have to add one more of water here because we have one oxygen on the left. Then the hydrogen is we add to two moles of hydrogen ions, Arrange surplus two electrons here And to balance the electrons, we have too much blood. This by five So that the number of electrons will be same. Both questions. So when we do that we can add it to questions. Then we'll have I to plus And then the H 20. You have six there. five on the right. So you have one on the left. Like O c minus form to I of the my name is That's right. And this then they hire ages. They have to On the right because we have 12 For the fresh question. You have 10 under second question then the last equation we have nine gallons is plus two on the left, But on the right is Plus seven. So that's oxidation. All right. So mhm. The forum. Yeah, For minus the oxygen's. We have to add four most of age to here. And that makes the hydrogen AIDS. So if that makes the hiring eight we have at eight have again irons here. And the difference in charges we have plus two on the manganese and the labs and Last eight minutes around here. So the difference of plus five. So you have to add five most of electrons here. Yeah. Than a reduction. Have we have be I with the minus form The I three plus. Mhm. Alright. So to balance the oxygen is we have three moles of H 20. Yeah. And when we do that, we have six hydrogen is on the right to plus six. Had again I asked on the left and the difference in charges B Plus two on the left and two elections. All right. So, yeah. Okay, so to have this same number of Electrons, we multiply this by two and multiply this by five. Okay. And when we add those three questions, you will have two And then two plus last five be I the minus bless reports and h blows. Mhm. All right. Their form two mm mm oh four minus last five. The I three plus Class seven. Age too. Right? Yeah. So we separate them into the organization and reduction House. All right, balance them separately. And at I have three questions.


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